Question

我有2个按钮和2个独立的活动，我想要控制流程如下：

Activityone
buttonOne {➡{1}}
ActivityTwo {➡{1}}

main.xml中：

buttonTwo

MainActivity.java

ActivityThree

的manifest.xml

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_height="match_parent"
android:layout_width="match_parent"
android:orientation="horizontal"
android:gravity="right">

<LinearLayout
    android:layout_height="match_parent"
    android:layout_width="match_parent"
    android:orientation="vertical"
    android:layout_weight="1.0">

    <LinearLayout
        android:layout_height="50dp"
        android:layout_width="match_parent"
        android:orientation="horizontal">

        <Button
            android:layout_height="match_parent"
            android:layout_width="50dp"
            android:background="@drawable/rozmare"/>

        <TextView
            android:layout_height="match_parent"
            android:text="کار های روزمره"
            android:textAppearance="?android:attr/textAppearanceMedium"
            android:layout_width="match_parent"
            android:gravity="center"
            android:textSize="25sp"/>

    </LinearLayout>

    <EditText
        android:textSize="20.0sp"
        android:gravity="top|right"
        android:id="@+id/editText1"
        android:padding="5.0dip"
        android:scrollbars="vertical"
        android:fadingEdge="vertical"
        android:layout_width="match_parent"
        android:layout_height="fill_parent"
        android:text=""
        android:capitalize="sentences"
        android:layout_gravity="top|right"
        android:textColor="#000000"
        android:background="#FFFFFF"/>

</LinearLayout>

<LinearLayout
    android:layout_height="match_parent"
    android:layout_width="65dp"
    android:orientation="vertical"
    android:layout_margin="1dp">

    <ScrollView
        android:layout_height="match_parent"
        android:layout_width="match_parent">

        <LinearLayout
            android:layout_height="match_parent"
            android:layout_width="match_parent"
            android:orientation="vertical">

            <Button
                android:layout_height="65dp"
                android:layout_width="match_parent"
                android:id="@+id/notelist"
                android:background="@drawable/personal"
                android:layout_margin="1dp"/>

            <Button
                android:layout_height="65dp"
                android:layout_width="match_parent"
                android:background="@drawable/kasbokar"
                android:layout_margin="1dp"
                android:id="@+id/notelist1"/>

        </LinearLayout>

    </ScrollView>

</LinearLayout>

</LinearLayout>

但是两个按钮都在执行相同的操作，两个按钮都将转到import android.app.Activity; import android.content.Context; import android.content.Intent; import android.os.Bundle; import android.widget.Button; import android.view.View; import android.view.View.OnClickListener; import android.view.Menu; import android.widget.TextView; import android.widget.EditText; import java.io.FileInputStream; import java.io.FileOutputStream; public class MainActivity extends Activity { Button buttonOne; Button buttonTwo; EditText editText1; String fileName; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); addListenerOnButton(); getActionBar().hide(); getWindow().setSoftInputMode(3); editText1 = (EditText) findViewById(R.id.editText1); fileName = getResources().getString(R.string.file_name); try { FileInputStream fis = openFileInput(fileName); byte[] readBytes = new byte[fis.available()]; fis.read(readBytes); editText1.setText(new String(readBytes)); fis.close(); } catch (Exception e) { return; } } public void onPause() { super.onPause(); try { FileOutputStream fos = openFileOutput(fileName, 0); fos.write(editText1.getText().toString().getBytes()); fos.close(); } catch (Exception e) { return; } } public void addListenerOnButton() { final Context context = this; buttonOne = (Button) findViewById(R.id.notelist); buttonOne.setOnClickListener(new OnClickListener() { @Override public void onClick(View arg0) { Intent intent = new Intent(context, NoteList.class); startActivity(intent); buttonTwo = (Button) findViewById(R.id.notelist1); buttonTwo.setOnClickListener(new OnClickListener() { @Override public void onClick(View arg0) { Intent intent = new Intent(context, NoteList1.class); startActivity(intent); } }); } });} public void EXIT(View view) { finish(); }}，另一个问题是，如果我不接触<?xml version="1.0" encoding="utf-8"?> <manifest xmlns:android="http://schemas.android.com/apk/res/android" package="ir.whitegate.noteking" android:versionCode="1" android:versionName="1.0" > <uses-sdk android:minSdkVersion="8" android:targetSdkVersion="16" /> <application android:allowBackup="true" android:icon="@drawable/ic_launcher" android:label="@string/app_name" android:theme="@style/AppTheme" > <activity android:name=".MainActivity" android:label="@string/app_name" > <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> <activity android:name=".NoteList" android:label="@string/app_name" android:windowSoftInputMode="adjustUnspecified"/> <activity android:name=".NoteEdit" android:label="@string/app_name" android:windowSoftInputMode="adjustUnspecified"/> <activity android:name=".NoteList1" android:label="@string/app_name" android:windowSoftInputMode="adjustUnspecified"/> <activity android:name=".NoteEdit1" android:label="@string/app_name" android:windowSoftInputMode="adjustUnspecified"/> </application> activityTwo将不行。

Answer 1

您已在第一个按钮的侦听器中添加了第二个按钮的侦听器，因此

如果我不接触ButtonOne，ButtonTwo将无效。

第二个按钮的监听器只有在按下第一个按钮时才会初始化

但它们应该是分开的

public void addListenerOnButton() {
    final Context context = this;   
    buttonOne = (Button) findViewById(R.id.notelist);

    buttonOne.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View arg0) {   
           Intent intent = new Intent(context, NoteList.class);
           startActivity(intent);
            }
        });

    buttonTwo = (Button) findViewById(R.id.notelist1);

    buttonTwo.setOnClickListener(new OnClickListener() {    
        @Override
        public void onClick(View arg0) {   
            Intent intent = new Intent(context, NoteList1.class);
            startActivity(intent);    
            }    
        });    
}

他们两个都要活动两个

此行为与简单地使用相同的布局结构有关，因此请使用settext函数或在XML代码中进行更改。

Answer 2

您的问题的解决方案是在xml中定义onClick函数

<Button
android:text="Don't have an account? Join!"
android:onClick="toRegister"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
/>

然后在班级中定义你的功能

    public void toRegister(View view){

    Intent newIntent = new Intent(this, SignUpActivity.class);
    newIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
    LoginActivity.this.startActivity(newIntent);
}

Answer 3

您已在第一个侦听器中添加了第二个侦听器。

buttonOne.setOnClickListener（new OnClickListener（）{

@Override
public void onClick(View arg0) {

    Intent intent = new Intent(context, NoteList.class);
    startActivity(intent);


    buttonTwo = (Button) findViewById(R.id.notelist1);

    // >>>>>>>>>>>>>>>>>>>>>>> inside buttonOne
    buttonTwo.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View arg0) {

            Intent intent = new Intent(context, NoteList1.class);
            startActivity(intent);

        }

    });
    // >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>

}
}); //  >>>>>>>>>> button one ends here

声明onClickListener的另一种简单方法是将其声明为对象字段，如下所示

  private View.OnClickListener clickListener = new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            switch (v.getId()){
                case R.id.notelist1: {
                    // go to notelist 1
                    break;
                }

                case R.id.notelist: {
                    // go to notelist 
                    break;
                }
            }
        }
    };

并在下面的按钮上设置监听器

buttonOne.setOnClickListener(clickListener);
buttonTwo.setOnClickListener(clickListener);

第二个按钮上的OnClickListener既未正确初始化也未按预期工作

3 个答案: