您好我在写入数据库之前尝试使用数据验证表单。但我不确定为什么数据验证不起作用。以下是我的代码
filename:bookoffer.php
$NameErr = $EmailErr = $DescriptionErr = "";
//$Name = $Email = $Description;
if (isset($_POST['Submit']))
{
$errors = array();
if (empty($_POST['Name']))
{
$NameErr = "**Name is required**";
}
else
{
$Name = ($_POST['Name']);
//check if name only contain letter and white space
if (!preg_match("/^[a-zA-Z ]*$/",$Name))
{
$NameErr = "**Only letters and white space allowed**";
}
}
if (empty($_POST['Email']))
{
$EmailErr = "**Email is required**";
}
else
{
$Email = ($_POST['Email']);;
//check if e-mail address is well-formed
if (!filter_var($Email, FILTER_VALIDATE_EMAIL))
{
$EmailErr = "**Invalid email format**";
}
}
if (empty($_POST['Description']))
{
$Description = "**Description is required**";
}
else
{
$Description = ($_POST['Description']);
}
}
//if(count($errors)==0)
include 'database_connect.php'; //make database connection
$Name = $_POST['Name'];
$Email = $_POST['Email'];
$Description = $_POST['Description'];
$sql = "INSERT INTO books_offer (Name, Email, Description) values ('$Name', '$Email', '$Description')";
$redirect = true;
header('Location: Thank_you.php');
mysqli_query($conn, $sql) or die (mysqli_error($conn));
mysqli_close($conn);
?>
这是html文件,它正在调用bookoffer.php
<!DOCTYPE HTML>
<html>
<head>
<style>
.error {color: #FF0000;}
</style>
</head>
<body>
<h2>Please Offer Your Book</h2>
<form id="bookoffer" method="post" action="bookoffer.php" >
<p><span class="error"> <font color="red">*required field.</font></span></p>
Name<font color="red">*</font> <input type="text" name="Name" >
<span class="error"> <?php echo $NameErr;?></span>
<br></br>
Email<font color="red">*</font> <input type="text" name="Email" >
<span class="error"> <?php echo $EmailErr;?></span>
<br></br>
Description<font color="red">*</font><textarea name ="Description" rows="5" cols="40" ></textarea>
<span class="error"> <?php echo $DescriptionErr;?></span>
<br></br>
<input type="submit" name="submit_form" value="Submit" />
</form>
</body>
</html>
答案 0 :(得分:0)
您没有填充$errors
数组,因此您注释掉的if语句将始终为true
。您将错误存储在单个变量中。一种选择是改变
$errors = array();
到
$errors = false;
然后,当您设置错误变量时,为每个变量添加一行以将$errors
设置为true
,例如,
if (empty($_POST['Name']))
{
$NameErr = "**Name is required**";
$errors = true; // this line added
}
您现在可以将注释掉的if语句更新为
if ($errors) {