Question

我正在使用基础标签，我想从datepicker字段按YEAR排序我的自定义帖子。每个标签是一年（2016年2015年等）。当用户单击选项卡并显示时，将显示具有该事件日期元字段（acf datepicker字段）的所有自定义帖子，并在该选项卡内容中进行监听。但现在使用我的代码，它列出了自己的选项卡中的每个帖子，这些帖子会导致同一年的多个标签（2015-2015-2015-2016-2016）而不是（2016-2015-2014-2013），其中包含的帖子位于标签内容。这个例子就是我想要实现的目标：exactly what i am after

我不知道我现在在哪里，但是我已经做了很多事，没有做任何事情。从来没有做过这样的事情所以我可能是我的leage，但我想知道如何做到这一点以及我需要在代码中进行更改以完成它。到目前为止，这是我的代码：

$currentTime = current_time('Ymd'); // getting current time                 
$format_in = 'd/m/Y'; // the format your value is saved in (set in the field options)
$format_out_fields = 'Y'; // the format you want to end up with
$date = DateTime::createFromFormat($format_in, get_field('event_date'));

$args = array(
    'post_type' => 'cpt',
    'posts_per_page' => -1,
    'orderby'   => 'meta_value',
    'meta_key'  => 'acf_field',
    'order'     => 'DEC',
);
$subsQuery = new WP_Query( $args );
?>
<?php if ( $subsQuery->have_posts() ) : ?>
<?php section_open(); ?>
<h2 class="type2"><?php _e('H1 tabs', 'theme'); ?></h2>
<?php innerSection_open(); ?>

<?php /////////  TABS TITLE / BUTTONS  ///////////// ?>
<ul class="tabs" data-tabs id="tabs">   
    <?php 
    $counter = 0; 
    while ( $subsQuery->have_posts() ) : $subsQuery->the_post();
    ++$counter;

    $format_in = 'd/m/Y'; // the format your value is saved in (set in the field options)
    $format_out = __('jS F Y', 'theme'); // the format you want to end up with
    $date = DateTime::createFromFormat($format_in, get_field('acf_field'));
    ?>


        <li class="tabs-title <?php if ( $counter == 1 ) { echo "is-active"; } ?>">
            <a href="#panel-<?php the_ID(); ?>" <?php if ( $counter == 1 ) { echo 'aria-selected="true"'; } ?>>
                <?php
                $format_in = 'd/m/Y'; // the format your value is saved in (set in the field options)
                $format_out_tabs = 'Y'; // the format you want to end up with
                $date = DateTime::createFromFormat($format_in, get_field('acf_field'));
                echo $date->format( $format_out_tabs );
                ?>
            </a>
        </li>

    <?php endwhile; ?>
</ul>
    <?php /////////  TABS CONTENT  ///////////// ?>
<div class="tabs-content" data-tabs-content="tabs"> 
    <?php 
    $counter = 0; 
    while ( $subsQuery->have_posts() ) : $subsQuery->the_post();
    ++$counter;
    ?>

        <?php 
        $format_in = 'd/m/Y'; // the format your value is saved in (set in the field options)
        $format_out = __('j.m.Y', 'theme'); // the format you want to end up with
        $format_out_year = __('Y', 'theme'); // the format you want to end up with
        $date = DateTime::createFromFormat($format_in, get_field('event_date'));
        $date_year = DateTime::createFromFormat($format_in, get_field('event_date'));
        ?>

        <div class="tabs-panel <?php if ( $counter == 1 ) { echo "is-active"; } ?>" id="panel-<?php the_ID(); ?>">

            <span><?php echo $date->format( $format_out ); ?>:</span><br/>
            <span class="bold">
            <?php if( get_field( 'acf_type' ) == "event") { ?>
            <?php _e('Event', 'theme'); ?>:
            <?php } ?>
            <?php
            $theTitle = get_the_title();
            echo $theTitle;
            ?>
            </span><br/>

                <?php if( get_field( 'link' )) { ?>
                <?php if (isexternal(get_field('link')) == true ) { ?>
                <a href="<?php the_field('event_link' ); ?>" target="_blank" style="text-decoration: underline;"><?php _e('Read more', 'theme'); ?>&nbsp;<i class="fa fa-external-link" aria-hidden="true"></i></a>
                <?php } ?>
            <?php } ?>


        </div>

    <?php endwhile; ?>
</div>

在acf datepicker字段的选项卡中按日期分组/列出/排序自定义帖子类型的帖子

0 个答案: