Question

我有一个列数组，我需要为每列的2行产品的SUM。例： 1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 我想要做的是col2和col3的以下内容：总数= 2 * 3 + 2 * 3 + 2 * 3 + 2 * 3 = 24 以下是此操作的代码： int product_col2Xcol3 = 0; int sum_totalcol2Xcol3 = 0; //计算col2和col3的SUM（Product） for（int row = 0; row＆lt; r; row ++） { for（int j = 0; j＆lt; r; j ++） { product_col2Xcol3 = matrix [j，col2] * matrix [j，col3]; sum_totalcol2Xcol3 = sum_totalcol2Xcol3 + product_col2Xcol3; } } Console.WriteLine（“Total is：”+ 2 * sum_totalcol2Xcol3）; 我得到了一个结果，但答案是错误的，这是一个非常大的数字。请帮忙。谢谢！

Answer 1

for（int j = 0; j＆lt; r; j ++）有什么作用？你正在计算矩阵[j，col2] *矩阵[j，col3] * r次

int sum_totalcol2Xcol3 = 0;

for (int row = 0; row < r; row++)
{
    sum_totalcol2Xcol3 += matrix[row, col2] * matrix[row, col3];
}
Console.WriteLine("Total is :" + sum_totalcol2Xcol3 );

或

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Answer 2

int product_col2Xcol3 = 0;
int sum_totalcol2Xcol3 = 0;

//Calculations of the SUM(Product) of col2 and col3
for (int row = 0; row < number_of_rows; row++)
{

     product_col2Xcol3 = matrix[row, col2] * matrix[row, col3];
     sum_totalcol2Xcol3 = sum_totalcol2Xcol3 + product_col2Xcol3 ;

}
Console.WriteLine("Total is :" + sum_totalcol2Xcol3 );

Answer 3

  int[,] matrix={
                    {1, 2, 3, 4},
                    {1, 2, 3, 4},
                    {1, 2, 3, 4},
                    {1, 2, 3, 4}
                };


  int product_col2Xcol3 = 0;
  int sum_totalcol2Xcol3 = 0;

  // if you precisely want the column 1 and 2 of each row then do as below:
  for (int row = 0; row <matrix.GetLength(0); row++)
  {

      product_col2Xcol3 = matrix[row, 1] * matrix[row, 2];
      sum_totalcol2Xcol3 += product_col2Xcol3;

  }
  Console.WriteLine("Total is :" + sum_totalcol2Xcol3);

计算数组中两列的乘积然后计算总和C＃

3 个答案: