Question

我想知道是否可以避免在自定义助手中使用..语法。

让我们说我有这个帮手：

Handlebars.registerHelper('for', function(from, to, incr, block) {
    var accum = '';
    for(var i = from; i < to; i += incr)
        accum += block.fn(i);
    return accum;
});

是否可以使用它而无需在其中添加..以供参考：

  {{#for 0 5 1}}
        {{#ifCond1OrCond2 (lookup ../bid this) (lookup ../ask this)}}
        <tr>
          <td>{{math this "+" 1}}</td>
          <td>{{#with (lookup ../../bid this)}}{{quantity}}{{/with}}</td>
          <td>{{#with (lookup ../../bid this)}}{{price}}{{/with}}</td>
          <td>{{#with (lookup ../../ask this)}}{{price}}{{/with}}</td>
          <td>{{#with (lookup ../../ask this)}}{{quantity}}{{/with}}</td>
        </tr>
      {{/ifCond1OrCond2}}
  {{/for}}

这是一个小提琴https://jsfiddle.net/ChristopheThiry/f9wu07f4/，显示正在发生的事情

以下是我想要使用的语法：

  {{#for 0 5 1}}
        {{#ifCond1OrCond2 (lookup bid this) (lookup ask this)}}
        <tr>
          <td>{{math this "+" 1}}</td>
          <td>{{#with (lookup bid this)}}{{quantity}}{{/with}}</td>
          <td>{{#with (lookup bid this)}}{{price}}{{/with}}</td>
          <td>{{#with (lookup ask this)}}{{price}}{{/with}}</td>
          <td>{{#with (lookup ask this)}}{{quantity}}{{/with}}</td>
        </tr>
      {{/ifCond1OrCond2}}
  {{/for}}

Answer 1

我发现自己是文档中的解决方案：使用@root完成工作，因为它从根元素开始。

 {{#for 0 5 1}}
        {{#ifCond1OrCond2 (lookup @root/bid this) (lookup ask this)}}
        <tr>
          <td>{{math this "+" 1}}</td>
          <td>{{#with (lookup @root/bid this)}}{{quantity}}{{/with}}</td>
          <td>{{#with (lookup @root/bid this)}}{{price}}{{/with}}</td>
          <td>{{#with (lookup @root/ask this)}}{{price}}{{/with}}</td>
          <td>{{#with (lookup @root/ask this)}}{{quantity}}{{/with}}</td>
        </tr>
      {{/ifCond1OrCond2}}
  {{/for}}

如何避免在车把帮手内使用..查找

1 个答案: