Question

这段代码有什么问题？它会检测我是否已经到达怪物的坐标但是只有其中一个，或者至少是最近的一个。如果我去其他坐标，它并没有告诉我怪物已经出现。不知道为什么，因为每次输入“北方”时我都会循环浏览怪物矢量。这是代码。

怪物类：

class Monster
{
    public:
        std::vector<std::string> names;
        std::vector<double> posx; // North - South
        std::vector<double> posy; // East - West

        bool compareCoords(double monsterPosX, double monsterPosY);
        void cMonster(std::string monsterName, double monsterPosX, double monsterPosY);
        void randomSpawn();

    protected:

    private:
};

compareCoords检测那些坐标上是否存在怪物以及cMonster（创建怪物）功能：

void Monster::cMonster(std::string monsterName, double monsterPosX, double monsterPosY)
{
    if (compareCoords(monsterPosX, monsterPosY) == false)
    {
        names.push_back(monsterName);
        posx.push_back(monsterPosX);
        posy.push_back(monsterPosY);
        std::cout << "Monster " << monsterName << " has been created at X: " << monsterPosX << " Y: " << monsterPosY << std::endl;
    }
}

bool Monster::compareCoords(double monsterPosX, double monsterPosY)
{
    for (unsigned int i = 0; i < posx.size(); i++)
    {
        if (monsterPosX == posx[i] && monsterPosY == posy[i])
        {
            return true;
        }
    }
    return false;
}

主：

int main()
{
    srand(time(0));
    Monster newenemy;
    Character newplayer;

    newenemy.cMonster("Weezo", 1, 0);
    newenemy.cMonster("Weezo", 2, 0);

    newplayer.posx.push_back(0);
    newplayer.posy.push_back(0);

    home:

    std::cout << "-->> ";
    std::string userInput;
    std::cin.clear();

    getline(std::cin, userInput);

    if (!userInput.compare("north"))
    {
        newplayer.headNorth();

        for (unsigned int i = 0; i < newenemy.names.size(); i++)
        {
            if (newplayer.posx[i] == newenemy.posx[i] && newplayer.posy[i] == newenemy.posy[i])
            {
                std::cout << "A " << newenemy.names[i] << " has appeared." << std::endl;
            }
        }
    }

    else if (!userInput.compare("south"))
    {
        newplayer.headSouth();

        for (unsigned int i = 0; i < newenemy.posx.size(); i++)
        {
            if (newplayer.posx[i] == newenemy.posx[i] && newplayer.posy[i] == newenemy.posy[i])
            {
                std::cout << "A " << newenemy.names[i] << " has appeared." << std::endl;
            }
        }
    }

    else
    {
        std::cout << "You have entered an invalid command." << std::endl;
    }
}

^正如你在这里看到的那样，它显示的是我在大猩猩坐标时的情况，而不是第二个怪物唐纳德特朗普。它只是忽略了第二个。

我被困在这里几个小时，我不明白可能出现的问题。谢谢！

从向量C ++中读取

0 个答案: