Question

我正在创建一个API。这是我的PHP函数。

function get_schools($cn){
    $schools = "SELECT * FROM schools";
    $school_result = mysqli_query($cn, $schools);
    $response_array['form_data']['schools'] = '';
    $school_array = array();
    while ($school_row = mysqli_fetch_assoc($school_result)) {
        $school_array[$school_row['school_id']] = $school_row['school_name'];
    }
    $response_array['status'] = 'success';
    $response_array['form_data']['schools'] = $school_array;
    echo json_encode($response_array);
}

这是我的js。

getSchools();

function getSchools(){
    var requestDATA = {
        'request': 'get_schools'
    }
    myApp.showIndicator();
    serverRequest(requestDATA, getSchoolsSuccess, responseError, true, true);
}

function getSchoolsSuccess(){
    if(hideIndicator){
        myApp.hideIndicator();
    }
    console.log(data);

    if(data.status == 'success'){

    }else if (data.status == 'error'){
        requestFailure(data.status, data.message, showAlert);
    } else if (data.status == '') {
        requestFailure(data.status, data.message, showAlert);
    }
}

/* AJAX Request Function */

function serverRequest(requestDATA, successCallback, errorCallback, hideIndicator, showAlert){
var METHOD = "POST";
    var serverURL = 'http://localhost/istudy/server.php'; //Path to Server.php
    var DATA_TYPE = 'json';
    var TIMEOUT = 20000;
    console.log(requestDATA);
    $$.ajax({
        url: serverURL,
        data: requestDATA,
        dataType: DATA_TYPE,
        type: METHOD,
        timeout: TIMEOUT,
        success: function(data){
            successCallback(data, hideIndicator, showAlert);
        },
        error: function(a, b, c){
            errorCallback(a, b, c, hideIndicator, showAlert);
        }
    }); 
}

/* Function to handle request error */

function responseError(xhr, textStatus, errorThrown, hideIndicator, showAlert){
    console.log(xhr);
    console.log(textStatus);
    console.log(errorThrown);
    var error_message = "";
    switch(textStatus){
        case 'error':
        error_message = "Please check your internet connection and try again.";
        break;
        case 'parsererror':
        error_message = "Internal error occureed. Report application administrator about this error.";
        break;
        case 'timeout':
        error_message = "Slow internet may be. Pull down to refresh page.";
        break;
        case 'abort':
        error_message = "The request was aborted.";
        break;
        default:
        error_message = "Cannot reach server at this time. You can report this error.";
        break;
    }
    if(hideIndicator){
        myApp.hideIndicator();
    }

    if(showAlert){
        myApp.alert(error_message, "Oh Snap! :(", null);
    }
}

/* Request With Server Fail or Error or Others */

function requestFailure(status, message, showAlert){
    if(showAlert){
        if(status == 'error'){
            myApp.alert(message, 'No Data Available!', null);
        }else if(status == ''){
            myApp.alert(message, 'Request Failure!', null);
        }else{
            if(showAlert){
                myApp.alert("Application was not ready to serve this request at this time.", 'Unknown Response', null);
            }
        }
    }
}

一切正常。查询也会在responseText中获取结果，但我得到了parseerror。知道可能是什么问题吗？

请参阅下面附图。

可能是什么问题？

Answer 1

由于您要将DATA_TYPE定义为json，这意味着执行请求后发送的数据已转换为array。这就是你得到parse error

的原因

通过结构函数获取AJAX调用的parseerror

1 个答案: