Question

在我的angularjs应用程序中，我有一个模型，它是一个对象数组，如下所示：

 $scope.originalData = [{

     "id": 10000,
     "transactionid": "gec43434",
     "status": "COMPLETED",
     "session_id": "TTYUU455667",
     "errors": "1",
     "start_timestamp": "2016-11-07 02:35:35",
     "log_field": "Sample Text For Testing"

 }, {

     "id": 10001,
     "transactionid": "r34fdfdf",
     "status": "COMPLETED",
     "session_id": "dfdfer3453df",
     "errors": "3",
     "start_timestamp": "2016-10-07 03:20:15",
     "log_field": "Sample Text2 For Testing"

 }];

现在我需要修改相同的对象数组，如下所示，除了log_field剩余的所有属性都应该放在同一个对象的另一个属性下。

$scope.modifiedData = [{
     "subItems": {
         "id": 1000,
         "transactionid": "gec43434",
         "status": "COMPLETED",
         "session_id": "TTYUU455667",
         "errors": "1",
         "start_timestamp": "2016-11-07 02:35:35"
     },
     "log_field": "Sample Text For Testing"

 }, {
     "subItems": {
         "id": 10001,
         "transactionid": "r34fdfdf",
         "status": "COMPLETED",
         "session_id": "dfdfer3453df",
         "errors": "3",
         "start_timestamp": "2016-10-07 03:20:15"
     },
     "log_field": "Sample Text2 For Testing"

 }]

Answer 1

这是你能做的。使用Array.map并删除。

＆＃13;

        select ir.ProductId,sum(ir.IssueQuantity)as 'Quantity',p.ProductName
        --,ir.IssueDate,ir.ReturnDate

        from Product.IssueReturn ir join Company.Product p on p.ProductId=ir.ProductId

        group by ir.ProductId,p.ProductName
        --,ir.IssueDate,ir.ReturnDate

＆＃13;

万一，如果你不应该修改原始数据，这就是你可以做的。

＆＃13;

var originalData = [{
  "id": 10000,
  "transactionid": "gec43434",
  "status": "COMPLETED",
  "session_id": "TTYUU455667",
  "errors": "1",
  "start_timestamp": "2016-11-07 02:35:35",
  "log_field": "Sample Text For Testing"
}, {
  "id": 10001,
  "transactionid": "r34fdfdf",
  "status": "COMPLETED",
  "session_id": "dfdfer3453df",
  "errors": "3",
  "start_timestamp": "2016-10-07 03:20:15",
  "log_field": "Sample Text2 For Testing"
}];


var result = originalData.map((item) => {
  var log_field = item.log_field;
  delete item.log_field;
  return {
    "subItems": item,
    "log_field": log_field
  };
});

console.log(result);

＆＃13;

Answer 2

似乎很简单

＆＃13;

const originalData = [{"id":10000,"transactionid":"gec43434","status":"COMPLETED","session_id":"TTYUU455667","errors":"1","start_timestamp":"2016-11-07 02:35:35","log_field":"Sample Text For Testing"},{"id":10001,"transactionid":"r34fdfdf","status":"COMPLETED","session_id":"dfdfer3453df","errors":"3","start_timestamp":"2016-10-07 03:20:15","log_field":"Sample Text2 For Testing"}]

const doNotMap = 'log_field'
const modifiedData = originalData.map(d => {
  let subKeys = Object.keys(d).filter(key => key !== doNotMap)
  return {
    subItems: subKeys.reduce((obj, key) => {
      return Object.assign(obj, {
        [key]: d[key]
      })
    }, Object.create(null)),
    [doNotMap]: d[doNotMap]
  }
})

console.info('Modified =', modifiedData)
console.log('Original =', originalData)

＆＃13;

所以这里的ES2015版本并没有太大差异

＆＃13;

var originalData = [{"id":10000,"transactionid":"gec43434","status":"COMPLETED","session_id":"TTYUU455667","errors":"1","start_timestamp":"2016-11-07 02:35:35","log_field":"Sample Text For Testing"},{"id":10001,"transactionid":"r34fdfdf","status":"COMPLETED","session_id":"dfdfer3453df","errors":"3","start_timestamp":"2016-10-07 03:20:15","log_field":"Sample Text2 For Testing"}]

var doNotMap = 'log_field'
var modifiedData = originalData.map(function(d) {
  var subKeys = Object.keys(d).filter(function(key) {
    return key !== doNotMap
  })
  var modified = Object.create(null)
  modified.subItems = subKeys.reduce(function(obj, key) {
    var keyObj = Object.create(null)
    keyObj[key] = d[key]
    return Object.assign(obj, keyObj)
  }, Object.create(null))

  modified[doNotMap] = d[doNotMap]
  return modified
})

console.info('Modified =', modifiedData)
console.log('Original =', originalData)

＆＃13;

Answer 3

这是我的方法，无论您的数据结构如何，我都会添加所有字段。这是＆＃34;略有＆＃34;如果您的领域需要改变，未来的证据。除WebPack外，所有字段都会添加到subItems。

log_field

angularjs，需要转换对象属性

3 个答案: