Ajax在android webview中不起作用

时间:2016-11-23 05:34:19

标签: android ajax webview android-webview

我正在webview中加载一个网站,我们在网站上使用了Ajax并且它在网页浏览器和移动浏览器上工作正常但是在android webview ajax不工作没有错误在控制台中。这是我的代码: -

public class Activity_WebView extends AppCompatActivity implements  
 ConnectivityReceiver.ConnectivityReceiverListener {
WebView webview;
ProgressDialog pro_dialog;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_web_view);

    webview = (WebView) findViewById(R.id.webview);
    webview.getSettings().setPluginState(WebSettings.PluginState.ON);
    webview.setWebViewClient(new loadinsame());
    pro_dialog = new ProgressDialog(Activity_WebView.this);
    webview.getSettings().setJavaScriptEnabled(true);
    webview.getSettings().setDomStorageEnabled(true);
    webview.getSettings().setAllowUniversalAccessFromFileURLs(true);

    boolean connection = checkConnection();
    if (connection) {
        webview.loadUrl("website url");
    } else {
        Toast.makeText(Activity_WebView.this, "Sorry! Not connected to 
       internet", Toast.LENGTH_SHORT).show();
        dialog_Show(webview, "Please check you Inernet connect and Reload.", 
        false);
    }
}

@Override
public void onNetworkConnectionChanged(boolean isConnected) {
    if (!isConnected) {
        Toast.makeText(Activity_WebView.this, "Sorry! Not connected to 
        internet", Toast.LENGTH_SHORT).show();
    }
}

private class loadinsame extends WebViewClient {

    @Override
    public void onPageStarted(WebView view, String url, Bitmap favicon) {
        super.onPageStarted(view, url, favicon);
        pro_dialog.setCancelable(false);
        pro_dialog.setMessage("Loading...");
        pro_dialog.show();
    }

    @Override
    public boolean shouldOverrideUrlLoading(WebView view, String url) {
                view.loadUrl(url);
        return true;
    }
    @Override
    public void onPageFinished(WebView view, String url) {
        super.onPageFinished(view, url);
        pro_dialog.dismiss();

    }

    @Override
    public void onReceivedError(final WebView webview, WebResourceRequest 
    request, WebResourceError error) {
        super.onReceivedError(webview, request, error);
        pro_dialog.dismiss();
       // dialog_Show(webview, "Error Occur, Do you want to Reload?", true);

    }
}

@Override
public void onBackPressed() {

    if (webview.canGoBack()) {
        webview.goBack();
    } else {
        super.onBackPressed();
    }
}

private boolean checkConnection() {
    boolean isConnected = ConnectivityReceiver.isConnected();
    return isConnected;
}

@Override
protected void onResume() {
    super.onResume();
    MyApplication.getInstance().setConnectivityListener(this);
}
}

当我使用模拟器检查Chrome网站时,发现我的ajax保持待定状态,然后在一段时间后取消。 提前谢谢。

4 个答案:

答案 0 :(得分:2)

通过覆盖shouldInterceptRequest拦截你的ajax调用是这样的:

private class LoadInSame extends WebViewClient {
    @Override
    public WebResourceResponse shouldInterceptRequest(WebView webview, WebResourceRequest webrequest)
    {
        Log.d("test", "shouldInterceptRequest");
       return this.handleRequest(webrequest.getUrl().toString());
    }
    @NonNull
    private WebResourceResponse handleRequest(@NonNull String urlString) {
        try {
            URL url = new URL(urlString);
            HttpURLConnection connection = (HttpURLConnection)url.openConnection();
            connection.setRequestProperty("User-Agent", "");
            connection.setRequestMethod("GET");
            connection.setDoInput(true);
            connection.connect();

            InputStream inputStream = connection.getInputStream();
            return new WebResourceResponse("text/json", "utf-8", inputStream);
        } catch (MalformedURLException e) {
            e.printStackTrace();
            return null;
        }
        catch (ProtocolException e) {
            e.printStackTrace();
            return null;
        }catch (IOException e) {
            e.printStackTrace();
            return null;
        }

    }
}

请同时遵循JAVA命名惯例。

答案 1 :(得分:2)

只需通过设置来推广@Jeff Thomas评论

mWebView.getSettings().setDomStorageEnabled(true);

工作了!

答案 2 :(得分:2)

解决方案

  1. 如果你想在 WebView 中加载 web url,那么你需要遵循我的代码它的代码工作正常,并且在 web 页面中使用的任何类型的脚本语言。

     public void webviewCallBack(String coverUrl) {
        WebView  WebView  webView = (WebView) findViewById(R.id.web_view);
            webView.getSettings().setJavaScriptCanOpenWindowsAutomatically(true);
            webView.getSettings().setPluginState(WebSettings.PluginState.ON);
            webView.getSettings().setAppCacheEnabled(true);
            webView.getSettings().setDatabaseEnabled(true);
            webView.getSettings().setDomStorageEnabled(true);
            webView.getSettings().setBuiltInZoomControls(true);
            webView.getSettings().setJavaScriptEnabled(true);
            webView.clearView();
            webView.measure(100, 100);
            webView.getSettings().setUseWideViewPort(true);
            webView.getSettings().setLoadWithOverviewMode(true);
    
            webView.setWebViewClient(new WebViewClient() {
    
                // For api level bellow 24
                @Override
                public boolean shouldOverrideUrlLoading(WebView view, String url) {
                    Log.d("weburl__", url);
    
                    if (url.startsWith("http") || url.startsWith("https")) {
                        // Return false means, web view will handle the link
                        return false;
                    } else if (url.startsWith("tel:")) {
                        // Handle the tel: link
                        handleTelLink(url);
    
   // Return true means, leave the current web view and handle the url itself
                        return true;
                    }
    
                    return false;
                }
    
                // From api level 24
                @RequiresApi(api = Build.VERSION_CODES.LOLLIPOP)
                @Override
                public boolean shouldOverrideUrlLoading(WebView view, WebResourceRequest request) {
                    // Get the tel: url
                    String url = request.getUrl().toString();
                    Log.d("weburl_____", url);
    
                    if (url.startsWith("http") || url.startsWith("https")) {
                   // Return false means, web view will handle the link
                        return false;
                    } else if (url.startsWith("tel:")) {
                        // Handle the tel: link
                        handleTelLink(url);
    
                        // Return true means, leave the current web view and handle the url itself
                        return true;
                    }
    
                    return false;
                }
            });
    
            // Load the url into web view
            webView.loadUrl(coverUrl);
            hoadler();
        }

    public void hoadler() {


        Runnable task = new Runnable() {
            public void run() {
                material_design_progressbar.setVisibility(View.VISIBLE);
            }
        };
        worker.schedule(task, 5, TimeUnit.SECONDS);
    }

  1. 希望此代码对您有所帮助!

答案 3 :(得分:0)

启用Java脚本后,它便可以正常工作。

String Message = Serial2.readString();
Serial.println(Message);