我有一个名为预测的表格,我们存储未来6个月所有产品的预测。例如,当我们在11月时,我们创建了12月,1月,2月,3月,4月和5月的预测。预测表看起来像下面的那个
+----------------+---------------+--------------+----------+
| product_number | forecasted_on | forecast_for | quantity |
+----------------+---------------+--------------+----------+
| Prod 1 | 2016-11-01 | 2016-12-01 | 100 |
| Prod 1 | 2016-11-01 | 2017-01-01 | 200 |
| Prod 1 | 2016-11-01 | 2017-02-01 | 300 |
| Prod 1 | 2016-11-01 | 2017-03-01 | 400 |
| Prod 1 | 2016-11-01 | 2017-04-01 | 500 |
| Prod 1 | 2016-11-01 | 2017-05-01 | 600 |
+----------------+---------------+--------------+----------+
表中包含产品编号列表和创建预测的日期,即forecasted_on和创建预测的月份以及预测数量。
每个月都会在接下来的6个月内添加数据。因此,当预测为2016年12月1日时,将在1月至6月期间创建预测。
我正在尝试制作一份报告,说明过去3个月的总预测情况如何变化。像这样的东西
+------------+----------------+---------------+----------------+
| | 0 months prior | 1 month prior | 2 months prior |
+------------+----------------+---------------+----------------+
| 2016-12-01 | 200 | 150 | 250 |
| 2017-01-01 | 300 | 250 | 150 |
| 2017-02-01 | 100 | 150 | 100 |
+------------+----------------+---------------+----------------+
目前我在rails中使用了大量重复代码来生成此表。我想看看是否有更简单的方法直接使用SQL查询。
非常感谢任何帮助。
答案 0 :(得分:0)
使用PIVOT查询:
select forecast_for,
sum( case when forecasted_on + interval '1' month = forecast_for
then quantity end ) q_0,
sum( case when forecasted_on + interval '2' month = forecast_for
then quantity end ) q_1,
sum( case when forecasted_on + interval '3' month = forecast_for
then quantity end ) q_2,
sum( case when forecasted_on + interval '4' month = forecast_for
then quantity end ) q_3,
sum( case when forecasted_on + interval '5' month = forecast_for
then quantity end ) q_4,
sum( case when forecasted_on + interval '6' month = forecast_for
then quantity end ) q_5
from Table1
group by forecast_for
order by 1
;
演示:http://sqlfiddle.com/#!15/30e5e/1
| forecast_for | q_0 | q_1 | q_2 | q_3 | q_4 | q_5 |
|----------------------------|--------|--------|--------|--------|--------|--------|
| December, 01 2016 00:00:00 | 100 | (null) | (null) | (null) | (null) | (null) |
| January, 01 2017 00:00:00 | (null) | 200 | (null) | (null) | (null) | (null) |
| February, 01 2017 00:00:00 | (null) | (null) | 300 | (null) | (null) | (null) |
| March, 01 2017 00:00:00 | (null) | (null) | (null) | 400 | (null) | (null) |
| April, 01 2017 00:00:00 | (null) | (null) | (null) | (null) | 500 | (null) |
| May, 01 2017 00:00:00 | (null) | (null) | (null) | (null) | (null) | 600 |
答案 1 :(得分:0)
假设(product_number, forcast_on, forcasted_for)
是唯一的(因此不需要聚合),那么这应该可以完成这项工作:
WITH forecast_dates AS (
SELECT DISTINCT product_number, forcast_for
FROM forecasts
)
SELECT
fd.forcast_for AS "forecast for",
m1.quantity AS "one month prior",
m2.quantity AS "two months prior",
m3.quantity AS "three months prior"
FROM forecast_dates fd
LEFT JOIN forecasts m1 ON fd.forcast_for = m1.forcast_for AND fd.forcast_for = m1.forcasted_on + INTERVAL '1 month'
LEFT JOIN forecasts m2 ON fd.forcast_for = m2.forcast_for AND fd.forcast_for = m2.forcasted_on + INTERVAL '2 month'
LEFT JOIN forecasts m3 ON fd.forcast_for = m3.forcast_for AND fd.forcast_for = m3.forcasted_on + INTERVAL '3 month'
WHERE fd.product_number = 'Prod 1'
ORDER BY fd.forcast_for;