Question

我在mongoDB上的聚合管道就像。

struct ABLoop {
    float a, b, time_from_a;
};

我的资产集合中有条目，如。

db.assets.aggregate([{"$match":{"$or":[{"albums":{"$elemMatch":{"id":"78c72b85944e5085a4a3be77a2d175fe","order":{"$gt":"C2"}}}},{"albums":{"$elemMatch":{"id":"18f292072b7555965e0f61a0331a3a43","order":{"$gt":"C2"}}}}]}}
,{"$unwind":"$albums"},
{"$sort":{"albums.order":1,"created":1}},
{"$group":{"_id":"$albums.id","assets":{"$push":"$$ROOT"}}},
{"$project":{"assets":{"$slice":["$assets",6]}}}])

返回的结果类似于。

{
    "_id": "8ed6dc473e331d895ecbdea7f9bbd55e",
    "created": 1479463428837247,
    "updated": 1479463428837247,
    "catalog_id": "4b5ce056175151e3f0aa1741eedb7f12",
    "albums": {
      "id": "18f292072b7555965e0f61a0331a3a43",
      "order": "D1"
    }
  },
  {
    "_id": "aec701d23dfe5f3a100d678e1a04f716",
    "created": 1479463428902155,
    "updated": 1479463428902155,
    "catalog_id": "4b5ce056175151e3f0aa1741eedb7f12",
    "albums": {
      "id": "18f292072b7555965e0f61a0331a3a43",
     "order": "D2"
    }
  },
  {
    "_id": "b2fe8f9dcf8f3f92f6396cfa574ef71c",
    "created": 1479463428971650,
    "updated": 1479463428971650,
    "catalog_id": "4b5ce056175151e3f0aa1741eedb7f12",
    "albums": {
      "id": "18f292072b7555965e0f61a0331a3a43",
      "order": "E1"
    }
  },
  {
    "_id": "050b550fb23bf780f93eec43cbc667f1",
    "created": 1479463428065297,
    "updated": 1479463428065297,
    "catalog_id": "4b5ce056175151e3f0aa1741eedb7f12",
    "albums": {
      "id": "78c72b85944e5085a4a3be77a2d175fe",
      "order": "D1"
    }
  },
  {
    "_id": "dc54279bc0318f41808b65d1fe7142b2",
    "created": 1479463428134560,
    "updated": 1479463428134560,
    "catalog_id": "4b5ce056175151e3f0aa1741eedb7f12",
    "albums": {
      "id": "78c72b85944e5085a4a3be77a2d175fe",
      "order": "D2"
    }
  }

结果与用于或在匹配查询中传递的相册的顺序不同。 78c72b85944e5085a4a3be77a2d175fe将在18f292072b7555965e0f61a0331a3a43之后发布。理想情况下，它应该与传递给查询的顺序相同。任何想法

Answer 1

我知道这真的很晚，但是我发现自己进行了查找，并经历了大约25个堆栈溢出问题，因此我认为应该发表。这是我所做的（用于聊天室，因此，如果您想分页，请按相反的顺序进行。

                        Group.find({ name: { $regex : new RegExp(name, "i") } })
                            .skip(pageOptions.page*pageOptions.limit)
                            .limit(pageOptions.limit)
                            .sort( '-createdAt' )
                            .populate("sender")
                            .exec((err, result) => {
                                result.reverse();
                                callback(err, result);
                            });

关键是：

result.reverse();

希望这可以帮助某人。

mongoDB聚合查询以相反的顺序返回结果

1 个答案: