Question

我试图用DNA序列做一些基本的python，但现在我遇到了一个小问题。

这是我的初始代码：

def positie(enzyme):
    pos = sequentie.find(enzyme.lower())
    print (pos)

def searchopdracht(enzyme):
    if enzyme.lower() in sequentie:
        print(enzyme, " does cut, at location:")
        positie(enzyme)
        print(" ")
    else:
        print(enzyme, "does not cut")
        print(" ")

for enzyme in [DdeI, BspMII, EcoRI, HindIII, TaqI]:
    searchopdracht(enzyme)

其中输出以下内容：

CTGAG does cut, at location: 1022
TCCGGA does not cut  
GAATTC  does cut, at location: 1449
AAGCTT  does cut, at location: 77
TCGA  does cut, at location: 171

一切都很好并且有效，但是我想要显示酶的名称而不是序列，例如，不是＆＃34; CTGAG确实切割，位置：1022＆＃34;但是＆＃34; DdeI确实在地点：1022＆＃34;

这是我尝试的（但没有提供任何输出），但随意提出其他建议：

def positie( enzyme ):
    pos = sequentie.find(enzyme.lower())
    print (pos)

def searchopdracht(enzyme, enzyme_name):
    if enzyme.lower() in sequentie:
        print(enzyme_name," does cut, at location:")
        positie(enzyme)
        print(" ")
    else:
        print(enzyme_name, "does not cut")
        print(" ")

list1 = [DdeI, BspMII, EcoRI, HindIII, TaqI]
list2 = ["DdeI", "BspMII", "EcoRI", "HindIII", "TaqI"]

for (enzyme, enzyme_name) in (list1, list2):
    searchopdracht(enzyme)

Answer 1

您需要将enzyme_name作为参数传递给searchopdracht()，并使用zip创建输入的元组对：

for enzyme, enzyme_name in zip(list1, list2):
    searchopdracht(enzyme, enzyme_name) # added argument

试图在for循环中使用2个列表不起作用

1 个答案: