在java中从接口实现泛型方法

时间:2016-11-23 01:09:14

标签: java generics interface generic-method

我有两个接口和一个实现它们的类。在界面中,我展示了一种常用方法和一种通用方法。在main方法中实现它们时,通常的方法显示正确的结果,但通用的方法没有。如果可能的话,你能告诉我,为什么increase_twice()方法没有返回正确的结果呢?这是我的代码:

Rectangle.java:

public class Rectangle implements TwoDShape {

    private double width, height;

    public Rectangle (double width, double height) {
        this.width = width;
        this.height = height;
    }

    public double area() {
        return width * height;
    }

    public double perimeter() {
        return 2.0 * (width + height);
    }

    public void describe() {
        System.out.println("Rectangle[width=" + width + ", height=" + height + "]");
    }

    @Override
    public Rectangle increase_twice() {
        // TODO Auto-generated method stub
        return new Rectangle(2*this.width, 2*this.height);
    }


}

TwoDShape.java:

public interface TwoDShape extends GeometricShape {
    public double  area();


}

GeometricShape.java:

public interface GeometricShape<T extends GeometricShape<T>>
{
    public void describe();
    public T increase_twice();

}

最后测试类ArrayListExample.java

import java.util.ArrayList;


public class ArrayListExample {



     public static void describe_all( ArrayList<? extends GeometricShape> shapes )

     {
         for(int i=0;i<shapes.size();i++)
         {
            shapes.get(i).describe();

         } 
         System.out.println("Total number of shapes:"+ shapes.size());
     }


    private static ArrayList<Rectangle> increase_size(ArrayList<Rectangle> rects)
    {
          for(int i=0;i<rects.size();i++)
          {
            rects.get(i).increase_twice();

          }
        return rects; 

    }


     public static void main(String[] args) {


        System.out.println("The result of describe() method:"); 

        System.out.println();
        System.out.println("Example rectangles");
        ArrayList<Rectangle> rects = new ArrayList<Rectangle>();
        rects.add(new Rectangle(2.0, 3.0));
        rects.add(new Rectangle(5.0, 5.0));
        describe_all(rects);
        System.out.println();

        System.out.println("The result of increase_twice() method:"); 
        System.out.println();
        System.out.println("Example rectangles after increase:");
        ArrayList<Rectangle> double_rects =  increase_size(rects);
        describe_all(double_rects);

    }


}

我希望increase_twice将返回Rectangle [width = 4.0,height = 6.0]的矩形 Rectangle [width = 10.0,height = 10.0]但它的返回方式与describe方法相同,即: 矩形[宽度= 2.0,高度= 3.0] 矩形[宽度= 5.0,高度= 5.0] 如果可能的话,你能告诉我哪里出错了吗?

2 个答案:

答案 0 :(得分:1)

我认为问题出在increase_twice函数中。当您调用rects.get(i).increase_twice();时,实际上是在创建一个具有doubled值并返回的新Rectangle对象。您没有更新当前对象。 increase_twice方法应该是:

@Override
    public void increase_twice() {
        // TODO Auto-generated method stub
        this.width *= 2;
        this.height *= 2;
    }

这样,您将更新从ArrayList获取的当前对象的宽度和高度值。 您可能必须更改increase_twice()的定义,因为我认为您不需要返回一个新的Rectangle对象。

如果有效,请告诉我。

答案 1 :(得分:1)

Rectangle.increase_twice()返回一个新的Object。但是,在ArrayListExample.increase_size()中,未设置返回的对象。 您可以将该方法修改为:

import {createStore} from 'redux'

或者您可以将Rectangle.increase_twice()修改为:

private static ArrayList<Rectangle> increase_size(ArrayList<Rectangle> rects) {
    for (int i = 0; i < rects.size(); i++) {
        rects.set(i, rects.get(i).increase_twice());
    }
    return rects;
}

和GeometricShape.increase_twice()声明:

@Override
    public void increase_twice() {
        // TODO Auto-generated method stub
        this.width = 2 * this.width;
        this.height = 2 * this.height;
    }