Question

我有一个自动生成的字符串，如下所示：

["January","February",null,"April"]

我需要从字符串中删除“，null”的任何匹配，即：

["January","February",null,"April"] --> ["January","February","April"]

如何找到除",null"以外的所有内容？

我尝试了"^(?!,null).*"的变体而没有成功。

Answer 1

如上所述回答您的问题，您不需要正则表达式：

str = str.replace(",null", "");

但是，要处理边缘情况：

["January","February",null,"April"] --> ["January","February","April"]
["January",null,null,"April"] --> ["January","April"]
[null,"January","February","April"] --> ["January","February","April"]
["January","February","April",null] --> ["January","February","April"]
[null] --> []

你将更好地服务于正则表达式：

str = str.replaceAll("(?<=\\[)null,?|,null", "");

替换正则表达式适用于null第一个（也可能是唯一的）位置，以及任何其他情况。

Answer 2

请查看这个，我们可以使用过滤功能

var arr = [null, "January","February",null,"April", null];

var arr2 = arr.filter(function(x){return x !== null})

console.log(arr,arr2);

从字符串REGEX中删除字符串

2 个答案: