Question

我需要一些关于此的帮助，我想知道当用户点击页面上的任何位置一次时如何打开新选项卡。这是我的博主。我有这段代码：

＆＃13;

<script type="text/javascript">

    var popup = function() {

        window.open ("http://example.com", "Window","status=1,toolbar=1,width=500,height=300,resizable=yes");
    }

</script>
<body onclick="popup()">
    <h1>Click anywhere!</h1>
</body>

＆＃13;

但是没有用，因为每次点击都会打开一个新标签，我尝试使用Cookie代码

＆＃13;

<SCRIPT LANGUAGE="JavaScript">

<!-- Begin
var expDays = 1; // number of days the cookie should last

var page = "only-popup-once.html";
var windowprops = "width=300,height=200,location=no,toolbar=no,menubar=no,scrollbars=no,resizable=yes";

function GetCookie (name) {
var arg = name + "=";
var alen = arg.length;
var clen = document.cookie.length;
var i = 0;
while (i < clen) {
var j = i + alen;
if (document.cookie.substring(i, j) == arg)
return getCookieVal (j);
i = document.cookie.indexOf(" ", i) + 1;
if (i == 0) break;
}
return null;
}
function SetCookie (name, value) {
var argv = SetCookie.arguments;
var argc = SetCookie.arguments.length;
var expires = (argc > 2) ? argv[2] : null;
var path = (argc > 3) ? argv[3] : null;
var domain = (argc > 4) ? argv[4] : null;
var secure = (argc > 5) ? argv[5] : false;
document.cookie = name + "=" + escape (value) +
((expires == null) ? "" : ("; expires=" + expires.toGMTString())) +
((path == null) ? "" : ("; path=" + path)) +
((domain == null) ? "" : ("; domain=" + domain)) +
((secure == true) ? "; secure" : "");
}
function DeleteCookie (name) {
var exp = new Date();
exp.setTime (exp.getTime() - 1);
var cval = GetCookie (name);
document.cookie = name + "=" + cval + "; expires=" + exp.toGMTString();
}
var exp = new Date();
exp.setTime(exp.getTime() + (expDays*24*60*60*1000));
function amt(){
var count = GetCookie('count')
if(count == null) {
SetCookie('count','1')
return 1
}
else {
var newcount = parseInt(count) + 1;
DeleteCookie('count')
SetCookie('count',newcount,exp)
return count
   }
}
function getCookieVal(offset) {
var endstr = document.cookie.indexOf (";", offset);
if (endstr == -1)
endstr = document.cookie.length;
return unescape(document.cookie.substring(offset, endstr));
}

function checkCount() {
var count = GetCookie('count');
if (count == null) {
count=1;
SetCookie('count', count, exp);

window.open(page, "", windowprops);

}
else {
count++;
SetCookie('count', count, exp);
   }
}
//  End -->
</script>

＆＃13;

但是没有用，因为浏览器会阻止弹出窗口。

某些网站如powvideo或animeflv有一个脚本，当用户点击任意位置时会自动打开一个新标签，如data：text / html; base64，XXXXX

感谢。

Answer 1

您只需要一个可以检查的标志，看看是否仍然可以打开弹出窗口。

var openPage = true;
function popup() {
  if(openPage){
   window.open ("http://example.com","Window","status=1,toolbar=1,width=500,height=300,resizable=yes");
   openPage = false;
  }
}

<body onclick="popup()">
    <h1>Click anywhere!</h1>
</body>

Answer 2

<body class="index">

  <h1>Click anywhere!</h1>

  <script type="text/javascript">

    var homepage = document.querySelector('body.index');

    var popUp = function(e) {
      window.open ("http://example.com", "Window","status=1,toolbar=1,width=500,height=300,resizable=yes");
      homepage.removeEventListener('click', popUp, false);
    }

    homepage.addEventListener('click', popUp, false);

  </script>


</body>

Answer 3

<script>
var clickCounter = 0;

function clickMagnet(e){
  if( clickCounter == 0 ) {
    // open window code here
  }
  clickCounter++;
}
</script>
<body onclick="clickMagnet">

您需要一个跟踪点击次数的变量。如果它大于0则什么都不做。在我的例子中，我将一个函数绑定到由click事件触发的body。 clickCounter变量跟踪点击次数。把你的代码打开if条件里面的窗口，其中conditionCheck == 0你应该是好的。

当用户仅在页面上的任意位置单击一次时打开新选项卡

3 个答案: