Question

我使用以下代码计算时间差

$estimated_time = '40:30';
$completed_time = '20:45';

// list the times
list($hours1, $minutes1) = explode(':', $estimated_time);
list($hours2, $minutes2) = explode(':', $completed_time);

// mktime
$t1 = mktime($hours1, $minutes1); // estimated time
$t2 = mktime($hours2, $minutes2); // completed time

// Calc the difference in seconds
$seconds = $t1 - $t2;
// hours
$hours     =  floor($seconds / (60*60));
// minutes
$minutes   =  floor(($seconds / 60) % 60);

// result 19:45
echo $diff = $hours . ':' . $minutes;

此计算有效，因为预计会有19:45。问题是当我像这样改变时间时

// expected 4:30 extra hours but result is -5:30
// this is caused by the floor method but if I remove the floor
// method the positive value is not working correctly
$estimated_time = '40:00';
$completed_time = '44:30';

结果为-5：-30。这是由于地板造成的。如何正确地使用正值和负值。这也是用时间计算的正确方法。

我曾尝试使用DateTime但它无法处理大于24的小时

解决感谢@Mad Dog PHP calc difference between time greater than 24 hours

$estimated_time = '40:30';
$completed_time = '20:55';

// invert
// 0 => positive
// 1 => negative

// list the times
list($hours1, $minutes1) = explode(':', $estimated_time);
list($hours2, $minutes2) = explode(':', $completed_time);

$date1 = new DateTime('now', new DateTimeZone('UTC'));
$date2 = new DateTime('now', new DateTimeZone('UTC'));
$time1 = new DateInterval('PT'.$hours1.'H'.$minutes1.'M');
$time2 = new DateInterval('PT'.$hours2.'H'.$minutes2.'M');

$date1->add($time1);
$date2->add($time2);

$diff = $date2->diff($date1);
$result = ($diff->days * 24 + $diff->h) . $diff->format(':%I');

if($diff->invert == 0){
    echo $result;
} else {
    echo 0 . ' (extra time: '.$result.')';
}

PHP计算时间差异

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