问题陈述
为了运行基因注释软件，我需要准备两种类型的文件，即vcard文件和覆盖表，并且必须与vcard和coverage表进行一对一的匹配。由于我运行2k样本，很难识别哪个文件不是一对一匹配。我知道这两个文件都有唯一的标识号，因此，如果两个文件夹中的文件具有相同的唯一编号，我将其视为＆＃34;相同＆＃34;文件
我制作了一个比较两个文件夹并报告每个文件夹中唯一条目的程序。为此，我制作了两个列表，其中包含每个目录的唯一文件名。
我想格式化报告文件（制表符分隔的.txt文件），使其看起来如下所示：
Unique in fdr1 Unique in fdr2
file x file a
file y file b
file z file c
我发现这很难做，因为我必须迭代两次（因为我有两个列表），但据我所知，没有办法回到StreamWriter的前一行。基本上，一旦我遍历第一个列表并填充第一列，我怎么能用第二个列填充第二列？
有人可以帮我解决这个问题吗？
由于
如果代码的设计必须改变（即一个列表而不是两个），请告诉我
根据某些用户的要求，这就是我要做的事情（不工作版本）
// Write report
using (StreamWriter sw = new StreamWriter(dest_txt.Text + @"\" + "Report.txt"))
{
// Write headers
sw.WriteLine("Unique Entries in Folder1" + "\t" + "Unique Entries in Folder2");
// Write unique entries in fdr1
foreach(string file in fdr1FileList)
{
sw.WriteLine(file + "\t");
}
// Write unique entries in fdr2
foreach (string file in fdr2FileList)
{
sw.WriteLine(file + "\t");
}
sw.Dispose();
}
根据我查找唯一条目的方法的要求，这是我的代码段
Dictionary<int, bool> fdr1Dict = new Dictionary<int, bool>();
Dictionary<int, bool> fdr2Dict = new Dictionary<int, bool>();
List<string> fdr1FileList = new List<string>();
List<string> fdr2FileList = new List<string>();
string fdr1Path = folder1_txt.Text;
string fdr2Path = folder2_txt.Text;
// File names in the specified directory; path not included
string[] fdr1FileNames = Directory.GetFiles(fdr1Path).Select(Path.GetFileName).ToArray();
string[] fdr2FileNames = Directory.GetFiles(fdr2Path).Select(Path.GetFileName).ToArray();
// Iterate through the first directory, and add GL number to dictionary
for(int i = 0; i < fdr1FileNames.Length; i++)
{
// Grabs only the number from the file name
string number = Regex.Match(fdr1FileNames[i], @"\d+").ToString();
int glNumber;
// Make sure it is a number
if(Int32.TryParse(number, out glNumber))
{
fdr1Dict[glNumber] = true;
}
// If number not present, raise exception
else
{
throw new Exception(String.Format("GL Number not found in: {0}", fdr1FileNames[i]));
}
}
// Iterate through the second directory, and add GL number to dictionary
for (int i = 0; i < fdr2FileNames.Length; i++)
{
// Grabs only the number from the file name
string number = Regex.Match(fdr2FileNames[i], @"\d+").ToString();
int glNumber;
// Make sure it is a number
if (Int32.TryParse(number, out glNumber))
{
fdr2Dict[glNumber] = true;
}
// If number not present, raise exception
else
{
throw new Exception(String.Format("GL Number not found in: {0}", fdr2FileNames[i]));
}
}
// Iterate through the first directory, and find files that are unique to it
for (int i = 0; i < fdr1FileNames.Length; i++)
{
int glNumber = Int32.Parse(Regex.Match(fdr1FileNames[i], @"\d+").Value);
// If same file is not present in the second folder add to the list
if(!fdr2Dict[glNumber])
{
fdr1FileList.Add(fdr1FileNames[i]);
}
}
// Iterate through the second directory, and find files that are unique to it
for (int i = 0; i < fdr2FileNames.Length; i++)
{
int glNumber = Int32.Parse(Regex.Match(fdr2FileNames[i], @"\d+").Value);
// If same file is not present in the first folder add to the list
if (!fdr1Dict[glNumber])
{
fdr2FileList.Add(fdr2FileNames[i]);
}
答案 0 :(得分：0)
我会一次构建每一行。像这样：
int row = 0;
string[] fdr1FileList = new string[0];
string[] fdr2FileList = new string[0];
while (row < fdr1FileList.Length || row < fdr2FileList.Length)
{
string rowText = "";
rowText += (row >= fdr1FileList.Length ? "\t" : fdr1FileList[row] + "\t");
rowText += (row >= fdr2FileList.Length ? "\t" : fdr2FileList[row]);
row++;
}
答案 1 :(得分：0)
尝试这样的事情：
static void Main(string[] args)
{
Dictionary<int, string> fdr1Dict = FilesToDictionary(Directory.GetFiles("path1"));
Dictionary<int, string> fdr2Dict = FilesToDictionary(Directory.GetFiles("path2"));
var unique_f1 = fdr1Dict.Where(f1 => !fdr2Dict.ContainsKey(f1.Key)).ToArray();
var unique_f2 = fdr2Dict.Where(f2 => !fdr1Dict.ContainsKey(f2.Key)).ToArray();
int f1_size = unique_f1.Length;
int f2_size = unique_f2.Length;
int list_length = 0;
if (f1_size > f2_size)
{
list_length = f1_size;
Array.Resize(ref unique_f2, list_length);
}
else
{
list_length = f2_size;
Array.Resize(ref unique_f1, list_length);
}
using (StreamWriter writer = new StreamWriter("output.txt"))
{
writer.WriteLine(string.Format("{0,-30}{1,-30}", "Unique in fdr1", "Unique in fdr2"));
for (int i = 0; i < list_length; i++)
{
writer.WriteLine(string.Format("{0,-30}{1,-30}", unique_f1[i].Value, unique_f2[i].Value));
}
}
}
static Dictionary<int, string> FilesToDictionary(string[] filenames)
{
Dictionary<int, string> dict = new Dictionary<int, string>();
for (int i = 0; i < filenames.Length; i++)
{
int glNumber;
string filename = Path.GetFileName(filenames[i]);
string number = Regex.Match(filename, @"\d+").ToString();
if (int.TryParse(number, out glNumber))
dict.Add(glNumber, filename);
}
return dict;
}
答案 2 :(得分：0)
我非常有信心，这会在我测试过的时候起作用：
static void Main(string[] args)
{
var firstDir = @"Path1";
var secondDir = @"Path2";
var firstDirFiles = System.IO.Directory.GetFiles(firstDir);
var secondDirFiles = System.IO.Directory.GetFiles(secondDir);
print2Dirs(firstDirFiles, secondDirFiles);
}
private static void print2Dirs(string[] firstDirFile, string[] secondDirFiles)
{
var maxIndex = Math.Max(firstDirFile.Length, secondDirFiles.Length);
using (StreamWriter streamWriter = new StreamWriter("result.txt"))
{
streamWriter.WriteLine(string.Format("{0,-150}{1,-150}", "Unique in fdr1", "Unique in fdr2"));
for (int i = 0; i < maxIndex; i++)
{
streamWriter.WriteLine(string.Format("{0,-150}{1,-150}",
firstDirFile.Length > i ? firstDirFile[i] : string.Empty,
secondDirFiles.Length > i ? secondDirFiles[i] : string.Empty));
}
}
}
这是一个非常简单的代码，但如果你需要帮助理解它，请告诉我:)