Question

我有一个HashMap，里面有键和值。我想用字符串中的地图值替换键。

在字符串中，键被写为 @keyName 或 @＆＃34; keyName＆＃34; 这些应该替换为 map.get（＆＃34; keyName＆＃34;）

让我们说我们的地图就是这个

"key1" : "2"  
"key2" : "3"  
"key3" : "4"  
"key 4" : "5"
"key-5" : "6"

因此，如果我们处理字符串＆＃34; hello world，我已经@ key1岁了。＆＃34; ，它将成为＆＃34; hello world，我是2岁。＆＃34;

我们可以使用 @＆＃34; key1＆＃34; ，而不是 @ key1 。如果我们在没有引号的情况下使用它，则空格（空格字符）或EOF应该跟在键名后面，并且键名不应该包含空格。但是如果键名中有一个空格，那么它应该是引号。

如果我们处理字符串＆＃34; hello world，我就是@＆＃34; key @＆＃34; key1＆＃34;＆＃34;在第一步它应该替换特殊字符串中的特殊字符串并成为＆＃34; hello world，我是@＆＃34; key2＆＃34;已经过了。＃34; 。岁了。＆＃34; 然后第二步它应该是＆＃34;你好世界，我3岁。＆＃34;

我已经为一个特殊字符串完成了它，它不识别特殊字符串中的特殊字符串。这是代码：

private static Pattern specialStringPattern = Pattern.compile("@\"([^\"]*?)\"|@\\S+");

/** this replaces the keys inside a string with their values.
 * for example @keyName or @"keyName" is replaced with the value of the keyName. */
public static String specialStrings(String s) {
    Matcher matcher = specialStringPattern.matcher(s);
    while (matcher.find()) {
        String text = matcher.group();
        text = text.replace("@","").replaceAll("\"","");
        s = s.replace(matcher.group(),map.get(text));
    }
    return s;
}

抱歉我的英语，以及我缺乏正则表达式的知识。我认为通过稍微修改代码应该很容易得到答案。

以下是我需要的一些例子：

There is @key1 apples on the table.  
There is 2 apples on the table.

There is @"key1" apples on the table.  
There is 2 apples on the table.

There is @key 4 apples on the table.
There is null 4 apples on the table.

There is @"key 4" apples on the table.
There is 5 apples on the table.

There is @key@key2 apples on the table.
There is @key3 apples on the table. (second step)
There is 4 apples on the table. (final output)

There is @"key @"key3"" apples on the table.
There is @"key 4" apples on the table. (second step)
There is 5 apples on the table. (final output)

There is @"key @key3" apples on the table.
There is @"key 4" apples on the table. (second step)
There is 5 apples on the table. (final output)

There is @"key @key3 " apples on the table.
There is @"key 4 " apples on the table. (second step)
There is null apples on the table. (final output)

There is @key-5 apples on the table.
There is 6 apples on the table.

Answer 1

我制作的正则表达式符合您的示例： https://regex101.com/r/nudYEl/2

@(\"[\w\s]+\")|(?!@(\w+)@(\w+))@(\w+)

你需要修改你的函数来递归：

public static String specialStrings(String s) {
    Matcher matcher = specialStringPattern.matcher(s);
    boolean findAgain = false;
    while (matcher.find()) {
        String text = matcher.group();
        text = text.replace("@","").replaceAll("\"","");
        s = s.replace(matcher.group(),map.get(text));
        findAgain = true;
    }
    if (findAgain) return specialStrings(s);
    return s;
}

[更新]
正则表达式：https://regex101.com/r/nudYEl/4

@(\"[\w\s-]+\")|(?!@([\w-]+)@([\w-]+))@([\w-]+)

Answer 2

不要使用正则表达式：

for (boolean hit = true; hit;) {
    hit = false;
    for (String key : map.keySet()) {
        if (str.contains("@\"" + key + "\"")) {
            str = str.replace("@\"" + key + "\"", map.get(key));
            hit = true;
        } else if (str.contains("@" + key  )) {
            str = str.replace("@" + key + "", map.get(key));
            hit = true;
        }
    }
}

使用正则表达式

2 个答案: