Question

我试图使用php将我的PHP代码转换为javascript ajax。你可以帮我纠正错误，因为我的php代码仍在激活。

html代码：

<form method="post" enctype="multipart/form-data" action="testadd.php">
<input type="file" name="image" id="image">
<br/>
<input type="submit" name="submit" value="upload" id="submit">
</form>

PHP：

    <?php

        if(isset($_POST['submit'])){

           if(getimagesize($_FILES['image']['tmp_name']) == false){
                  echo "Please select an image";
                  echo "<br/>";

           }else{
                $image = addslashes($_FILES['image']['tmp_name']);
                $name = addslashes($_FILES['image']['name']);
                $image = file_get_contents($image);
                $image = base64_encode($image);
                saveImage($name, $image);
           }

        }

        displayImage();

        function saveImage($name, $image){
          $con = new PDO("mysql:host=localhost; dbname=testimages", "root", "");
          $con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
          $stmt = $con->query("INSERT INTO images(id, name, image) VALUES(38836929, '$name', '$image') ON DUPLICATE KEY UPDATE image='$image', name='$name'");
          $stmt->execute();
        }
        function displayImage(){
            $con = new PDO("mysql:host=localhost; dbname=testimages", "root", "");
            $con->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
            $stmt = $con->query("SELECT * FROM images");
            $stmt->execute();
            while($result = $stmt->fetch(PDO::FETCH_OBJ)){
                 echo '<img height="24" width="24" src="data:image;base64,' . $result->image . '">';
                 echo '<br/>';
                 echo $result->name . ' ';
            }
        }

 ?>

的javascript：

   $(document).ready(function(){
    $("#submit").click(function(){

        var image = document.getElementById("image").value;

        alert(" " + image);

        if(image == ""){
            alert("please select image");
        }else{
            $.ajax({
                type: "POST",
                url: "testadd.php",
                data: "image=" + image,
                success: function(data){
                    if(data == success){
                        alert("test");
                    }else{
                        alert("fail");
                    }
                }

            });
        }
        return false;
    });
});

请你检查一下应该是什么问题才能修复。

Answer 1

AJAX必须有内容Type，ProcessData才能上传图片文件

             $.ajax({
                  url: 'Your url here',
                  data: formData,
                  type: 'POST',
                  // THIS MUST BE DONE FOR FILE UPLOADING
                  contentType: false,
                  processData: false,
                  // ... Other options like success and etc
                  success : function(data){
                      //Do stuff for ahed process....
                  }
                });

将图像从php发布到javascript

1 个答案: