PHP：如何从不同的数组中获取常见值？

Question

我有两个数组如下： -

$a = ["2","11","6"];
$b = ["6","7"];
$c = array_diff($a, $b);

$c = ["2","11"];

$c中的结果是错误的。我希望结果应为$c = [6]

换句话说，我希望返回两个数组中的公共元素！但它给出了错误的错误。请帮助我？

Answer 1

使用array_intersect()

$a = ["2","11","6"];
$b = ["6","7"];
$c = array_intersect($a, $b);

演示：https://eval.in/682653

Answer 2

您可以使用array_intersect

$c = array_intersect($a, $b);

Answer 3

$a = ["2","11","6"];
$b = ["6","7"];
$c = array_intersect($a,$b);

Answer 4

使用array_intersect（http://php.net/manual/en/function.array-intersect.php）

<?php
$a = ["2","11","6"];
$b = ["6","7"];
$c = array_intersect($a, $b);

print_r($c)

?>