我在Excel中遇到这个问题,我需要从一串文本中提取数据,如下所示。以下数据全部位于不同的行上。我试图仅将斜杠之间的数据提取为x/y/z/a/b/c
格式,并忽略前面的其余数据。希望可以使用vba解决此问题。
一个例子:
s1 167.4/164.2/172.0/165.8/162.5/165.6
s2 163.6/164.1/167.2/167.1/165.6/167.6
S#1:0.1682/0.1646/0.1641/0.1653/0.1622/0.1642
S#2:0.1623/0.1621/0.1667/0.1680/0.1667/0.1643
s24=1903/1881/1873/1903/1915/1891
s25=1872/1858/1904/1879/1854/1868
SLOT 24:0.2031/0.1991/0.1959/0.1989/0.1987/0.2051
SLOT 25:0.2014/0.2019/0.2014/0.2033/0.2001/0.2017
答案 0 :(得分:1)
正则表达式将是最有力的答案。
需要自定义VBA功能和表达式以满足您的要求。
详细指南:How to use Regular Expressions (Regex) in Microsoft Excel both in-cell and loops
您可以使用的正则表达式可能是:(?:\ s |:| =)。*
即。找到第一个空格或第一个:或第一个=,然后选择之后的所有内容。
答案 1 :(得分:0)
看看这个:
Public Sub RegExpExample()
Dim rng As Range
Dim c As Variant, arr As Variant
Dim k As Long
Dim regEx As Object
Dim Match, Matches
' Uses late binding so no need to add references
Set regEx = CreateObject("VBScript.RegExp")
' Change this to match your range where your values are
With Sheet2
Set rng = .Range(.Cells(1, 1), .Cells(8, 1))
End With
' Declare RegEx parameters
With regEx
.Pattern = "(?:\d*\.)?\d+"
.IgnoreCase = True
.Global = True
End With
' Loop through each row
For Each c In rng
Set Matches = regEx.Execute(c)
If Matches.Count > 0 Then
ReDim arr(1 To Matches.Count)
k = 1
For Each Match In Matches
arr(k) = Match
k = k + 1
Next Match
' Print back to worksheet
Range(c.Offset(0, 1), c.Offset(0, UBound(arr))) = arr
End If
Next c
End Sub
您必须决定如何处理返回的第一列值,或等到RegEx更好的人提出答案