寻求由ggplot 2.2.0破坏的gtable_add_grob代码的解决方法
在具有多个构面变量的图中，ggplot2重复“外部”变量的构面标签，而不是在“内部”变量的所有级别上具有单个跨越构面条带。我有一些代码，我一直使用gtable_add_grob包中的gtable来覆盖重复的外部构面标签，并使用单个跨越小面条。
不幸的是，由于facet strip的grob结构发生了变化，此代码不再适用于ggplot2 2.2.0。具体来说，在ggplot2的早期版本中，facet标签的每一行都有自己的一组grob。但是，在版本2.2.0中，看起来每个facet标签的垂直堆栈都是单个grob。这打破了我的代码，我不知道如何解决它。
这是一个具体的例子，取自an SO question I answered a few months ago：
# Data
df = structure(list(location = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L), .Label = c("SF", "SS"), class = "factor"), species = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c("AGR", "LKA"), class = "factor"),
position = structure(c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L,
1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L), .Label = c("top", "bottom"), class = "factor"), density = c(0.41,
0.41, 0.43, 0.33, 0.35, 0.43, 0.34, 0.46, 0.32, 0.32, 0.4,
0.4, 0.45, 0.34, 0.39, 0.39, 0.31, 0.38, 0.48, 0.3, 0.42,
0.34, 0.35, 0.4, 0.38, 0.42, 0.36, 0.34, 0.46, 0.38, 0.36,
0.39, 0.38, 0.39, 0.39, 0.39, 0.36, 0.39, 0.51, 0.38)), .Names = c("location",
"species", "position", "density"), row.names = c(NA, -40L), class = "data.frame")
# Begin with a regular ggplot with three facet levels
p=ggplot(df, aes("", density)) +
geom_boxplot(width=0.7, position=position_dodge(0.7)) +
theme_bw() +
facet_grid(. ~ species + location + position) +
theme(panel.margin=unit(0,"lines"),
strip.background=element_rect(color="grey30", fill="grey90"),
panel.border=element_rect(color="grey90"),
axis.ticks.x=element_blank()) +
labs(x="")
我们从一个有三个层面的情节开始。
现在我们将覆盖带有跨越条带的顶部两个小平面条带，这样我们就不会有重复的条带标签：
pg = ggplotGrob(p)
# Add spanning strip labels for species
pos = c(4,11)
for (i in 1:2) {
pg <- gtable_add_grob(pg,
list(rectGrob(gp=gpar(col="grey50", fill="grey90")),
textGrob(unique(densityAGRLKA$species)[i],
gp=gpar(cex=0.8))), t=3,l=pos[i],b=3,r=pos[i]+7,
name=c("a","b"))
}
# Add spanning strip labels for location
pos=c(4,7,11,15)
for (i in 1:4) {
pg = gtable_add_grob(pg,
list(rectGrob(gp = gpar(col="grey50", fill="grey90")),
textGrob(rep(unique(densityAGRLKA$location),2)[i],
gp=gpar(cex=0.8))), t=4,l=pos[i],b=4,r=pos[i]+3,
name = c("c","d"))
}
grid.draw(pg)
这是ggplot2 2.1.0的情节：
但是，如果我使用ggplot2 2.2.0尝试相同的代码，我会返回原始图表，不会更改条带标签。看一下原始情节p的grob结构，可以看出为什么会这样。我已经粘贴在这个问题底部的grob表中。为了节省空间，我只包括与小平面条相关的行。
查看cells列，请注意在2.1.0版本的图中，每行中的前两个数字是3,4或5，表示grob相对于该行的垂直位置情节中的其他凹凸不平。在上面的代码中，t的{{1}}和l参数设置为3或4的值，因为这些是我想用跨越条覆盖的小平面条行。
现在查看2.2.0版本中的gtable_add_grob列：请注意，前两个数字始终为6.另请注意，构面条仅包含8个grob而不是24个版本2.1.0。在版本2.2.0中，似乎每个堆栈的三个构面标签现在是单个grob而不是三个单独的grob。因此，即使我将cells中的t和b参数更改为6，也会覆盖所有三个方面条。这是一个例子：
gtable_add_grob 
所以，在那个非常冗长的介绍之后，这是我的问题：如何使用ggplot2版本2.2.0创建跨越小平面条，看起来像我使用ggplot2版本2.1.0使用pg = ggplotGrob(p)
# Add spanning strip labels for species
pos = c(4,11)
for (i in 1:2) {
pg <- gtable_add_grob(pg,
list(rectGrob(gp=gpar(col="grey50", fill="grey90")),
textGrob(unique(densityAGRLKA$species)[i],
gp=gpar(cex=0.8))), t=6,l=pos[i],b=6,r=pos[i]+7,
name=c("a","b"))
}
创建的那些？我希望有一个简单的调整，但如果它需要大手术，那么，这也没关系。
ggplot 2.1.0
gtable_add_grobpg
ggplot2 2.2.0
TableGrob (9 x 19) "layout": 45 grobs
z cells name grob
2 1 ( 3- 3, 4- 4) strip-top absoluteGrob[strip.absoluteGrob.147]
3 2 ( 4- 4, 4- 4) strip-top absoluteGrob[strip.absoluteGrob.195]
4 3 ( 5- 5, 4- 4) strip-top absoluteGrob[strip.absoluteGrob.243]
5 4 ( 3- 3, 6- 6) strip-top absoluteGrob[strip.absoluteGrob.153]
6 5 ( 4- 4, 6- 6) strip-top absoluteGrob[strip.absoluteGrob.201]
7 6 ( 5- 5, 6- 6) strip-top absoluteGrob[strip.absoluteGrob.249]
8 7 ( 3- 3, 8- 8) strip-top absoluteGrob[strip.absoluteGrob.159]
9 8 ( 4- 4, 8- 8) strip-top absoluteGrob[strip.absoluteGrob.207]
10 9 ( 5- 5, 8- 8) strip-top absoluteGrob[strip.absoluteGrob.255]
11 10 ( 3- 3,10-10) strip-top absoluteGrob[strip.absoluteGrob.165]
12 11 ( 4- 4,10-10) strip-top absoluteGrob[strip.absoluteGrob.213]
13 12 ( 5- 5,10-10) strip-top absoluteGrob[strip.absoluteGrob.261]
14 13 ( 3- 3,12-12) strip-top absoluteGrob[strip.absoluteGrob.171]
15 14 ( 4- 4,12-12) strip-top absoluteGrob[strip.absoluteGrob.219]
16 15 ( 5- 5,12-12) strip-top absoluteGrob[strip.absoluteGrob.267]
17 16 ( 3- 3,14-14) strip-top absoluteGrob[strip.absoluteGrob.177]
18 17 ( 4- 4,14-14) strip-top absoluteGrob[strip.absoluteGrob.225]
19 18 ( 5- 5,14-14) strip-top absoluteGrob[strip.absoluteGrob.273]
20 19 ( 3- 3,16-16) strip-top absoluteGrob[strip.absoluteGrob.183]
21 20 ( 4- 4,16-16) strip-top absoluteGrob[strip.absoluteGrob.231]
22 21 ( 5- 5,16-16) strip-top absoluteGrob[strip.absoluteGrob.279]
23 22 ( 3- 3,18-18) strip-top absoluteGrob[strip.absoluteGrob.189]
24 23 ( 4- 4,18-18) strip-top absoluteGrob[strip.absoluteGrob.237]
25 24 ( 5- 5,18-18) strip-top absoluteGrob[strip.absoluteGrob.285]
pg
2 个答案:
答案 0 :(得分：13)
实际上，ggplot2 v2.2.0逐列构造复杂的条带，每列都是一个grob。这可以通过提取一个条带然后检查其结构来检查。使用你的情节：
library(ggplot2)
library(gtable)
library(grid)
# Your data
df = structure(list(location = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L), .Label = c("SF", "SS"), class = "factor"), species = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c("AGR", "LKA"), class = "factor"),
position = structure(c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L,
1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L), .Label = c("top", "bottom"), class = "factor"), density = c(0.41,
0.41, 0.43, 0.33, 0.35, 0.43, 0.34, 0.46, 0.32, 0.32, 0.4,
0.4, 0.45, 0.34, 0.39, 0.39, 0.31, 0.38, 0.48, 0.3, 0.42,
0.34, 0.35, 0.4, 0.38, 0.42, 0.36, 0.34, 0.46, 0.38, 0.36,
0.39, 0.38, 0.39, 0.39, 0.39, 0.36, 0.39, 0.51, 0.38)), .Names = c("location",
"species", "position", "density"), row.names = c(NA, -40L), class = "data.frame")
# Your ggplot with three facet levels
p=ggplot(df, aes("", density)) +
geom_boxplot(width=0.7, position=position_dodge(0.7)) +
theme_bw() +
facet_grid(. ~ species + location + position) +
theme(panel.spacing=unit(0,"lines"),
strip.background=element_rect(color="grey30", fill="grey90"),
panel.border=element_rect(color="grey90"),
axis.ticks.x=element_blank()) +
labs(x="")
# Get the ggplot grob
pg = ggplotGrob(p)
# Get the left most strip
index = which(pg$layout$name == "strip-t-1")
strip1 = pg$grobs[[index]]
# Draw the strip
grid.newpage()
grid.draw(strip1)
# Examine its layout
strip1$layout
gtable_show_layout(strip1)
获得外带条标签的一种粗糙方式是跨越＆＃39;内部标签是从头开始构造条带：
# Get the strips, as a list, from the original plot
strip = list()
for(i in 1:8) {
index = which(pg$layout$name == paste0("strip-t-",i))
strip[[i]] = pg$grobs[[index]]
}
# Construct gtable to contain the new strip
newStrip = gtable(widths = unit(rep(1, 8), "null"), heights = strip[[1]]$heights)
## Populate the gtable
# Top row
for(i in 1:2) {
newStrip = gtable_add_grob(newStrip, strip[[4*i-3]][1],
t = 1, l = 4*i-3, r = 4*i)
}
# Middle row
for(i in 1:4){
newStrip = gtable_add_grob(newStrip, strip[[2*i-1]][2],
t = 2, l = 2*i-1, r = 2*i)
}
# Bottom row
for(i in 1:8) {
newStrip = gtable_add_grob(newStrip, strip[[i]][3],
t = 3, l = i)
}
# Put the strip into the plot
# (It could be better to remove the original strip.
# In this case, with a coloured background, it doesn't matter)
pgNew = gtable_add_grob(pg, newStrip, t = 7, l = 5, r = 19)
# Draw the plot
grid.newpage()
grid.draw(pgNew)
OR 使用vectorised gtable_add_grob（参见评论）：
pg = ggplotGrob(p)
# Get a list of strips from the original plot
strip = lapply(grep("strip-t", pg$layout$name), function(x) {pg$grobs[[x]]})
# Construct gtable to contain the new strip
newStrip = gtable(widths = unit(rep(1, 8), "null"), heights = strip[[1]]$heights)
## Populate the gtable
# Top row
cols = seq(1, by = 4, length.out = 2)
newStrip = gtable_add_grob(newStrip, lapply(strip[cols], `[`, 1), t = 1, l = cols, r = cols + 3)
# Middle row
cols = seq(1, by = 2, length.out = 4)
newStrip = gtable_add_grob(newStrip, lapply(strip[cols], `[`, 2), t = 2, l = cols, r = cols + 1)
# Bottom row
newStrip = gtable_add_grob(newStrip, lapply(strip, `[`, 3), t = 3, l = 1:8)
# Put the strip into the plot
pgNew = gtable_add_grob(pg, newStrip, t = 7, l = 5, r = 19)
# Draw the plot
grid.newpage()
grid.draw(pgNew)
答案 1 :(得分：5)
编辑允许不同宽度的面板（例如scales = "free_x"，space = "free_x"）。
此尝试采用原始ggplot，提取一些信息，然后构造包含重叠条带的新grob。功能不漂亮，但它的工作原理......到目前为止。它需要安装plyr。
library(ggplot2)
library(grid)
library(gtable)
df = structure(list(location = structure(c(1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L), .Label = c("SF", "SS"), class = "factor"), species = structure(c(1L,
1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L, 2L,
2L, 2L, 2L, 2L, 2L, 2L, 2L), .Label = c("AGR", "LKA"), class = "factor"),
position = structure(c(1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L,
1L, 2L, 2L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L,
2L), .Label = c("top", "bottom"), class = "factor"), density = c(0.41,
0.41, 0.43, 0.33, 0.35, 0.43, 0.34, 0.46, 0.32, 0.32, 0.4,
0.4, 0.45, 0.34, 0.39, 0.39, 0.31, 0.38, 0.48, 0.3, 0.42,
0.34, 0.35, 0.4, 0.38, 0.42, 0.36, 0.34, 0.46, 0.38, 0.36,
0.39, 0.38, 0.39, 0.39, 0.39, 0.36, 0.39, 0.51, 0.38)), .Names = c("location",
"species", "position", "density"), row.names = c(NA, -40L), class = "data.frame")
# Begin with a regular ggplot with three facet levels
p=ggplot(df, aes("", density)) +
geom_boxplot(width=0.7, position=position_dodge(0.7)) +
theme_bw() +
facet_grid(. ~ species + location + position) +
theme(panel.spacing=unit(0,"lines"),
strip.background=element_rect(color="grey30", fill="grey90"),
panel.border=element_rect(color="grey90"),
axis.ticks.x=element_blank()) +
labs(x="")
## The function to get overlapping strip labels
OverlappingStripLabels = function(plot) {
# Get the ggplot grob
g = ggplotGrob(plot)
### Collect some information about the strips from the plot
# Get a list of strips
strip = lapply(grep("strip-t", g$layout$name), function(x) {g$grobs[[x]]})
# Number of strips
NumberOfStrips = sum(grepl(pattern = "strip-t", g$layout$name))
# Number of rows
NumberOfRows = length(strip[[1]])
# Panel spacing and it's unit
plot_theme <- function(p) {
plyr::defaults(p$theme, theme_get())
}
PanelSpacing = plot_theme(plot)$panel.spacing
unit = attr(PanelSpacing, "unit")
# Map the boundaries of the new strips
Nlabel = vector("list", NumberOfRows)
map = vector("list", NumberOfRows)
for(i in 1:NumberOfRows) {
for(j in 1:NumberOfStrips) {
Nlabel[[i]][j] = getGrob(grid.force(strip[[j]][i]), gPath("GRID.text"), grep = TRUE)$label
}
map[[i]][1] = TRUE
for(j in 2:NumberOfStrips) {
map[[i]][j] = Nlabel[[i]][j] != Nlabel[[i]][j-1]
}
}
## Construct gtable to contain the new strip
# Set the widths of the strips, based on widths of the panels and PanelSpacing
panel = subset(g$layout, grepl("panel", g$layout$name), l, drop = TRUE)
StripWidth = list()
for(i in seq_along(panel)) StripWidth[[i]] = unit.c(g$width[panel[i]], PanelSpacing)
newStrip = gtable(widths = unit.c(unit(unlist(StripWidth), c("null", unit)))[-2*NumberOfStrips],
heights = strip[[1]]$heights)
## Populate the gtable
seqLeft = list()
for(i in 1:NumberOfRows) {
Left = which(map[[i]] == TRUE)
seqLeft[[i]] = if((i-1) < 1) 2*Left - 1 else sort(unique(c(seqLeft[[i-1]], 2*Left - 1)))
seqRight = c(seqLeft[[i]][-1] -2, (2*NumberOfStrips-1))
newStrip = gtable_add_grob(newStrip, lapply(strip[(seqLeft[[i]]+1)/2], `[`, i), t = i, l = seqLeft[[i]], r = seqRight)
}
## Put the strip into the plot
# Get the locations of the original strips
pos = subset(g$layout, grepl("strip-t", g$layout$name), t:r)
## Use these to position the new strip
pgNew = gtable_add_grob(g, newStrip, t = unique(pos$t), l = min(pos$l), r = max(pos$r))
return(pgNew)
}
## Draw the plot
grid.newpage()
grid.draw(OverlappingStripLabels(p))
打破这个功能可能不会太困难，但我在数据上尝试过，因为行的排序不是那么均匀。
p1 = ggplot(mtcars, aes("", hp)) +
geom_boxplot(width=0.7, position=position_dodge(0.7)) +
theme_bw() +
facet_grid(. ~ vs + am + carb, labeller = label_both) +
theme(panel.spacing=unit(0.2,"lines"),
strip.background=element_rect(color="grey30", fill="grey90"),
panel.border=element_rect(color="grey90"),
axis.ticks.x=element_blank()) +
labs(x="")
grid.draw(OverlappingStripLabels(p1))
p2 = ggplot(mtcars, aes("", hp)) +
geom_boxplot(width=0.7, position=position_dodge(0.7)) +
theme_bw() +
facet_grid(. ~ vs + carb + am, labeller = label_both) +
theme(panel.spacing=unit(0.2,"lines"),
strip.background=element_rect(color="grey30", fill="grey90"),
panel.border=element_rect(color="grey90"),
axis.ticks.x=element_blank()) +
labs(x="")
grid.draw(OverlappingStripLabels(p2))
df = structure(list(id = 1:19,
category1 = c("X", "X", "X", "X", "X", "X", "X", "X", "X", "Y", "Y", "Y", "Y", "Y", "Y", "Y", "Y", "Y", "Y"),
category2 = c(21L, 21L, 21L, 22L, 22L, 22L, 22L, 22L, 22L, 23L, 23L, 23L, 24L, 24L, 24L, 25L, 25L, 26L, 26L),
category3 = c("C1", "C2", "C3", "D1", "D2", "D3", "D5", "D6", "D7", "E1", "E2", "E3", "F1", "F2", "F3", "G1", "G2", "H1", "H2"),
freq = c(4L, 7L, 4L, 28L, 20L, 0L, 1L, 4L, 1L, 17L, 33L, 31L, 20L, 20L, 21L, 15L, 18L, 12L, 13L)),
.Names = c("id", "category1", "category2", "category3", "freq"), class = "data.frame", row.names = c(NA, -19L))
p3 = ggplot(df, aes(category3, freq)) +
geom_bar(stat = "identity") +
facet_grid(. ~ category1 + category2, scale = "free_x", space = "free_x")
grid.draw(OverlappingStripLabels(p3))
相关问题
最新问题
- 我写了这段代码，但我无法理解我的错误
- 我无法从一个代码实例的列表中删除 None 值，但我可以在另一个实例中。为什么它适用于一个细分市场而不适用于另一个细分市场？
- 是否有可能使 loadstring 不可能等于打印？卢阿
- java中的random.expovariate()
- Appscript 通过会议在 Google 日历中发送电子邮件和创建活动
- 为什么我的 Onclick 箭头功能在 React 中不起作用？
- 在此代码中是否有使用“this”的替代方法？
- 在 SQL Server 和 PostgreSQL 上查询，我如何从第一个表获得第二个表的可视化
- 每千个数字得到
- 更新了城市边界 KML 文件的来源？