请帮忙:如何在Excel VBA代码编辑器中打开行号?我使用的是Excel 2013版本。
谢谢。
答案 0 :(得分:6)
这是我在VBE IDE中添加行号的代码。它是Excel MVP mikerickson提供的here解决方案的改进。我已经解决了这个问题,因为在我遇到过的极少数情况下,VBE无法进入调试模式,例如在代码中有.ReplaceLine方法时。实际上,一旦执行它就无法进入调试模式,因此Erl可能对调试很有用(而不是Debug.Print)。我添加了几个功能,例如:
- 可以将行号添加为标签:
10: Dim foo as bar
或通过标签从代码中分隔的单个数字:10 Dim foo as bar
- 可以将行号添加到过程语句的结尾,并将过程声明行的缩进与numberered的End语句行匹配。或者没有。
- 是否可以为空行添加行号
- [WIP]可以将行号添加到模块中的特定过程
- [WIP]匹配代码行的所有缩进与行号以匹配缩进的最后一行的缩进。如果最后一行为
200: End Sub
,则行30: With ActiveSheet
将重新缩进为30: ActiveSheet
- [WIP]添加VBE IDE命令直接以当前模块/ proc作为参数进行调用
Public Enum vbLineNumbers_LabelTypes
vbLabelColon ' 0
vbLabelTab ' 1
End Enum
Public Enum vbLineNumbers_ScopeToAddLineNumbersTo
vbScopeAllProc ' 1
vbScopeThisProc ' 2
End Enum
Sub AddLineNumbers(ByVal wbName As String, _
ByVal vbCompName As String, _
ByVal LabelType As vbLineNumbers_LabelTypes, _
ByVal AddLineNumbersToEmptyLines As Boolean, _
ByVal AddLineNumbersToEndOfProc As Boolean, _
ByVal Scope As vbLineNumbers_ScopeToAddLineNumbersTo, _
Optional ByVal thisProcName As String)
' USAGE RULES
' DO NOT MIX LABEL TYPES FOR LINE NUMBERS! IF ADDING LINE NUMBERS AS COLON TYPE, ANY LINE NUMBERS AS VBTAB TYPE MUST BE REMOVE BEFORE, AND RECIPROCALLY ADDING LINE NUMBERS AS VBTAB TYPE
Dim i As Long
Dim j As Long
Dim procName As String
Dim startOfProcedure As Long
Dim lengthOfProcedure As Long
Dim endOfProcedure As Long
Dim strLine As String
With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
.CodePane.Window.Visible = False
If Scope = vbScopeAllProc Then
For i = 1 To .CountOfLines
strLine = .Lines(i, 1)
procName = .ProcOfLine(i, vbext_pk_Proc) ' Type d'argument ByRef incompatible ~~> Requires VBIDE library as a Reference for the VBA Project
If procName <> vbNullString Then
startOfProcedure = .ProcStartLine(procName, vbext_pk_Proc)
bodyOfProcedure = .ProcBodyLine(procName, vbext_pk_Proc)
countOfProcedure = .ProcCountLines(procName, vbext_pk_Proc)
prelinesOfProcedure = bodyOfProcedure - startOfProcedure
'postlineOfProcedure = ??? not directly available since endOfProcedure is itself not directly available.
lengthOfProcedure = countOfProcedure - prelinesOfProcedure ' includes postlinesOfProcedure !
'endOfProcedure = ??? not directly available, each line of the proc must be tested until the End statement is reached. See below.
If endOfProcedure <> 0 And startOfProcedure < endOfProcedure And i > endOfProcedure Then
GoTo NextLine
End If
If i = bodyOfProcedure Then InProcBodyLines = True
If bodyOfProcedure < i And i < startOfProcedure + countOfProcedure Then
If Not (.Lines(i - 1, 1) Like "* _") Then
InProcBodyLines = False
PreviousIndentAdded = 0
If Trim(strLine) = "" And Not AddLineNumbersToEmptyLines Then GoTo NextLine
If IsProcEndLine(wbName, vbCompName, i) Then
endOfProcedure = i
If AddLineNumbersToEndOfProc Then
Call IndentProcBodyLinesAsProcEndLine(wbName, vbCompName, LabelType, endOfProcedure)
Else
GoTo NextLine
End If
End If
If LabelType = vbLabelColon Then
If HasLabel(strLine, vbLabelColon) Then strLine = RemoveOneLineNumber(.Lines(i, 1), vbLabelColon)
If Not HasLabel(strLine, vbLabelColon) Then
temp_strLine = strLine
.ReplaceLine i, CStr(i) & ":" & strLine
new_strLine = .Lines(i, 1)
If Len(new_strLine) = Len(CStr(i) & ":" & temp_strLine) Then
PreviousIndentAdded = Len(CStr(i) & ":")
Else
PreviousIndentAdded = Len(CStr(i) & ": ")
End If
End If
ElseIf LabelType = vbLabelTab Then
If Not HasLabel(strLine, vbLabelTab) Then strLine = RemoveOneLineNumber(.Lines(i, 1), vbLabelTab)
If Not HasLabel(strLine, vbLabelColon) Then
temp_strLine = strLine
.ReplaceLine i, CStr(i) & vbTab & strLine
PreviousIndentAdded = Len(strLine) - Len(temp_strLine)
End If
End If
Else
If Not InProcBodyLines Then
If LabelType = vbLabelColon Then
.ReplaceLine i, Space(PreviousIndentAdded) & strLine
ElseIf LabelType = vbLabelTab Then
.ReplaceLine i, Space(4) & strLine
End If
Else
End If
End If
End If
End If
NextLine:
Next i
ElseIf AddLineNumbersToEmptyLines And Scope = vbScopeThisProc Then
End If
.CodePane.Window.Visible = True
End With
End Sub
Function IsProcEndLine(ByVal wbName As String, _
ByVal vbCompName As String, _
ByVal Line As Long) As Boolean
With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
If Trim(.Lines(Line, 1)) Like "End Sub*" _
Or Trim(.Lines(Line, 1)) Like "End Function*" _
Or Trim(.Lines(Line, 1)) Like "End Property*" _
Then IsProcEndLine = True
End With
End Function
Sub IndentProcBodyLinesAsProcEndLine(ByVal wbName As String, ByVal vbCompName As String, ByVal LabelType As vbLineNumbers_LabelTypes, ByVal ProcEndLine As Long)
Dim procName As String
Dim startOfProcedure As Long
Dim endOfProcedure As Long
With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
procName = .ProcOfLine(ProcEndLine, vbext_pk_Proc)
bodyOfProcedure = .ProcBodyLine(procName, vbext_pk_Proc)
endOfProcedure = ProcEndLine
strEnd = .Lines(endOfProcedure, 1)
j = bodyOfProcedure
Do Until Not .Lines(j - 1, 1) Like "* _" And j <> bodyOfProcedure
strLine = .Lines(j, 1)
If LabelType = vbLabelColon Then
If Mid(strEnd, Len(CStr(endOfProcedure)) + 1 + 1 + 1, 1) = " " Then
.ReplaceLine j, Space(Len(CStr(endOfProcedure)) + 1) & strLine
Else
.ReplaceLine j, Space(Len(CStr(endOfProcedure)) + 2) & strLine
End If
ElseIf LabelType = vbLabelTab Then
If endOfProcedure < 1000 Then
.ReplaceLine j, Space(4) & strLine
Else
Debug.Print "This tool is limited to 999 lines of code to work properly."
End If
End If
j = j + 1
Loop
End With
End Sub
Sub RemoveLineNumbers(ByVal wbName As String, ByVal vbCompName As String, ByVal LabelType As vbLineNumbers_LabelTypes)
Dim i As Long
With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
For i = 1 To .CountOfLines
procName = .ProcOfLine(i, vbext_pk_Proc)
If procName <> vbNullString Then
If i = .ProcBodyLine(procName, vbext_pk_Proc) Then InProcBodyLines = True
LenghtBefore = Len(.Lines(i, 1))
If Not .Lines(i - 1, 1) Like "* _" Then
InProcBodyLines = False
.ReplaceLine i, RemoveOneLineNumber(.Lines(i, 1), LabelType)
Else
If IsInProcBodyLines Then
' do nothing
Else
.ReplaceLine i, Mid(.Lines(i, 1), RemovedChars_previous_i + 1)
End If
End If
LenghtAfter = Len(.Lines(i, 1))
LengthBefore_previous_i = LenghtBefore
LenghtAfter_previous_i = LenghtAfter
RemovedChars_previous_i = LengthBefore_previous_i - LenghtAfter_previous_i
If Trim(.Lines(i, 1)) Like "End Sub*" Or Trim(.Lines(i, 1)) Like "End Function" Or Trim(.Lines(i, 1)) Like "End Property" Then
LenOfRemovedLeadingCharacters = LenghtBefore - LenghtAfter
procName = .ProcOfLine(i, vbext_pk_Proc)
bodyOfProcedure = .ProcBodyLine(procName, vbext_pk_Proc)
j = bodyOfProcedure
strLineBodyOfProc = .Lines(bodyOfProcedure, 1)
Do Until Not strLineBodyOfProc Like "* _"
j = j + 1
strLineBodyOfProc = .Lines(j, 1)
Loop
LastLineBodyOfProc = j
strLastLineBodyOfProc = strLineBodyOfProc
strLineEndOfProc = .Lines(i, 1)
For k = bodyOfProcedure To j
.ReplaceLine k, Mid(.Lines(k, 1), 1 + LenOfRemovedLeadingCharacters)
Next k
i = i + (j - bodyOfProcedure)
GoTo NextLine
End If
Else
' GoTo NextLine
End If
NextLine:
Next i
End With
End Sub
Function RemoveOneLineNumber(ByVal aString As String, ByVal LabelType As vbLineNumbers_LabelTypes)
RemoveOneLineNumber = aString
If LabelType = vbLabelColon Then
If aString Like "#:*" Or aString Like "##:*" Or aString Like "###:*" Then
RemoveOneLineNumber = Mid(aString, 1 + InStr(1, aString, ":", vbTextCompare))
If Left(RemoveOneLineNumber, 2) Like " [! ]*" Then RemoveOneLineNumber = Mid(RemoveOneLineNumber, 2)
End If
ElseIf LabelType = vbLabelTab Then
If aString Like "# *" Or aString Like "## *" Or aString Like "### *" Then RemoveOneLineNumber = Mid(aString, 5)
If aString Like "#" Or aString Like "##" Or aString Like "###" Then RemoveOneLineNumber = ""
End If
End Function
Function HasLabel(ByVal aString As String, ByVal LabelType As vbLineNumbers_LabelTypes) As Boolean
If LabelType = vbLabelColon Then HasLabel = InStr(1, aString & ":", ":") < InStr(1, aString & " ", " ")
If LabelType = vbLabelTab Then
HasLabel = Mid(aString, 1, 4) Like "# " Or Mid(aString, 1, 4) Like "## " Or Mid(aString, 1, 4) Like "### "
End If
End Function
Function RemoveLeadingSpaces(ByVal aString As String) As String
Do Until Left(aString, 1) <> " "
aString = Mid(aString, 2)
Loop
RemoveLeadingSpaces = aString
End Function
Function WhatIsLineIndent(ByVal aString As String) As String
i = 1
Do Until Mid(aString, i, 1) <> " "
i = i + 1
Loop
WhatIsLineIndent = i
End Function
Function HowManyLeadingSpaces(ByVal aString As String) As String
HowManyLeadingSpaces = WhatIsLineIndent(aString) - 1
End Function
你可以这样打电话:
Sub AddLineNumbers_vbLabelColon()
AddLineNumbers wbName:="EvaluateCall.xlsm", vbCompName:="ModLineNumbers_testDest", LabelType:=vbLabelColon, AddLineNumbersToEmptyLines:=True, AddLineNumbersToEndOfProc:=True, Scope:=vbScopeAllProc
End Sub
Sub AddLineNumbers_vbLabelTab()
AddLineNumbers wbName:="EvaluateCall.xlsm", vbCompName:="ModLineNumbers_testDest", LabelType:=vbLabelTab, AddLineNumbersToEmptyLines:=True, AddLineNumbersToEndOfProc:=True, Scope:=vbScopeAllProc
End Sub
Sub RemoveLineNumbers_vbLabelColon()
RemoveLineNumbers wbName:="EvaluateCall.xlsm", vbCompName:="ModLineNumbers_testDest", LabelType:=vbLabelColon
End Sub
Sub RemoveLineNumbers_vbLabelTab()
RemoveLineNumbers wbName:="EvaluateCall.xlsm", vbCompName:="ModLineNumbers_testDest", LabelType:=vbLabelTab
End Sub
作为提醒,这里有一些关于行号的编译规则:
答案 1 :(得分:0)
简短回答,尚未在2013年尝试过。
做一次:
Module2
中的大代码粘贴到工作簿中的此答案中。Module3
的代码。Module4
的代码。Global allow_for_line_addition As String
行,这样您就可以自动添加每个第一行上方/的内容
模块。end sub
,end function
或End Property
之后不会输入任何内容。每次修改代码时都会这样做:
Module3
的代码,以删除工作簿中所有模块的行号。Module4
的代码,为工作簿中的所有模块添加行号。 (*因为有时候如果你剪掉线或移动它们会出现错误(例如将line 2440:
放在line 2303:
之上)。通过删除并重新添加它们,行编号会自动更正再次)
长答案(包括学习步骤和尝试) - 对我而言,实施hymced的答案并不简单,因此我记录了在VBA代码中为行模块添加行号所需的步骤编辑器(*并再次删除它们)。我按照以下步骤使其正常工作。
Module2
,并将第二个代码复制到临时 Module3
。然后将临时 Module3
中第二个代码的第一行修改为:
AddLineNumbers wbName:="Book1.xlsm", vbCompName:="Module1", LabelType:=vbLabelColon, AddLineNumbersToEmptyLines:=True, AddLineNumbersToEndOfProc:=True, Scope:=vbScopeAllProc
我收到了错误:
procName = .ProcOfLine(i, vbext_pk_Proc) ` Type d`argument ByRef incompatible ~~> Requires VBIDE library as a Reference for the VBA Project
所以我读到我必须启用VBIDE库。
所以我停止了代码,点击了工具&gt;引用,找不到VBIDE库。
在this forum上,我发现通过添加引用来启用VBIDE VBA可扩展性库:
单击VBE中的Tools-References,然后向下滚动并勾选 Microsoft Visual Basic for Applications可扩展性5.3。
的条目
所以在这样做之后,第一个错误消失了,它没有突出显示任何一行但却给出了错误&#34;无效的过程调用或参数&#34;。
由于我仍然不确定vbCompName,我认为可能需要知道sub而不是模块,所以我尝试修改临时 {{1转到:
Module3
突出了这一行:
AddLineNumbers wbName:="Book1.xlsm", vbCompName:="learn", LabelType:=vbLabelColon, AddLineNumbersToEmptyLines:=True, AddLineNumbersToEndOfProc:=True, Scope:=vbScopeAllProc
说:With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
。 (所以我也尝试过:subscript out of range
和Module1.learn
,产生Module1:learn
- 错误。
事实证明,
subscript out of range
如果要提供行号的子号位于名为AddLineNumbers wbName:="Book1.xlsm", vbCompName:="Module1", LabelType:=vbLabelColon, AddLineNumbersToEmptyLines:=True, AddLineNumbersToEndOfProc:=True, Scope:=vbScopeAllProc
的模块中,则是调用替换子的正确方法。第一个错误描述发生,但它确实将行号添加到代码中(包含Module1
的第一行和包含sub ...
的最后一行除外。在名为end sub
的{{1}}中进行了测试名为Module1
的excel 2016工作簿。完整性sub learn()
包括:
Book1.xlsm
然而,在回来的路上,删除行号,它产生了一个错误,因为它询问了learn
中Sub learn()
ThisWorkbook.Worksheets("Sheet1").Activate
Range("A1").Activate
Range("A1").Select
Range("A1").Value = Range("A1").Value + 1
End Sub
的.lines(0,1)
所以我将其修改为排除.lines(0,1),方法是将更改后的代码放入 final procName
:
Sub AddLineNumbers...
使用下面的代码调用Module2
上的替换,粘贴在临时 Public Enum vbLineNumbers_LabelTypes
vbLabelColon ' 0
vbLabelTab ' 1
End Enum
Public Enum vbLineNumbers_ScopeToAddLineNumbersTo
vbScopeAllProc ' 1
vbScopeThisProc ' 2
End Enum
Sub AddLineNumbers(ByVal wbName As String, _
ByVal vbCompName As String, _
ByVal LabelType As vbLineNumbers_LabelTypes, _
ByVal AddLineNumbersToEmptyLines As Boolean, _
ByVal AddLineNumbersToEndOfProc As Boolean, _
ByVal Scope As vbLineNumbers_ScopeToAddLineNumbersTo, _
Optional ByVal thisProcName As String)
' USAGE RULES
' DO NOT MIX LABEL TYPES FOR LINE NUMBERS! IF ADDING LINE NUMBERS AS COLON TYPE, ANY LINE NUMBERS AS VBTAB TYPE MUST BE REMOVE BEFORE, AND RECIPROCALLY ADDING LINE NUMBERS AS VBTAB TYPE
Dim i As Long
Dim j As Long
Dim procName As String
Dim startOfProcedure As Long
Dim lengthOfProcedure As Long
Dim endOfProcedure As Long
Dim strLine As String
With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
.CodePane.Window.Visible = False
If Scope = vbScopeAllProc Then
For i = 1 To .CountOfLines - 1
strLine = .Lines(i, 1)
procName = .ProcOfLine(i, vbext_pk_Proc) ' Type d'argument ByRef incompatible ~~> Requires VBIDE library as a Reference for the VBA Project
If procName <> vbNullString Then
startOfProcedure = .ProcStartLine(procName, vbext_pk_Proc)
bodyOfProcedure = .ProcBodyLine(procName, vbext_pk_Proc)
countOfProcedure = .ProcCountLines(procName, vbext_pk_Proc)
prelinesOfProcedure = bodyOfProcedure - startOfProcedure
'postlineOfProcedure = ??? not directly available since endOfProcedure is itself not directly available.
lengthOfProcedure = countOfProcedure - prelinesOfProcedure ' includes postlinesOfProcedure !
'endOfProcedure = ??? not directly available, each line of the proc must be tested until the End statement is reached. See below.
If endOfProcedure <> 0 And startOfProcedure < endOfProcedure And i > endOfProcedure Then
GoTo NextLine
End If
If i = bodyOfProcedure Then inprocbodylines = True
If bodyOfProcedure < i And i < startOfProcedure + countOfProcedure Then
If Not (.Lines(i - 1, 1) Like "* _") Then
inprocbodylines = False
PreviousIndentAdded = 0
If Trim(strLine) = "" And Not AddLineNumbersToEmptyLines Then GoTo NextLine
If IsProcEndLine(wbName, vbCompName, i) Then
endOfProcedure = i
If AddLineNumbersToEndOfProc Then
Call IndentProcBodyLinesAsProcEndLine(wbName, vbCompName, LabelType, endOfProcedure)
Else
GoTo NextLine
End If
End If
If LabelType = vbLabelColon Then
If HasLabel(strLine, vbLabelColon) Then strLine = RemoveOneLineNumber(.Lines(i, 1), vbLabelColon)
If Not HasLabel(strLine, vbLabelColon) Then
temp_strLine = strLine
.ReplaceLine i, CStr(i) & ":" & strLine
new_strLine = .Lines(i, 1)
If Len(new_strLine) = Len(CStr(i) & ":" & temp_strLine) Then
PreviousIndentAdded = Len(CStr(i) & ":")
Else
PreviousIndentAdded = Len(CStr(i) & ": ")
End If
End If
ElseIf LabelType = vbLabelTab Then
If Not HasLabel(strLine, vbLabelTab) Then strLine = RemoveOneLineNumber(.Lines(i, 1), vbLabelTab)
If Not HasLabel(strLine, vbLabelColon) Then
temp_strLine = strLine
.ReplaceLine i, CStr(i) & vbTab & strLine
PreviousIndentAdded = Len(strLine) - Len(temp_strLine)
End If
End If
Else
If Not inprocbodylines Then
If LabelType = vbLabelColon Then
.ReplaceLine i, Space(PreviousIndentAdded) & strLine
ElseIf LabelType = vbLabelTab Then
.ReplaceLine i, Space(4) & strLine
End If
Else
End If
End If
End If
End If
NextLine:
Next i
ElseIf AddLineNumbersToEmptyLines And Scope = vbScopeThisProc Then
End If
.CodePane.Window.Visible = True
End With
End Sub
Function IsProcEndLine(ByVal wbName As String, _
ByVal vbCompName As String, _
ByVal Line As Long) As Boolean
With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
If Trim(.Lines(Line, 1)) Like "End Sub*" _
Or Trim(.Lines(Line, 1)) Like "End Function*" _
Or Trim(.Lines(Line, 1)) Like "End Property*" _
Then IsProcEndLine = True
End With
End Function
Sub IndentProcBodyLinesAsProcEndLine(ByVal wbName As String, ByVal vbCompName As String, ByVal LabelType As vbLineNumbers_LabelTypes, ByVal ProcEndLine As Long)
Dim procName As String
Dim startOfProcedure As Long
Dim endOfProcedure As Long
With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
procName = .ProcOfLine(ProcEndLine, vbext_pk_Proc)
bodyOfProcedure = .ProcBodyLine(procName, vbext_pk_Proc)
endOfProcedure = ProcEndLine
strEnd = .Lines(endOfProcedure, 1)
j = bodyOfProcedure
Do Until Not .Lines(j - 1, 1) Like "* _" And j <> bodyOfProcedure
strLine = .Lines(j, 1)
If LabelType = vbLabelColon Then
If Mid(strEnd, Len(CStr(endOfProcedure)) + 1 + 1 + 1, 1) = " " Then
.ReplaceLine j, Space(Len(CStr(endOfProcedure)) + 1) & strLine
Else
.ReplaceLine j, Space(Len(CStr(endOfProcedure)) + 2) & strLine
End If
ElseIf LabelType = vbLabelTab Then
If endOfProcedure < 1000 Then
.ReplaceLine j, Space(4) & strLine
Else
Debug.Print "This tool is limited to 999 lines of code to work properly."
End If
End If
j = j + 1
Loop
End With
End Sub
Sub RemoveLineNumbers(ByVal wbName As String, ByVal vbCompName As String, ByVal LabelType As vbLineNumbers_LabelTypes)
Dim i As Long
With Workbooks(wbName).VBProject.VBComponents(vbCompName).CodeModule
'MsgBox ("nr of lines = " & .CountOfLines & vbNewLine & "Procname = " & procName)
'MsgBox ("nr of lines REMEMBER MUST BE LARGER THAN 7! = " & .CountOfLines)
For i = 1 To .CountOfLines
procName = .ProcOfLine(i, vbext_pk_Proc)
If procName <> vbNullString Then
If i > 1 Then
'MsgBox ("Line " & i & " is a body line " & .ProcBodyLine(procName, vbext_pk_Proc))
If i = .ProcBodyLine(procName, vbext_pk_Proc) Then inprocbodylines = True
If .Lines(i - 1, 1) <> "" Then
'MsgBox (.Lines(i - 1, 1))
End If
If Not .Lines(i - 1, 1) Like "* _" Then
'MsgBox (inprocbodylines)
inprocbodylines = False
'MsgBox ("recoginized a line that should be substituted: " & i)
'MsgBox ("about to replace " & .Lines(i, 1) & vbNewLine & " with: " & RemoveOneLineNumber(.Lines(i, 1), LabelType) & vbNewLine & " with label type: " & LabelType)
.ReplaceLine i, RemoveOneLineNumber(.Lines(i, 1), LabelType)
Else
If IsInProcBodyLines Then
' do nothing
'MsgBox (i)
Else
.ReplaceLine i, Mid(.Lines(i, 1), RemovedChars_previous_i + 1)
End If
End If
End If
Else
' GoTo NextLine
End If
NextLine:
Next i
End With
End Sub
Function RemoveOneLineNumber(ByVal aString As String, ByVal LabelType As vbLineNumbers_LabelTypes)
RemoveOneLineNumber = aString
If LabelType = vbLabelColon Then
If aString Like "#:*" Or aString Like "##:*" Or aString Like "###:*" Or aString Like "####:*" Then
RemoveOneLineNumber = Mid(aString, 1 + InStr(1, aString, ":", vbTextCompare))
If Left(RemoveOneLineNumber, 2) Like " [! ]*" Then RemoveOneLineNumber = Mid(RemoveOneLineNumber, 2)
End If
ElseIf LabelType = vbLabelTab Then
If aString Like "# *" Or aString Like "## *" Or aString Like "### *" Or aString Like "#### *" Then RemoveOneLineNumber = Mid(aString, 5)
If aString Like "#" Or aString Like "##" Or aString Like "###" Or aString Like "####" Then RemoveOneLineNumber = ""
End If
End Function
Function HasLabel(ByVal aString As String, ByVal LabelType As vbLineNumbers_LabelTypes) As Boolean
If LabelType = vbLabelColon Then HasLabel = InStr(1, aString & ":", ":") < InStr(1, aString & " ", " ")
If LabelType = vbLabelTab Then
HasLabel = Mid(aString, 1, 4) Like "# " Or Mid(aString, 1, 4) Like "## " Or Mid(aString, 1, 4) Like "### " Or Mid(aString, 1, 5) Like "#### "
End If
End Function
Function RemoveLeadingSpaces(ByVal aString As String) As String
Do Until Left(aString, 1) <> " "
aString = Mid(aString, 2)
Loop
RemoveLeadingSpaces = aString
End Function
Function WhatIsLineIndent(ByVal aString As String) As String
i = 1
Do Until Mid(aString, i, 1) <> " "
i = i + 1
Loop
WhatIsLineIndent = i
End Function
Function HowManyLeadingSpaces(ByVal aString As String) As String
HowManyLeadingSpaces = WhatIsLineIndent(aString) - 1
End Function
中
sub learn()
现在它可以工作(添加和删除行号,所有4种方法都可以调用在临时 module3
中添加/删除行号来为模块中的单个子目录添加/删除行号在示例案例中 Sub AddLineNumbers_vbLabelColon()
AddLineNumbers wbName:="Book1.xlsm", vbCompName:="Module1", LabelType:=vbLabelColon, AddLineNumbersToEmptyLines:=True, AddLineNumbersToEndOfProc:=True, Scope:=vbscopeallproc
End Sub
Sub AddLineNumbers_vbLabelTab()
AddLineNumbers wbName:="Book1.xlsm", vbCompName:="Module1", LabelType:=vbLabelTab, AddLineNumbersToEmptyLines:=True, AddLineNumbersToEndOfProc:=True, Scope:=vbscopeallproc
End Sub
Sub RemoveLineNumbers_vbLabelColon()
RemoveLineNumbers wbName:="Book1.xlsm", vbCompName:="Module1", LabelType:=vbLabelColon
End Sub
Sub RemoveLineNumbers_vbLabelTab()
RemoveLineNumbers wbName:="Book1.xlsm", vbCompName:="Module1", LabelType:=vbLabelTab
End Sub
。所以我试图在同一个模块中放置2个子组件。在这种情况下,代码没有将添加行号更改为第二个子组件。
所以我在module2
上面添加了以下一行:
module1
使Module1
看起来像:
Global allow_for_line_addition As String
现在它将行号添加到整个模块,但它没有从整个模块中删除行号,因此我编辑了hymced Module1
Module2`的删除代码。
注意:如果在子或函数结束后有空白行,则每次运行脚本时都会添加白线以添加行号(在第一次运行后,只需更新行号) )。这些空行号在执行代码时会导致错误,因此您应该删除它们一次。如果sub的末尾没有空行,则此代码也不会添加新行。
要为工作簿中的所有模块添加行号,请在修改它时将长代码保留在最终 Global allow_for_line_addition As String
Sub learn()
ThisWorkbook.Worksheets("Sheet1").Activate
Range("A1").Activate
Range("A1").Select
Range("A1").Value = Range("A1").Value + 1
End Sub
Sub learn2()
ThisWorkbook.Worksheets("Sheet1").Activate
Range("A1").Activate
Range("A1").Select
Range("A1").Value = Range("A1").Value + 1
End Sub
中并替换临时代码 s answer as well and already put it in the long code of **final**
最终 Module2
:
Module3
并将以下代码添加到最终 Module3
:
Global allow_for_line_addition As String 'this is just so that you can automatically add linenumbers
Sub remove_line_numbering_all_modules()
'source: https://stackoverflow.com/questions/36791473/vba-getting-the-modules-in-workbook
'This code numbers all the modules in your .xlsm
Dim vbcomp As VBComponent
Dim modules As Collection
Set modules = New Collection
For Each vbcomp In ThisWorkbook.VBProject.VBComponents
'if normal or class module
If ((vbcomp.Type = vbext_ct_StdModule) Or (vbcomp.Type = vbext_ct_ClassModule)) Then
'V0:
RemoveLineNumbers wbName:=ThisWorkbook.name, vbCompName:=vbcomp.name, LabelType:=vbLabelColon
'V1:
'Call RemoveLineNumbers(ThisWorkbook.name, vbcomp.name)
End If
Next vbcomp
End Sub
您可以将Module4
替换为您自己的工作簿的名称,或者使用Global allow_for_line_addition As String 'this is just so that you can automatically add linenumbers
'This sub adds line numbers to all the modules after you have added the following line to every module
'add tools references microsoft visual basic for applications (5.3) as checked
'Source httpsstackoverflow.comquestions40731182excel-vba-how-to-turn-on-line-numbers-in-code-editor50368332#50368332
Sub add_line_numbering_all_modules()
'source: https://www.stackoverflow.com/questions/36791473/vba-getting-the-modules-in-workbook
'This code numbers all the modules in your .xlsm
Dim vbcomp As VBComponent
Dim modules As Collection
Set modules = New Collection
For Each vbcomp In ThisWorkbook.VBProject.VBComponents
'if normal or class module
If ((vbcomp.Type = vbext_ct_StdModule) Or (vbcomp.Type = vbext_ct_ClassModule)) Then
'V0:
Call AddLineNumbers(ThisWorkbook.name, vbcomp.name, vbLabelColon, True, True, vbScopeAllProc)
'v1
'Call AddLineNumbers(ThisWorkbook.name, vbcomp.name)
End If
Next vbcomp
End Sub
替换(注意不是&#34;&#34;),反之亦然。