我需要以下列XML格式从表中导出数据:
<studentid="000011111">
<academic_goal type="official">
<program_group>
<program type="catalog">2014-16</program>
<program type="degree">BS</program>
<program type="major">PS</program>
<program type="concentration">PCC</program>
</program_group>
<program_group>
<program type="catalog">2014-16</program>
<program type="degree">BS</program>
<program type="minor">HI</program>
</program_group>
</academic_goal>
</studentid>
到目前为止我所拥有的是:
<studentid="000011111">
<academic_goal type="official">
<program_group>
<program type="catalog">2014-16</program>
<program type="degree">BS</program>
<program type="major">PS</program>
<program type="minor">HI</program>
<program type="concentration">PCC</program>
</program_group>
</academic_goal>
</studentid>
如何循环显示此信息,以便未成年人在自己的program_group
标记内(以及目录和学位)?
这是表结构:
CREATE TABLE [dbo].[StudentProgramData](
[StudentID] [nvarchar](10) NULL,
[Catalog] [nvarchar](10) NULL,
[Degree] [nvarchar](10) NULL,
[Major] [nvarchar](50) NULL,
[Minor] [nvarchar](50) NULL,
[Concentration] [nvarchar](50) NULL)
示例数据:
insert into StudentProgramData
values
('000011111', '2014-16', 'BS', 'PS', 'HI', 'PCC'),
('000022222', '2012-14', 'BA', 'MK', 'BI', 'ESO'),
('000033333', '2012-14', 'BS', 'MB', NULL, 'AUE'),
('000044444', '2014-16', 'ME', 'PS', 'HI', NULL),
('000055555', '2010-12', 'MD', 'PS', NULL, 'PCC')
我收录了5个样本记录,但上面的输出只显示了第一个学生。
到目前为止我的循环代码是:
(select
ltrim(rtrim(StudentProgramData.catalog)) as [program/@catalog],
ltrim(rtrim(StudentProgramData.degree)) as [program/@degree],
ltrim(rtrim(StudentProgramData.major)) as [program/@major],
ltrim(rtrim(StudentProgramData.minor)) as [program/@minor],
ltrim(rtrim(StudentProgramData.concentration)) as [program/@concentration]
from StudentProgramData
for xml path('program'), type).query('
<academic_goal type="official">
{
for $program in /program
return
<program_group>
{$program/Name}
<program type="catalog">{data($program/program/@year)}</program>
<program type="degree">{data($program/program/@degree)}</program>
<program type="major">{data($program/program/@major)}</program>
<program type="minor">{data($program/program/@minor)}</program>
<program type="concentration">{data($program/program/@concentration)}</program>
</program_group>
}
</academic_goal>')
非常感谢您提供的任何帮助。
答案 0 :(得分:2)
另一种方法是为每个程序组创建派生表/ unpivot。
select SPD.StudentID as '@id',
(
select 'official' as '@type',
(
select V.Type as '@type',
V.Value as '*'
from (values('catalog', SPD.Catalog),
('degree', SPD.Degree),
('major', SPD.Major),
('concentration', SPD.Concentration)) as V(Type, Value)
for xml path('program'), root('program_group'), type
),
(
select V.Type as '@type',
V.Value as '*'
from (values('catalog', SPD.Catalog),
('degree', SPD.Degree),
('minor', SPD.Minor)) as V(Type, Value)
for xml path('program'), root('program_group'), type
)
for xml path('academic_goal'), type
)
from dbo.StudentProgramData as SPD
for xml path('student');
答案 1 :(得分:1)
我很确定有人会因为想出一些如此迂回的东西而打我的手腕(@Shnugo,你在哪里?),但这就是我得到的。它可能不是最好的,毫无疑问,有人会给你一个更好的答案。但这是你可以在此期间使用的东西。
SELECT
studentId AS [student/@id],
'official' AS [student/academic_goal/@type],
(
SELECT
(
SELECT
'catalog' AS [program/@type],
ltrim(rtrim(catalog)) AS [program]
FOR XML
PATH(''), TYPE
),
(
SELECT
'degree' AS [program/@type],
ltrim(rtrim(degree)) AS [program]
FOR XML
PATH(''), TYPE
),
(
SELECT
'major' AS [program/@type],
ltrim(rtrim(major)) AS [program]
FOR XML
PATH(''), TYPE
),
(
SELECT
'concentration' AS [program/@type],
ltrim(rtrim(concentration)) AS [program]
FOR XML
PATH(''), TYPE
)
FOR XML
PATH('program_group'), TYPE
) AS [student/academic_goal],
(
SELECT
(
SELECT
'catalog' AS [program/@type],
ltrim(rtrim(catalog)) AS [program]
FOR XML
PATH(''), TYPE
),
(
SELECT
'degree' AS [program/@type],
ltrim(rtrim(degree)) AS [program]
FOR XML
PATH(''), TYPE
),
(
SELECT
'minor' AS [program/@type],
ltrim(rtrim(minor)) AS [program]
FOR XML
PATH(''), TYPE
)
FOR XML
PATH('program_group'), TYPE
) AS [student/academic_goal]
FROM
StudentProgramData
FOR XML
PATH(''), ROOT('students');
产地:
<students>
<student id="000011111">
<academic_goal type="official">
<program_group>
<program type="catalog">2014-16</program>
<program type="degree">BS</program>
<program type="major">PS</program>
<program type="concentration">PCC</program>
</program_group>
<program_group>
<program type="catalog">2014-16</program>
<program type="degree">BS</program>
<program type="minor">HI</program>
</program_group>
</academic_goal>
</student>
<student id="000022222">
<academic_goal type="official">
<program_group>
<program type="catalog">2012-14</program>
<program type="degree">BA</program>
<program type="major">MK</program>
<program type="concentration">ESO</program>
</program_group>
<program_group>
<program type="catalog">2012-14</program>
<program type="degree">BA</program>
<program type="minor">BI</program>
</program_group>
</academic_goal>
</student>
<student id="000033333">
<academic_goal type="official">
<program_group>
<program type="catalog">2012-14</program>
<program type="degree">BS</program>
<program type="major">MB</program>
<program type="concentration">AUE</program>
</program_group>
<program_group>
<program type="catalog">2012-14</program>
<program type="degree">BS</program>
<program type="minor" />
</program_group>
</academic_goal>
</student>
<student id="000044444">
<academic_goal type="official">
<program_group>
<program type="catalog">2014-16</program>
<program type="degree">ME</program>
<program type="major">PS</program>
<program type="concentration" />
</program_group>
<program_group>
<program type="catalog">2014-16</program>
<program type="degree">ME</program>
<program type="minor">HI</program>
</program_group>
</academic_goal>
</student>
<student id="000055555">
<academic_goal type="official">
<program_group>
<program type="catalog">2010-12</program>
<program type="degree">MD</program>
<program type="major">PS</program>
<program type="concentration">PCC</program>
</program_group>
<program_group>
<program type="catalog">2010-12</program>
<program type="degree">MD</program>
<program type="minor" />
</program_group>
</academic_goal>
</student>
</students>
答案 2 :(得分:1)
您的格式很棘手的是使用了许多具有相同名称<program>
的节点。由于引擎需要首先构建属性,因此无法再添加值,然后再将属性添加到相同节点。引擎至少这么认为。
技巧:在两者之间添加一个空元素。这将告诉引擎,最后一个要关闭。试试这样:
SELECT StudentID AS [@id]
,(
SELECT 'official' AS [@type]
,(
SELECT 'catalog' AS [program/@type]
,spd.[Catalog] AS [program]
,''
,'degree' AS [program/@type]
,spd.[Degree] AS [program]
,''
,'major' AS [program/@type]
,spd.[Major] AS [program]
,''
,'concentration' AS [program/@type]
,spd.[Concentration] AS [program]
FOR XML PATH('program_group'),TYPE
)
,(
SELECT 'catalog' AS [program/@type]
,spd.[Catalog] AS [program]
,''
,'degree' AS [program/@type]
,spd.[Degree] AS [program]
,''
,'minor' AS [program/@type]
,spd.[Minor] AS [program]
FOR XML PATH('program_group'),TYPE
)
FROM StudentProgramData AS spd
WHERE s.StudentID=spd.StudentID
FOR XML PATH('academic_goal'),TYPE
)
FROM StudentProgramData AS s
FOR XML PATH('student')--,ROOT('root') --Do you need a root node? Probably yes, if more than 1 student...