我正在大学做一个项目,我们要创建一个java程序,将高尔夫球手添加到成员列表中。我无法将它们添加到列表中!
到目前为止,这是我的代码:
*import java.util.*;
public class GolfClubTester {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
System.out.println("Please enter number for:");
System.out.println("1: Joining Member:");
System.out.println("2: Remove an old Member:");
System.out.println("3: Search for a Member:");
System.out.println("4: View all");
//Ask User for input
Scanner input = new Scanner(System.in);
int i = input.nextInt();
if(i == 1){
//Clear scanner input buffer
input.nextLine();
System.out.println("Please enter Members name:");
String name = input.nextLine();
System.out.println("Please enter day:");
int day = input.nextInt();
System.out.println("Please enter month");
int month = input.nextInt();
System.out.println("Please enter year:");
int year = input.nextInt();
System.out.println("Please enter Handicap:");
int Handicap = input.nextInt();
System.out.println("Please enter Id:");
int MemId = input.nextInt();
//Clear scanner input buffer
input.nextLine();
//Ask user type of Member
System.out.println("Please enter type of Member:");
System.out.println("1 - Senior:");
System.out.println("2 - Junior:");
int i1 = input.nextInt();
if (i1 == 1){
//Create member object
Date join1 = new Date(day,month,year);
SeniorMembers s1 = new SeniorMembers(name,join1,Handicap,MemId);
//Display member details
System.out.println("**Senior Member has joined**");
System.out.println(s1);
return;
}
else if (i1 == 2){
Date join1 = new Date(day,month,year);
JuniorMembers j1 = new JuniorMembers(name,join1,Handicap,MemId);
//Display member details
System.out.println("**Junior Member has joined**");
System.out.println(j1);
}
else{
throw new IllegalArgumentException("Invalid input:");
}
}*
所以我可以说会员已加入,但实际上并没有保存会员。任何人都可以帮助并告诉我我错过了什么吗?
答案 0 :(得分:0)
ArrayList<SeniorMember> seniorMembersList = new ArrayList<>();
ArrayList<JuniorMember> juniorMembersList = new ArrayList<>();
public static void main(String[] args) {
// TODO code application logic here
System.out.println("Please enter number for:");
System.out.println("1: Joining Member:");
.......
if (i1 == 1){
//Create member object
Date join1 = new Date(day,month,year);
SeniorMembers s1 = new SeniorMembers(name,join1,Handicap,MemId);
//
//Adding here
//
seniorMembersList.add(s1);
//Display member details
System.out.println("**Senior Member has joined**");
System.out.println(s1);
return;
}
else if (i1 == 2){
Date join1 = new Date(day,month,year);
JuniorMembers j1 = new JuniorMembers(name,join1,Handicap,MemId);
//
//Adding here
//
juniorMembersList.add(j1);
//Display member details
System.out.println("**Junior Member has joined**");
System.out.println(j1);
}
然后,您可以使用seniorMembersList.get(position);
访问您需要的成员对象答案 1 :(得分:0)
此外,我认为您可以从所有评论和答案中获得,您可以将实例存储在列表中(例如ArrayList<String>
)。
由于您的程序采用main
方法,因此列表应在此方法中实例化。
提示:当您进一步实施时,请使用更面向对象的方法。