Question

我有一个列表撤消和另一个ap，我想保存每次我修改ap列表上的副本撤销但是当我保存时，例如撤销[2]我对ap做了什么，撤消[1]与Undo [2]相同，看起来它分配了列表ap而不是ap的值。我发现了一个类似的问题并试图分配ap [：]所以它会复制但不会。

from Functionalitati import *
from Ui import *
from GlobalVr import *
Active = True
NumarApartamente = int(input("Numarul apartamentelor:"))
cntA = 0
while cntA < NumarApartamente:
    ap.append({"gaz":{}, "apa":{}, "electricitate":{}, "canalizare":{}, "altele":{}})
    cntA = cntA + 1
Undo = Undo + ap[ : ]
while Active:
    while True:
        op1 = Umenu()
        if op1 > 6 and op1 < 0:
            print(x,'Nu este o comanda valida')
        else:
            break
    if op1 == 0:
        break
    op2 = Submenu(op1)

    if op1 == 6 and UndoCont > 0:
        UndoCont = UndoCont - 1
        Undo.pop()
        ap = Undo[UndoCont]
        print (Undo)

    elif op1 == 1 and op2 == 1 :
        ap = AddCheltuiala(ap)
        Undo = Undo + ap[ : ]
        UndoCont = UndoCont + 1

    elif op1 == 1 and op2 == 2 :
        ap = ModCheltuiala(ap)
        Undo.append(ap[0:NumarApartamente - 1])
        UndoCont = UndoCont + 1

    elif op1 == 2 and op2 == 1 :
        ap = DelCheltuiala(ap)
        Undo.append(ap[0:NumarApartamente - 1])
        UndoCont = UndoCont + 1

    elif op1 == 2 and op2 == 2 :    
        ap = DelCCheltuiala(ap)
        Undo.append(ap[0:NumarApartamente - 1])
        UndoCont = UndoCont + 1

    elif op1 == 2 and op2 == 3 :
        ap = DelTip(ap,NumarApartamente)
        Undo.append(ap[0:NumarApartamente - 1])
        UndoCont = UndoCont + 1

我也尝试过append和Undo = Undo + ap [：]，你可以看到。对不起，如果代码有点乱。编辑：我删除了上次编辑，我想让它更清晰所以我再制作一段代码来恢复我想说的话

from Functionalitati import *
from Ui import *
import datetime
ap = [] #lista principala

UndoCont = 0
nrAp = int(input("Da-ti numarul apartamentelor:"))
Undo = [None] * nrAp
contor = 0
while contor < nrAp:
    ap.append({"gaz":{}, "apa":{}, "electricitate":{}, "canalizare":{}, "altele":{}})
    contor = contor + 1

Undo[0] = ap[:]
print(Undo)
print("space" * 4)
ap[1]["gaz"]["date"] = 100
Undo[1] = ap[:]
print (Undo)

输出：

Da-ti numarul apartamentelor:2
[[{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}], None]
spacespacespacespace
[[{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {'date': 100}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}], [{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {'date': 100}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}]]

为什么撤消[0]修改为撤消[1]？我尝试使用Undo.append（list（ap））和Undo = Undo + list（ap）和ap [：]相同，现在我尝试初始化Undo之前和相同的结果。

Answer 1

Solved。我真的不知道它是如何工作的但是我使用copy.deepcopy()（copy.copy()没有用）

Python列表按值分配

1 个答案: