Question

我知道这个问题被问了一千多次，但我确实遇到了这个问题。最近我一直在我自己的网站上工作并试图用login db语句（PHP，MySQL）更新insert，但每次我都收到相同的错误消息：

INSERT INTO登录（ldate，uid）VALUES（now（），＆＃39;＆＃39;）
你有错误在你的SQL语法中;查看与MySQL对应的手册服务器版本，用于在＆＃39;]附近使用正确的语法。＆＃39;在第1行;

MySQL表：

+-------+-----------------+------+-----+-------------------+----------------+
| Field | Type            | Null | Key | Default           | Extra          |
+-------+-----------------+------+-----+-------------------+----------------+
| lid   | int(6) unsigned | NO   | PRI | NULL              | auto_increment |
| ldate | timestamp       | NO   |     | CURRENT_TIMESTAMP |                |
| uid   | int(6) unsigned | NO   | MUL | NULL              |                |

PHP代码：

if(isset($_POST["login"])){

       require("connect.php");

        $email = strip_tags(trim($_POST["email"]));
        $password = strip_tags(trim($_POST["password"]));

        $passwordSha = sha1($password);

        $sql = ("SELECT pemail,upass FROM personalDetails,passwords WHERE personalDetails.pemail='".$email."'"
                . " AND passwords.upass='".$passwordSha."'LIMIT 1");


        $result = $conn->query($sql);
        $row=mysqli_fetch_array($result,MYSQLI_ASSOC);
        $id = $row["uid"];


         if($row["pemail"] === $email && $row["upass"] === $passwordSha){
                   echo $row['pemail'];
                   $uid = $row["uid"];
                   $sql = "INSERT INTO logins (ldate,uid) VALUES (now(),'$uid')";


                   if (mysqli_query($conn, $sql)) {
                        echo "New record created successfully";
                   } else {
                            echo "Error: " . $sql . " " . mysqli_error($conn);
                   }
         }else{
                echo "0 results";
            }


                            }

任何建议将不胜感激。谢谢！

排序谢谢

php mysqli插入错误

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