如何将D1与D2进行比较,并将结果用作查询的一部分。
Select A.id,
CASE
WHEN D1 >= D2
THEN D2
WHEN D2 > D1
THEN D1
END
FROM A,E
我想得到D1和D2的较低者
main/0
答案 0 :(得分:1)
SELECT id, LEAST(d1, d2) FROM (
Select A.id,
(Select b.date from b,c where b.id=c.id and c.id = E.id and b.id = 1) as d1,
(Select b.date from b,c where b.id=c.id and c.id = E.id and b.id = 2)) as d2
from
A,E
)
答案 1 :(得分:1)
我想你可能想要这样的东西:
Select A.id, min(b.date)
from A
cross join b
join c on b.id = c.id
join E on c.id = E.id
where b in (1,2)
group by A.id
答案 2 :(得分:0)
使用$sql1 = "SELECT * FROM table1";
$sql2 = "SELECT * FROM table2";
$sql3 = "SELECT * FROM table3";
getElements(["table1"=> $sql1, "table2" => $sql2, "table3" => $sql3]);
sub-select
开始使用select id,
CASE WHEN D1 >= D2 THEN D2 ELSE D1 END
From
(
/* Your Query */
) A
语法而不是旧式逗号分隔连接。这是正确的方法
JOIN