我有以下输出:
portfolio name | accounts | segment | number
A | USD | seg1 | 23
A | CNY | seg2 | null
A | EUR | seg2 | null
B | EUR | seg2 | null
B | USD | seg2 | null
B | EUR | seg3 | 24
我想基本上根据投资组合名称,相同的段和相同的数字连接所有行。正如您所看到的,有时数字也可以为空。
基本上我想要这个例子的最终输出是:
A | USD | seg1 | 23
A | CNY, EUR | seg2 | null
B | EUR, USD | seg2 | null
B | EUR | seg3 | 24
我尝试过使用listagg,但无法弄明白......
希望你理解我的问题。
答案 0 :(得分:1)
如果您使用的是Oracle(您说过您尝试使用LISTAGG
),那么:
SELECT t.portfolio_name, t.segment,
LISTAGG(COALESCE(t.accounts,''),',') WITHIN GROUP (ORDER BY t.accounts) as segments,
(SELECT LISTAGG(COALESCE(s.number,''),',') WITHIN GROUP (ORDER BY s.number)
FROM (SELECT DISTINCT p.portfolio_name,p.segment,p.number
FROM YourTable p) s
WHERE t.portfolio_name = s.portfolio_name
AND t.segment = s.segment ) as numbers
FROM YourTable t
GROUP BY t.portfolio_name, t.segment
答案 1 :(得分:0)
select "portfolio name"
,listagg (accounts,',') within group (order by accounts) as accounts
,segment
,"number"
from t
group by "portfolio name"
,segment
,"number"
;
答案 2 :(得分:-1)
如果列已修复concat所有列,但请确保为此输出需要将null转换为字符串。 例如: 从t1
中选择c1 +' |' + cast(c2 as varchar)