Question

// array containing the active humans.
public final Array<Human> activeHumans = new Array<Human>();
// object pool.
public final Pool<Human> humanPool = new Pool<Human>() {
    @Override
    protected Human newObject() {
        return new Human(100, 500);
    }
};

............................................... .............................

@Override
public void update(float dt) {
checkCollisions();
}

public void checkCollisions() {

// human-human collision
    for (int i=0; i<activeHumans.size(); i++) {
    Human h1 = activeHumans.get(i);

    for (int j=0; j<activeHumans.size(); j++) {
        Human h2 = activeHumans.get(j);

        if (h1.getRectangle().overlaps(h2.getRectangle())) {
                h1.setX(h1.getX() + 2);
              }
    }
}

}

不知何故，所有对象Human（h1和h2）都会setX(h1.getX() + 2);。怎么解决？我只需要将其中一个放在一边

Answer 1

也许你可以改变第二个循环，以避免检查一个与自身重叠的对象（它总是这样做！）并且还避免检查每一对两次：

for (int j=i+1; j<activeHumans.size(); j++) ...

如何处理同类对象的冲突？

1 个答案: