以下是需要转换的JSON字符串:
{
"b2b": [
{
"ctin": "37ABCDE9552F3Z4",
"inv": [
{
"inum": "S008400",
"idt": "09-04-2016",
"val": 861786.91,
"pos": "6",
"rchrg": "No",
"pro_ass": "Y",
"itms": [
{
"num": 1,
"itm_det": {
"ty": "S",
"hsn_sc": "H724",
"txval": 5589.87,
"irt": 0.0,
"iamt": 0.0,
"crt": 87.92,
"camt": 5.7947562568E8,
"srt": 86.56,
"samt": 50.74
}
},
{
"num": 2,
"itm_det": {
"ty": "S",
"hsn_sc": "H863",
"txval": 2509.27,
"irt": 0.0,
"iamt": 0.0,
"crt": 12.99,
"camt": 26144.48,
"srt": 31.81,
"samt": 276654.5
}
}
]
}
]
},
{
"ctin": "76ABCDE2148F9Z9",
"inv": [
{
"chksum": "AflJufPlFStqKBZ",
"inum": "S008400",
"idt": "24-11-2016",
"val": 729248.16,
"pos": "6",
"rchrg": "No",
"pro_ass": "Y",
"itms": [
{
"num": 1,
"itm_det": {
"ty": "S",
"hsn_sc": "S8590",
"txval": 8196.88,
"irt": 0.0,
"iamt": 0.0,
"crt": 42.44,
"camt": 202.86,
"srt": 40.99,
"samt": 0.02
}
},
{
"num": 2,
"itm_det": {
"ty": "S",
"hsn_sc": "H357",
"txval": 6760.14,
"irt": 0.0,
"iamt": 0.0,
"crt": 23.89,
"camt": 6.8214986738E8,
"srt": 60.95,
"samt": 0.03
}
}
]
}
]
}
]
}
我需要内部循环数据作为新表。即第一个表应包含2行,其中应包含“ctin”和“inv”。类似地,第二个表应该具有inum细节,第三个表应该具有项目细节。
答案 0 :(得分:0)
我建议你遵循以下步骤:
JSON
字符串Edit > Paste Special > Paste JSON as classes
适当的课程:
public class Rootobject
{
public B2b[] b2b { get; set; }
}
public class B2b
{
public string ctin { get; set; }
public Inv[] inv { get; set; }
}
public class Inv
{
public string inum { get; set; }
public string idt { get; set; }
public float val { get; set; }
public string pos { get; set; }
public string rchrg { get; set; }
public string pro_ass { get; set; }
public Itm[] itms { get; set; }
public string chksum { get; set; }
}
public class Itm
{
public int num { get; set; }
public Itm_Det itm_det { get; set; }
}
public class Itm_Det
{
public string ty { get; set; }
public string hsn_sc { get; set; }
public float txval { get; set; }
public float irt { get; set; }
public float iamt { get; set; }
public float crt { get; set; }
public float camt { get; set; }
public float srt { get; set; }
public float samt { get; set; }
}
注意:您还可以在类上使用
[DataContract(Name ="...")]
等属性,在属性上使用[DataMember(Name = "...")]
,以便在C#
和{{1}之间进行一些区分属性名称。您应该使用名称
替换JSON
答案 1 :(得分:0)
使用json2charp,您可以轻松生成C#类,以便从JSON进行解析。您可以使用以下数据:
@media only screen and (max-width:768px)
{
/*do something*/
}
您可以删除不需要的属性。使用JSON.NET进行解析就像
public class ItmDet
{
public string ty { get; set; }
public string hsn_sc { get; set; }
public double txval { get; set; }
public double irt { get; set; }
public double iamt { get; set; }
public double crt { get; set; }
public double camt { get; set; }
public double srt { get; set; }
public double samt { get; set; }
}
public class Itm
{
public int num { get; set; }
public ItmDet itm_det { get; set; }
}
public class Inv
{
public string inum { get; set; }
public string idt { get; set; }
public double val { get; set; }
public string pos { get; set; }
public string rchrg { get; set; }
public string pro_ass { get; set; }
public List<Itm> itms { get; set; }
public string chksum { get; set; }
}
public class B2b
{
public string ctin { get; set; }
public List<Inv> inv { get; set; }
}
public class RootObject
{
public List<B2b> b2b { get; set; }
}