我的程序是验证输入代码是否为空。条件是如果输入的代码编号(通过csv文件)继续,如果代码编号为空,则显示错误消息。 "代码编号为空行:__"。 我的问题是如何打印代码编号为空的行的索引。
这是我的样本数据(csv):
CRITERIA CODE NAME AGE ADDRESS
ADD 0001 JOHN 21 USA
ADD MICH 16 EUR
ADD ALI 11 PHL
错误信息应为:
"The code number is empty in line 2."
"The code number is empty in line 3."
这是我目前的计划:
private static String[] sNextLine2;
public static Map<String,Employee> getChanges
( String sFileName, Map<String, Employee> mEmployeeList )
throws IOException {
//Read_File
setReader2(new CSVReader(new FileReader(sFileName)));
while ((sNextLine2 = reader2.readNext()) != null) {
switch(sNextLine2[0]) {
case "ADD":
if(sNextLine2[1].isEmpty()) {
System.out.println("The code number is empty in line" + lineNumber); //how to get that line number
} else if (mEmployeeList.containsKey(sNextLine2[1]))
{
System.out.println("Data already exist");
}
else
{
mEmployeeList.put(sNextLine2[1],new Employee(sNextLine2[1],
sNextLine2[2], sNextLine2[3], sNextLine2[4], sNextLine2[5],
sNextLine2[6], sNextLine2[7], sNextLine2[8]));
}
break;
}
我希望有人会帮助我。谢谢!
答案 0 :(得分:1)
你可以添加一个计数器,每.readNext()
递增一次,如果有错误就打印出来
int counter=0;
while ((sNextLine2 = reader2.readNext()) != null) {
counter++;
switch(sNextLine2[0]) {
case "ADD":
if(sNextLine2[1].isEmpty()) {
System.out.println("The code number is empty in line" + counter); //how to get that line number
} else if (mEmployeeList.containsKey(sNextLine2[1]))
{
System.out.println("Data already exist");
}
else
{
mEmployeeList.put(sNextLine2[1],new Employee(sNextLine2[1],
sNextLine2[2], sNextLine2[3], sNextLine2[4], sNextLine2[5],
sNextLine2[6], sNextLine2[7], sNextLine2[8]));
}
break;
}