你好我所有的新节点js和mongo db所以我面临一个问题,上面写的想要匹配数组中的id并得到所有匹配id的记录,但那不起作用我已经尝试过循环,但这需要花费太多时间,所以我正在寻找某种查询,通过它我传递id并得到匹配的结果我有下面的功能也在哪里我可以传递id并得到匹配的结果,但我不知道怎么称呼它。
exports.getDistrictFromId = function(req, res, next) {
var distId = req.params.id;
districtslib.getDistricts({_id: utils.toObjectId(distId)}, function(err, district) {
if (err) {
return next(err);
}
req.store.district = district;
next();
});
};
这是我的代码
exports.getCompleteTeachersList = function(req, res, next) {
var query = req.store.get('query');
var teacherQuery = {enabled: true};
var searchQuery = '';
if (!_.isUndefined(query)) {
// schoolQuery = {'name':new RegExp(query.replace(/([.?*+^$[\]\\(){}|-])/g, "\\$1"),'i')};
//{ $text: { $search: "amit hinduja"} }
//teacherQuery = {enabled: true,$or:[{firstName:new RegExp(query.replace(/([.?*+^$[\]\\(){}|-])/g, "\\$1"),'i')},{lastName:new RegExp(query.replace(/([.?*+^$[\]\\(){}|-])/g, "\\$1"),'i')}]};
if(query.trim() != '') {
teacherQuery = {enabled: true,$text: { $search: query} };
searchQuery = query;
}
}
teacherslib.getTeachers(teacherQuery, function(err, teachers) {
if (err) {
return next(err);
}
var schools = req.store.get('schools');
for(var i = 0; i < teachers.length; i++) {
teachers[i].schoolName = "";
for(var j = 0; j < schools.length; j++) {
if (teachers[i].schoolId.toString() === schools[j]._id.toString()) {
teachers[i].schoolName = schools[j].name;
teachers[i].distId = "";
var districts = req.store.get('districts');
console.log(schools[j].distId);
// i want to get the array of matching district id `schools[j].distId` from the district array from `var districts = req.store.get('districts');` this line
break;
}
}
}
req.store.set('searchQuery', searchQuery);
req.store.set('teachers', teachers);
//req.store.set('districts', districts);
next();
});
};
集合结构是这样的 1)在学校集合中出现了很糟糕的情况 使用distid从区获取所有匹配的记录 2)分区数组有countyid,从那个县id必须从县集合中获取数据