Question

我想在三列中显示我的sql结果，如下面的格式。

怎么可能？我应该用tr和td添加表吗？还是我的代码中的div？

CategoryName1     CategoryName2     CategoryName3   
subcategoryN      subcategoryN      subcategoryN



<?php 
  foreach ($resultLang as $oneRec)
  {             
    $catid= $oneRec["categoryID"];


    echo"<strong>".$oneRec["categoryName"]."</strong><br>";


    $sqlCmd2 ="SELECT subcategories.subCatID,subcategories.subCatName
              FROM subcategories
              JOIN categories
              ON subcategories.categoryID=categories.categoryID
              JOIN languages
              ON categories.languageID = languages.languageID
              WHERE languages.languageID =:lang
              AND categories.categoryID=:cboCat";
    $prepQuery2 = $conn ->prepare($sqlCmd2);
    $prepQuery2->bindParam(":lang",$langTemp, PDO::PARAM_INT);
    $prepQuery2->bindParam(":cboCat",$catid, PDO::PARAM_INT);
    $prepQuery2->execute();
    $resultLang2= $prepQuery2->fetchAll();

    foreach ($resultLang2 as $oneRec)
    {
        $subCatid=$oneRec["subCatID"];

        echo "<a href='displaysubcategory.php?subcat=?$subCatid'>".$oneRec["subCatName"]."</a></br>";

    }               
    echo "<br>";

  }

Answer 1

<?php 
echo"<ul class='maincats'>";
  foreach ($resultLang as $oneRec)
  {             
    $catid= $oneRec["categoryID"];


    echo"<li>";
    echo"<strong>".$oneRec["categoryName"]."</strong>";

    $sqlCmd2 ="SELECT subcategories.subCatID,subcategories.subCatName
              FROM subcategories
              JOIN categories
              ON subcategories.categoryID=categories.categoryID
              JOIN languages
              ON categories.languageID = languages.languageID
              WHERE languages.languageID =:lang
              AND categories.categoryID=:cboCat";
    $prepQuery2 = $conn ->prepare($sqlCmd2);
    $prepQuery2->bindParam(":lang",$langTemp, PDO::PARAM_INT);
    $prepQuery2->bindParam(":cboCat",$catid, PDO::PARAM_INT);
    $prepQuery2->execute();
    $resultLang2= $prepQuery2->fetchAll();
    if($resultLang2) {
        echo"<ul class='subcats'>";
        foreach ($resultLang2 as $oneRec)
        {
            $subCatid=$oneRec["subCatID"];
            echo"<li>";
            echo "<a href='displaysubcategory.php?subcat=?$subCatid'>".$oneRec["subCatName"]."</a>";
            echo"</li>";
        } 
        echo"</ul>";
    }
    echo"</li>";

  }
echo"</ul>";

之后根据你的设计主题使用float，display：inline-block属性为maincats和subats类创建一些CSS规则。

Answer 2

我不知道eclipse标签是什么，但我通常做的是：

 $header = "";
 $data = "";
foreach ($resultLang2 as $oneRec)
{
    $header .= "<td>".$oneRec['field']."</td>";
    $data .= "<tr><td>".$oneRec['someData']."</td><td>".$oneRec['someOtherData']."</td></tr>";
}

 echo "<table>";
 echo "<tr>".$header."</tr>";
 echo $data;
 echo "</table>";

在列中显示结果sql

2 个答案: