Question

正如标题所说的那样。我在一个if语句之后编写的PHP来检查表单的文本部分是否有任何值没有运行。它在我的代码中早先写的一个很好，但不是第二次。

以下是我的全部代码：

<?php include '../header.php'; include '../navigation.php'; ?>

<div id="pageContent">

<form name="format" method="POST" action="phpFunctions.php">
    Please input date: 
    <input type="date" name="date" value="<?php echo date('Y-m-d'); ?>" />
    <input type="submit" name"submit1" value="Format" />
</form>

<?php

if (isset($_POST['date'])) {
    $new_date = $_POST['date'];
    $date = new DateTime($new_date);
    echo 'M-D-Y Format: ' . $date->format('m-d-Y') . '<br>';
    echo 'D-M-Y Format: ' . $date->format('d-m-Y');
}

?>

<form name="stringStuff" method="POST" action="phpFunctions.php">
    Enter string:
    <input type="text" name"yourString">
    <input type="submit" name"submit2" value="Parse" />
</form>

<?php

if (isset($_POST['yourString']) && !empty($_POST['yourString'])) {
    echo 'ayyyyyy lmao';
    $new_string = $_POST['theString'];
    $trimmed_string = trim($new_string);
    echo 'ayyyyyy lmao';
    echo 'String Length: ' . strlen($new_string) . '<br>';
    echo 'Trim Whitespace: ' . $trimmed_string . '<br>';
    echo 'Lowercased: ' . strtolower($new_string) . '<br>';
    if(strpos($new_string, 'DMACC') !== false) {
        echo 'String contains DMACC';
    }
    else {
        echo 'String does not contain DMACC';
    }
}

?>

</div>

<?php include '../footer.php'; ?>

在我提到的

之后，代码中没有工作的部分就是这部分

if (isset($_POST['yourString']) && !empty($_POST['yourString'])) {
    echo 'ayyyyyy lmao';
    $new_string = $_POST['theString'];
    $trimmed_string = trim($new_string);
    echo 'ayyyyyy lmao';
    echo 'String Length: ' . strlen($new_string) . '<br>';
    echo 'Trim Whitespace: ' . $trimmed_string . '<br>';
    echo 'Lowercased: ' . strtolower($new_string) . '<br>';
    if(strpos($new_string, 'DMACC') !== false) {
        echo 'String contains DMACC';
    } else {
        echo 'String does not contain DMACC';
    }
}

Answer 1

你错过了=，name="yourString"

<form name="stringStuff" method="POST" action="test_index.php">
    Enter string:
    <input type="text" name="yourString">
    <input type="submit" name="submit2" value="Parse" />
</form>

Answer 2

似乎你缺少名字=＆＃34; yourString＆＃34;

<input type="text" name="yourString">
<input type="submit" name="submit2" value="Parse" />

php代码＆＃34; if（isset（$ _ POST ...＆＃34;未运行）

2 个答案: