Question

我有一个名为group的模型，另一个名为group membership。我尝试做的是为我的一个字段中的一个字段返回一个单独的字符串。它在前端正确显示，但在写入数据库时，它全部在一个字符串中。所有我想要做的就是获取group_name并在写入数据库时删除其余的字符串。我的目标是返回一个以上的值，因为我需要从同一个模型中获取公司和部门。

我的模特

# Group #
#########
class Group(models.Model):
    created_by = models.ForeignKey('auth.User', related_name='group_created_by')
    id = models.AutoField(primary_key=True)
    company = models.ForeignKey(Company)
    department = models.ForeignKey(Department)
    group_name = models.CharField(max_length=100)
    role = models.CharField(max_length=100)
    status = models.CharField(max_length=8)
    created_date = models.DateTimeField(default=timezone.now)
    modified_date = models.DateTimeField(blank=True, null=True)
    modified_by = models.ForeignKey('auth.User',
            related_name='group_modified_by',
            blank=True, null=True)

    def create(self):
        self.save()

    def __str__(self):
        return '{}{}{}'.format(self.company, self.department, self.group_name)

我的表格

# Group Name #
##############
class GroupNameModelChoiceField(ModelChoiceField):
    def label_from_instance(self, obj):
        return '{}'.format(obj.group_name)


# Group Membership #
####################
class GroupMembershipForm(forms.ModelForm):
    options = (('Enabled', 'Enabled',), ('Disabled', 'Disabled'))
    member_id = forms.CharField(
            widget=forms.TextInput(attrs={'class': 'form-control'})
            )
    company = forms.ModelChoiceField(
            queryset=Company.objects.filter(status='Enabled'),
            widget=forms.Select(attrs={'class': 'form-control'}),
            empty_label=''
            )
    department = forms.ModelChoiceField(
            queryset=Department.objects.filter(status='Enabled'),
            widget=forms.Select(attrs={'class': 'form-control'}),
            empty_label=''
            )
    group_name = GroupNameModelChoiceField(
            queryset=Group.objects.filter(status='Enabled'),
            widget=forms.Select(attrs={'class': 'form-control'}),
            empty_label=''
            )
    user_id = forms.ModelChoiceField(
            queryset=Person.objects.filter(status='Enabled'),
            widget=forms.Select(attrs={'class': 'form-control'}),
            empty_label=''
            )
    full_name = forms.CharField(
            widget=forms.TextInput(attrs={'class': 'form-control'}),
            )
    status = forms.CharField(
            widget=forms.Select(
                attrs={'class': 'form-control'},
                choices=options
                )
            )

    class Meta:
        model = GroupMembership
        fields = ('member_id', 'company', 'department', 'group_name',
                'user_id', 'full_name', 'status')

Answer 1

# Group #
#########
class Group(models.Model):
    created_by = models.ForeignKey('auth.User', related_name='group_created_by')
    id = models.AutoField(primary_key=True)
    company = models.ForeignKey(Company)
    department = models.ForeignKey(Department)
    group_name = models.CharField(max_length=100)
    role = models.CharField(max_length=100)
    status = models.CharField(max_length=8)
    created_date = models.DateTimeField(default=timezone.now)
    modified_date = models.DateTimeField(blank=True, null=True)
    modified_by = models.ForeignKey('auth.User',
            related_name='group_modified_by',
            blank=True, null=True)

    def create(self):
        self.save()

    # Please rename to something sensible
    @property
    def get_special_combination_value(self):
        return '{}{}{}'.format(self.company, self.department, self.group_name)

    def __str__(self):
        return self.group_name

使用@property：

from <yourapp>.models import Group

obj = Group()
# following line will print the special string
obj.get_special_combination_value

属性值也可以在django admin中用作：

class GroupAdmin(admin.ModelAdmin):
    list_display = ('get_special_combination_value',)

admin.site.register(Group, GroupAdmin)

为modelchoicefield独立地从django模型返回多个值

1 个答案: