我遇到使用Jackson将此XML解析为POJO的问题。我已经阅读了有关将类反序列化为POJOS的类的所有前面的描述,但我不断获得Null指针或不是END元素警告。我非常困惑,非常感谢任何帮助。
输入xml是
<row>
<entry align="right" valign="top">20</entry>
<entry align="right" valign="top">1A</entry>
<entry valign="top">SData</entry>
<entry align="center" valign="top">2</entry>
<entry valign="top">binary</entry>
<entry valign="top">Java enterprise</entry>
</row>
我正在使用的代码是;
static void testSmallXml(){
String big = null;
try
{
big = readFileToString("other/testXML/NewFile.xml");
} catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
XmlMapper xmlMapper = new XmlMapper();
String small = big.substring(big.lastIndexOf("<row>"), big.lastIndexOf("</row>")+8);
try
{
rows in = xmlMapper.readValue(small, rows.class);
System.out.println(in.entries[0].value);
} catch (IOException e)
{
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println(small);
}
我的POJO课程
@JacksonXmlRootElement(localName = "row")
@JsonIgnoreProperties(ignoreUnknown = true)
public static class rows{
@JacksonXmlProperty(localName = "entry")
public entry[] entries;
}
@JacksonXmlRootElement(localName = "entry")
@JsonIgnoreProperties(ignoreUnknown = true)
public static class entry{
@JacksonXmlProperty(isAttribute = true)
private String align;
@JacksonXmlProperty(isAttribute = true)
private String valign;
@JacksonXmlText
public String value;
}
我一直得到一个Null指针异常 行[ “条目”] - &GT;对象[] [2])
答案 0 :(得分:2)
试试这个:
@JacksonXmlRootElement(localName = "row")
public static class rows {
@JacksonXmlElementWrapper(useWrapping=false)
@JacksonXmlProperty(localName = "entry")
public entry[] entries;
}
public static class entry {
@JacksonXmlProperty(isAttribute = true)
private String align;
@JacksonXmlProperty(isAttribute = true)
private String valign;
@JacksonXmlText
public String value;
}