Question

我不是最好的程序员，所以如果你能向我解释为什么以及我应该做些什么来解决这个问题，我将不胜感激。

当我运行程序时，我能够输入所有内容，但最后它突出显示了第一个带有java.lang.stackoverflowError的扫描仪行。

import java.util.Scanner;
import java.lang.Object;
public class Login
{
    Scanner input = new Scanner(System.in);
    Scanner input2 = new Scanner(System.in);
    public void createAccount(){
        System.out.print("Create a 6 digit account number: ");
        int createNumber = input.nextInt();

        System.out.print("Create a 4 digit PIN: ");
        int createPin = input2.nextInt();
        Login acc = new Login();
        acc.loginScreen(createNumber, createPin);

    }
    public void loginScreen(int createNumber, int createPin){
        System.out.println("Enter your acocunt number: ");
        int accEntryNumber = input.nextInt();
        int lengthNum = String.valueOf(accEntryNumber).length();

        System.out.println("Enter your pin: ");
        int accEntryPin = input2.nextInt();
        int lengthPin = String.valueOf(accEntryPin).length();
        if(accEntryPin == createPin && accEntryNumber == createNumber){
            Main access = new Main();
            access.mainMenu();
        }
        else{
            System.out.println("Access denied");
        }
    }
}

Answer 1

您可以为整个程序使用一台扫描仪。像这样：

import java.util.Scanner;
import java.lang.Object;
public class Login
{
    Scanner input = new Scanner(System.in);
    public void createAccount(){
        System.out.print("Create a 6 digit account number: ");
        int createNumber = input.nextInt();

        System.out.print("Create a 4 digit PIN: ");
        int createPin = input.nextInt();
        Login acc = new Login();
        acc.loginScreen(createNumber, createPin);

    }
    public void loginScreen(int createNumber, int createPin){
        System.out.println("Enter your acocunt number: ");
        int accEntryNumber = input.nextInt();
        int lengthNum = String.valueOf(accEntryNumber).length();

        System.out.println("Enter your pin: ");
        int accEntryPin = input.nextInt();
        int lengthPin = String.valueOf(accEntryPin).length();
        if(accEntryPin == createPin && accEntryNumber == createNumber){
            Main access = new Main();
            access.mainMenu();
        }
        else{
            System.out.println("Access denied");
        }
    }
}

有人可以帮助我理解这个堆栈溢出错误

1 个答案: