Question

我想在akka-http中编写一个轮询客户端，将所有响应主体转换为Play JsObject。到目前为止我所使用的是使用this library的代码，它应该简单（我认为？）。但是当我尝试运行下面的代码时，我收到以下错误：

Error:(26, 56) type mismatch;
 found   : akka.http.scaladsl.unmarshalling.FromEntityUnmarshaller[play.api.libs.json.JsObject]
    (which expands to)  akka.http.scaladsl.unmarshalling.Unmarshaller[akka.http.scaladsl.model.HttpEntity,play.api.libs.json.JsObject]
 required: akka.http.scaladsl.unmarshalling.Unmarshaller[akka.http.scaladsl.model.HttpResponse,play.api.libs.json.JsObject]
    Unmarshaller.byteStringUnmarshaller.mapWithCharset { (data, charset) =>

我需要做些什么才能让事情按预期运作？

import java.util.UUID

import akka.actor.ActorSystem
import akka.http.scaladsl.Http
import akka.http.scaladsl.model.{HttpEntity, HttpRequest, HttpResponse}
import akka.stream.ActorMaterializer
import akka.stream.scaladsl.Source
import akka.http.scaladsl.unmarshalling.{Unmarshal, Unmarshaller}
import de.heikoseeberger.akkahttpplayjson.PlayJsonSupport._
import play.api.libs.json.{JsObject, Json}

import scala.concurrent.duration._
import scala.util.{Success, Try}


object Main extends App {

  implicit val system = ActorSystem("TestSys")
  implicit val ec = system.dispatcher
  implicit val materializer = ActorMaterializer()

  implicit val um:Unmarshaller[HttpResponse, JsObject] = {
    Unmarshaller.byteStringUnmarshaller.mapWithCharset { (data, charset) =>
      Json.parse(data.toArray).as[JsObject]
    }
  }

  val request = HttpRequest(uri="https://www.google.com/finance/info?q=INDEXDB%3ADAX") -> UUID.randomUUID()
  val pool = Http().superPool[UUID]()
  val googleFinanceFlow =
    Source.tick(0 milliseconds,10000 milliseconds,request)
      .via(pool)
    .runForeach {
      case (Success(response),_) =>
        val json = Unmarshal(response).to[JsObject]
        println(json.onSuccess{case r => println(r.toString())})
      case _ => Json.obj()
    }
}

Answer 1

只需删除Unmarshaller[HttpResponse, JsObject]的显式隐式（哇，听起来不错，嗯？）定义。这不是必需的，因为PlayJsonSupport提供了合适的unmarshaller。

在akka-http客户端中使用PlayJson

1 个答案: