Question

prob = input("Please enter your problem?")
words = set(prob.split())

file=open('solutions.txt')
line=file.readlines()
if ("smashed") or ("screen") or ("dropped") in words:
    print (line[0])
elif ("wet") or ("water") in words:
    print (line[6])
else:
    print("sorry")

此代码的问题在于它只打印文本文件的顶行

结果如下：

>>> 
============== RESTART: C:\Users\bb\Desktop\completed - Copy.py ==============
Please enter your problem?smashed
your screen is smashed

>>> 
============== RESTART: C:\Users\bb\Desktop\completed - Copy.py ==============
Please enter your problem?wet
your screen is smashed

>>> 
============== RESTART: C:\Users\bb\Desktop\completed - Copy.py ==============
Please enter your problem?bntuib
your screen is smashed

>>>

正如您所看到的，无论用户输入什么，它都只显示代码的顶行。

Answer 1

您的第一个check_list = ["smashed", "screen", "dropped"] # Words to check if any(w_ in words for w_ in check_list): # Checks that at least one conditions returns True print (line[0])条件存在问题。

请尝试以下方法：

        String strRx = "";
        int c = 0;
        int k = 0;

        //BLuetoothi pakettide vastuvõtmine ja ekraanile panek
        while (true) {
            try {
                //Mingi data tuleb, seega ekraanile
                if (connectedInputStream.available() > 0) {
                    bytes = connectedInputStream.read(buffer);
                    final String strReceived = new String(buffer);

                    runOnUiThread(new Runnable() {

                        @Override
                        public void run() {
                            // textStatus.append(strReceived);
                            textStatus.setText(strReceived);


                            String strReceivedCut=strReceived.substring(0,8); //Lõikab stringist esimese osa välja
                            boolean resultOfComparison=new String("EMPTYING").equals(strReceivedCut);
                            if(resultOfComparison==true) {
                                testkast.setText("It Happened");

                                //long timeNow= System.currentTimeMillis(); //Praegune hetk

                                //long startTime = System.currentTimeMillis();
                                //if(timeNow-startTime>1000*60*10) { //Should be 10 minutes
                                new UploadBySSH().execute(strReceived); //Saadame algse stringi SSH-ga servusse
                                //}

                            }
                        }
                    });



                    //Mingit datat ei tule, seega ootame Sleep
                } else SystemClock.sleep(100);

                //Keepalive osa, mis saadab ? mingi aja tagant
                //hetkel on ajaks 10*100=1000 millisekundit
                //Originaal programmi keepalive:
                //;E??????????;E??????????;E??????????;E??????????;E??????????;E??????????
                c++;

                if (c > 10) {
                    String kl = "?";
                    byte[] bytesToSend = kl.getBytes();
                    connectedOutputStream.write(bytesToSend);
                    c = 0;
                    k++;
                }


            } catch (IOException e) {
                e.printStackTrace();
                final String msgConnectionLost = "Ühendus nurjus: PANE PROGRAMM KINNI\n"
                        + e.getMessage();
                runOnUiThread(new Runnable() {

                    @Override
                    public void run() {
                        textStatus.setText(msgConnectionLost);
                    }
                });
            }
        }


    }`

Answer 2

好的，有很多可以看到这里，让我们一一去：

if语句采用可简化为布尔值的表达式（True / False）。通过或/分隔不同的语句以实现更严格的逻辑如果我想查看列表中是否有以下任何单词，例如：
```
#  (            )    (                )    (                )
if 'wet' in words or 'smashed' in words or 'dropped' in words:
  ...
```

由于这是多余的，我们可以尝试使其更灵活（和可扩展）。

words = ['wet', 'smashed', 'dropped']
if any(word in words for word in cur_line):
    ...

然后我们需要确保每一行都发生这种情况，因此我们应该遍历每一行并应用相同的逻辑......

words = ['wet', 'smashed', 'dropped']
for cur_line in line:
    if any(word in words for word in cur_line):
        print cur_line

如何打印包含用户输入的单词的行？

2 个答案: