我有一个阵列。
Array ( [initial] => MSS [hour] => 5.2 [row_checker_1] => 1 [project_name_1] => KGD001 [project_shortcode_1] => KGD001 [5_1] => 23 [6_1] => 3.3 [4_1] => 23.2 [remarks_1] => on going [task_id] => 76 [row_checker_2] => 2 [project_name_2] => DG001 [project_shortcode_2] => DG001 [5_2] => 1.1 [6_2] => 2.2 [4_2] => 3.1 [remarks_2] => on going )
现在我要拆分所有元素上限范围键是“project_shortcode_1”,而下限范围键是remarks_1。
因此,新数组应如下所示:
array ( [5_1] => 23 [6_1] => 3.3 [4_1] => 23.2 )
答案 0 :(得分:2)
使用带有标志ARRAY_FILTER_USE_KEY
的array_filter来使用数组键,并与获取所需键所需的逻辑进行比较。它适用于PHP 5.6。
$arr = array ( "initial" => "MSS",
"hour" => 5.2,
"row_checker_1" => 1,
"project_name_1" => "KGD001",
"project_shortcode_1" => "KGD001",
"5_1" => 23,
"6_1" => 3.3,
"4_1" => 23.2,
"remarks_1" => "on going",
"task_id" => 76,
"row_checker_2" => 2,
"project_name_2" => "DG001",
"project_shortcode_2" => "DG001",
"5_2" => 1.1,
"6_2" => 2.2,
"4_2" => 3.1,
"remarks_2" => "on going",
);
// PHP > 5.6
$result = array_filter($arr, function($k){
$var = explode('_', $k);
return is_numeric($var[0]) && $var[1]==1;
}, ARRAY_FILTER_USE_KEY);
答案 1 :(得分:2)
如果你需要的是一个包含所有范围NUMBER_N
的多维数组,那么使用类似这样的东西(从Dmitriy Demir回答扩展):
$myArray = array(
'initial' => 'MSS',
'hour' => '5.2',
'row_checker_1' => '1',
'project_name_1' => 'KGD001',
'project_shortcode_1' => 'KGD001',
'5_1' => '23',
'6_1' => '3.3',
'4_1' => '23.2',
'remarks_1' => 'on going',
'task_id' => '76',
'row_checker_2' => '2',
'project_name_2' => 'DG001',
'project_shortcode_2' => 'DG001',
'5_2' => '1.1',
'6_2' => '2.2',
'4_2' => '3.1',
'remarks_2' => 'on going'
);
function splitRange($a){
$newArray = array();
foreach ($a as $k => $v) {
$rightFormat = preg_match('/^\d+_(\d+)$/', $k, $index);
if ($rightFormat)
$newArray[$index[1]][$k] = $v;
}
return $newArray;
}
print_r(splitRange($myArray));
结果如下:
Array
(
[1] => Array
(
[5_1] => 23
[6_1] => 3.3
[4_1] => 23.2
)
[2] => Array
(
[5_2] => 1.1
[6_2] => 2.2
[4_2] => 3.1
)
)
从N
数组索引NUMBER_N
。
答案 2 :(得分:1)
由于您在评论中提到您希望获得格式为NUMBER_1
的所有值,我认为您需要遍历数组并使用regex检查值名称,然后添加值如果符合标准,则为新阵列。以下是我将如何做到这一点:
$myArray = array(
'initial' => 'MSS',
'hour' => '5.2',
'row_checker_1' => '1',
'project_name_1' => 'KGD001',
'project_shortcode_1' => 'KGD001',
'5_1' => '23',
'6_1' => '3.3',
'4_1' => '23.2',
'remarks_1' => 'on going',
'task_id' => '76',
'row_checker_2' => '2',
'project_name_2' => 'DG001',
'project_shortcode_2' => 'DG001',
'5_2' => '1.1',
'6_2a' => '2.2',
'4_2' => '3.1',
'remarks_2' => 'on going'
);
$newArray = array();
foreach ($myArray as $k => $v) {
$rightFormat = preg_match('/^\d+_\d+$/', $k);
if ($rightFormat)
$newArray[$k] = $v;
}
print_r($newArray);
在这种情况下,print_r
的结果将是:
阵列([5_1] => 23 [6_1] => 3.3 [4_1] => 23.2 [5_2] => 1.1 [6_2] => 2.2 [4_2] => 3.1)
如果下划线后的数字应始终为1,则将正则表达式从/^\d+_\d+$/
更改为/^\d+_1$/
。
您可以四处游戏,了解正则表达式的工作原理here。
PS:我已将所有值设置为字符串以方便使用。随意修改它。
答案 3 :(得分:1)
基于正则表达式的解决方案似乎适合这个问题。
preg_grep()是一个旨在对数组中的每个值应用正则表达式过滤器的函数。对于这种情况,我需要进行更多的调整,因为必须过滤密钥。
The One-liner :
$output=array_intersect_key($input,array_flip(preg_grep("/^\d+_1$/",array_keys($input)))));
/* array (
'5_1' => 23,
'6_1' => 3.3,
'4_1' => 23.2,
)*/
以下是逐步数组操作......
array_keys($input); // create array with input keys as values
/* array (
0 => 'initial',
1 => 'hour',
2 => 'row_checker_1',
3 => 'project_name_1',
4 => 'project_shortcode_1',
5 => '5_1',
6 => '6_1',
7 => '4_1',
8 => 'remarks_1',
9 => 'task_id',
10 => 'row_checker_2',
11 => 'project_name_2',
12 => 'project_shortcode_2',
13 => '5_2',
14 => '6_2',
15 => '4_2',
16 => 'remarks_2',
) */
preg_grep("/^\d+_1$/",array_keys($input)); // filter the input array using regex pattern
/* array (
5 => '5_1',
6 => '6_1',
7 => '4_1',
) */
array_flip(preg_grep("/^\d+_1$/",array_keys($input))); // flip the filtered array
/* array (
'5_1' => 5,
'6_1' => 6,
'4_1' => 7,
)*/
array_intersect_key($input,array_flip(preg_grep("/^\d+_1$/",array_keys($input)))); // filter input by comparing keys against filtered array
/* array (
'5_1' => 23,
'6_1' => 3.3,
'4_1' => 23.2,
)*/