Question

我正在使用Python Scipy我有下一个代码：

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我的最后一个函数... t = np.linspace(0, simtime, points) def Vbooster90(t): return np.sin(t * 2 * np.pi*F_booster + 0.5 * np.pi) def beam(t): return np.sign(Vrfq(t) - Vrfq(bunchwidth)) * 0.5 + 0.5 def criteria(t): return np.sign(Vbooster90(t)) def kicker(t): if criteria(t) > 0: k(t)=beam(t) else: k(t)=0 return k(t)有问题。我想在t的每个值中将函数kicker(t)与零进行比较，如果criteria(t)大于零，我想将criteria(t)赋给函数{{1}的值在相同的t值。我是Python新手，不熟悉语法。

Answer 1

修改kicker函数，如下所示。

def kicker(t):
    k = 0
    if criteria(t) > 0:
        k = beam(t)
return k

Answer 2

感谢您的回答，而不是定义一个函数，我接下来解决了它：

kicker = np.empty(points)
i = np.arange(points)
time = np.empty(points)
time[i] = i*simtime/points

for i in range(points):
   if criteria(time[i]) > 0:
    kicker[i] = beam(time[i])
   else:
    kicker[i] = 0

如何将函数值与常量进行比较

2 个答案: