Question

我正在研究这个问题here，以便从2x2图的子图中获取一个图例到整个窗口。目标是获取单个图例，然后删除其他图例，只有一个图例就足够了，应该位于整个窗格的右侧。

也许相关

Global legend using grid.arrange (gridExtra) and lattice based plots

代码

require(lattice)
require(gridExtra)

f<-function(x) as.double(as.character(x))   #factors converted to vectors https://stackoverflow.com/a/40680020/54964

data.female <- structure(list(N11.1 = structure(c(3L, 3L), .Label = c("", "0.0", 
"1.0", "N11"), class = "factor"), N22.1 = structure(c(2L, 2L), .Label = c("", 
"0.0", "2.0", "N22"), class = "factor"), N33.1 = structure(c(2L, 
2L), .Label = c("", "0.0", "N33"), class = "factor"), N44.1 = structure(2:3, .Label = c("", 
"0.0", "0.1", "0.2", "N44"), class = "factor"), N21.1 = structure(c(2L, 
2L), .Label = c("", "0.0", "N21"), class = "factor"), N31.1 = structure(c(2L, 
2L), .Label = c("", "0.0", "N31"), class = "factor"), N32.1 = structure(c(5L, 
7L), .Label = c("", "0.0", "10.8", "11.0", "12.0", "17.0", "20.9", 
"22.8", "24.0", "3.0", "4.0", "44.0", "N32"), class = "factor")), .Names = c("N11.1", 
"N22.1", "N33.1", "N44.1", "N21.1", "N31.1", "N32.1"), row.names = c("Sinus", 
"Arr/AHB"), class = "data.frame")

data.male <- structure(list(N11.1 = structure(c(3L, 3L), .Label = c("", "0.0", 
"1.0", "N11"), class = "factor"), N22.1 = structure(c(2L, 2L), .Label = c("", 
"0.0", "2.0", "N22"), class = "factor"), N33.1 = structure(c(2L, 
2L), .Label = c("", "0.0", "N33"), class = "factor"), N44.1 = structure(c(2L, 
2L), .Label = c("", "0.0", "0.1", "0.2", "N44"), class = "factor"), 
    N21.1 = structure(c(2L, 2L), .Label = c("", "0.0", "N21"), class = "factor"), 
    N31.1 = structure(c(2L, 2L), .Label = c("", "0.0", "N31"), class = "factor"), 
    N32.1 = structure(c(11L, 9L), .Label = c("", "0.0", "10.8", 
    "11.0", "12.0", "17.0", "20.9", "22.8", "24.0", "3.0", "4.0", 
    "44.0", "N32"), class = "factor")), .Names = c("N11.1", "N22.1", 
"N33.1", "N44.1", "N21.1", "N31.1", "N32.1"), row.names = c("Sinus", 
"Arr/AHB"), class = "data.frame")

ID<-c("Sinus","Arr/AHB")

tl <- "female"
p1 <- barchart(f(N11.1)+f(N22.1)+f(N33.1)+f(N44.1)+f(N21.1)+f(N31.1)+f(N32.1) ~ ID,
         data=data.female,
         auto.key=list(space='right'), 
         ylim=c(0,50),
     beside=TRUE,
     ylab = "Number of cases", 
     xlab = "Population/Sample",
     main = tl
         )
tl <- "male"
p2 <- barchart(f(N11.1)+f(N22.1)+f(N33.1)+f(N44.1)+f(N21.1)+f(N31.1)+f(N32.1) ~ ID,
         data=data.male,
         auto.key=list(space='right'),
         ylim=c(0,50),
     beside=TRUE,
     ylab = "Number of cases", 
     xlab = "Population/Sample",
     main = tl 
         )

# Just repeat two barcharts more to get 2x2 example
tl <- "female"
p3 <- barchart(f(N11.1)+f(N22.1)+f(N33.1)+f(N44.1)+f(N21.1)+f(N31.1)+f(N32.1) ~ ID,
         data=data.female,
         auto.key=list(space='right'), 
         ylim=c(0,50),
     beside=TRUE,
     ylab = "Number of cases", 
     xlab = "Population/Sample",
     main = tl
         )
tl <- "male"
p4 <- barchart(f(N11.1)+f(N22.1)+f(N33.1)+f(N44.1)+f(N21.1)+f(N31.1)+f(N32.1) ~ ID,
         data=data.male,
         auto.key=list(space='right'),
         ylim=c(0,50),
     beside=TRUE,
     ylab = "Number of cases", 
     xlab = "Population/Sample",
     main = tl)



grid.arrange(p1,p2,p3,p4, ncol=2, nrow=2,left=("LEFT TITLE"),right=("RIGHT"),bottom=("BOTTOM"), top=("TOP"))

编译生成上面的网格图，但由于图例

grid.arrange(p1,p2,p3,p4, ncol=2, nrow=2,
        legend=list(space='right',
        text=c("N11.1","N22.1","N33.1","N44.1","N21.1","N31.1","N32.1"),
                    columns=1))

最简单的方法是从一些子图继承图例并使用像auto.key这样的东西，但是我无法使用这样的共同工作，因此尝试使用legend命令创建grop对象。

图例命令有什么问题，是否有方便的方法将子图的图例继承到整个窗格，以便可以在窗格外部使用auto.key？

帮助者问题

颜色如何从自动glob创建命令auto.key继承到图例？



不是手动编写图例标签（N11.1，N22.1，...），而是如何从子图中方便地获取它？

Answer 1

我发了一个答案here。我们的想法是避免在绘图中插入密钥，并使用draw.key（）在最终grid.arranged plot的任何位置打印定义的键。

R：使用Lattice

1 个答案: