Question

我有3张桌子。团队，选项，OptionTeam。
团队持有TeamId和名称 Option包含OptionId，OptionGroup
OptionTeam持有TeamId，OptionId，OptionGroup

select a.TeamId, a.Name
(select count(*) from OptionTeam ot where ot.TeamId=a.TeamId and ot.OptionGroup=4) as Option1,
(select count(*) from OptionTeam ot where ot.TeamId=a.TeamId and ot.OptionGroup=5) as Option2,
(select count(*) from OptionTeam ot where ot.TeamId=a.TeamId and ot.OptionGroup=6) as Option3,
(select count(*) from OptionTeam ot where ot.TeamId=a.TeamId and ot.OptionGroup=11) as Option4
from Team a

我想获得一个团队列表，以及额外的列，指示每个团队连接到每个团队的选项数量。这是通过上面的查询来完成的，但我想用表Option中的OptionGroup替换4,5,6,11的值。
它必须是动态的，因为将来可能会有一个新的OptionGroup，我希望存储过程能够处理它。

示例数据：

Team  
TeamId  
1  
2  
3

选项

OptionId | OptionGroup  
11 | 4  
12 | 5  
13 | 4  
14 | 4  
15 | 5

OptionTeam

TeamId | OptionId | OptionGroup  
1 | 11 | 4  
1 | 13 | 4  
2 | 12 | 5  
2 | 14 | 4  
3 | 15 | 5

我想要的清单是

TeamId | Group4 (OptionGroup=4) | Group5 (OptionGroup=5)  
1 | 2 | 0  
2 | 1 | 1  
3 | 0 | 1

Answer 1

你需要一个动态的支点才能做到这一点。这是存储过程：

CREATE PROC [dbo].[pivotsp]
      @query    AS NVARCHAR(MAX),                   -- The query, can also be the name of a table/view.
      @on_rows  AS NVARCHAR(MAX),                   -- The columns that will be regular rows.
      @on_cols  AS NVARCHAR(MAX),                   -- The columns that are to be pivoted.
      @agg_func AS NVARCHAR(257) = N'SUM',          -- Aggregate function.
      @agg_col  AS NVARCHAR(MAX),                   -- Column to aggregate.
      @output   AS NVARCHAR(257) = N'',             -- Table for results
      @debug    AS bit = 0                          -- 1 for debugging
    AS

    -- Example usage:
    --    exec pivotsp
    --          'select * from vsaleshistory',
    --          'market,marketid,family,familyid,Forecaster,Forecasterid,product,productid',
    --          'month',
    --          'sum',
    --          'ku',
    --          '##sales'

    -- Input validation
    IF @query IS NULL OR @on_rows IS NULL OR @on_cols IS NULL
       OR @agg_func IS NULL OR @agg_col IS NULL
    BEGIN
      RAISERROR('Invalid input parameters.', 16, 1);
      RETURN;
    END

    -- Additional input validation goes here (SQL Injection attempts, etc.)

    BEGIN TRY
      DECLARE
        @sql     AS NVARCHAR(MAX),
        @cols    AS NVARCHAR(MAX),
        @newline AS NVARCHAR(2);

      SET @newline = NCHAR(13) + NCHAR(10);

      -- If input is a valid table or view
      -- construct a SELECT statement against it
      IF COALESCE(OBJECT_ID(@query, N'U'),
                  OBJECT_ID(@query, N'V')) IS NOT NULL
        SET @query = N'SELECT * FROM ' + @query;

      -- Make the query a derived table
      SET @query = N'(' + @query + N') AS Query';

      -- Handle * input in @agg_col
      IF @agg_col = N'*'
        SET @agg_col = N'1';

      -- Construct column list
      SET @sql =
          N'SET @result = '                                    + @newline +
          N'  STUFF('                                          + @newline +
          N'    (SELECT N'','' +  quotename( '
                       + 'CAST(pivot_col AS sysname)' +
                       + ')  AS [text()]'                          + @newline +
          N'     FROM (SELECT DISTINCT('
                       + @on_cols + N') AS pivot_col'              + @newline +
          N'           FROM' + @query + N') AS DistinctCols'   + @newline +
          N'     ORDER BY pivot_col'                           + @newline +
          N'     FOR XML PATH(''''))'                          + @newline +
          N'    ,1, 1, N'''');'

      IF @debug = 1
         PRINT @sql

      EXEC sp_executesql
        @stmt   = @sql,
        @params = N'@result AS NVARCHAR(MAX) OUTPUT',
        @result = @cols OUTPUT;

      IF @debug = 1
         PRINT @cols

      -- Create the PIVOT query
      IF @output = N''
          begin
            SET @sql =
                N'SELECT *'                                          + @newline +
                N'FROM (SELECT '
                              + @on_rows
                              + N', ' + @on_cols + N' AS pivot_col'
                              + N', ' + @agg_col + N' AS agg_col'        + @newline +
                N'      FROM ' + @query + N')' +
                              + N' AS PivotInput'                        + @newline +
                N'  PIVOT(' + @agg_func + N'(agg_col)'               + @newline +
                N'    FOR pivot_col IN(' + @cols + N')) AS PivotOutput;'
          end
      ELSE
          begin
            set @sql = 'IF  EXISTS (SELECT * FROM tempdb.sys.objects WHERE  ' +
                'name = ''' + @output + ''' AND type = N''U'') DROP TABLE tempdb.' + @output
            EXEC sp_executesql @sql;

            SET @sql =
                N'SELECT * INTO ' + @output                          + @newline +
                N'FROM (SELECT '
                              + @on_rows
                              + N', ' + @on_cols + N' AS pivot_col'
                              + N', ' + @agg_col + N' AS agg_col'        + @newline +
                N'      FROM ' + @query + N')' +
                              + N' AS PivotInput'                        + @newline +
                N'  PIVOT(' + @agg_func + N'(agg_col)'               + @newline +
                N'    FOR pivot_col IN(' + @cols + N')) AS PivotOutput;'
          end

        IF @debug = 1
           PRINT @sql

        EXEC sp_executesql @sql;
    END TRY
    BEGIN CATCH
      DECLARE
        @error_message  AS NVARCHAR(2047),
        @error_severity AS INT,
        @error_state    AS INT;

      SET @error_message  = ERROR_MESSAGE();
      SET @error_severity = ERROR_SEVERITY();
      SET @error_state    = ERROR_STATE();

      RAISERROR(@error_message, @error_severity, @error_state);

      RETURN;
    END CATCH

通过这种方式，可以很容易地在可变数量的列上进行旋转：

EXEC pivotsp
        'SELECT TeamID, OptionGroup, OptionID AS Options FROM OptionTeam',
        'Teamid',        -- Row headers
        'optiongroup',   -- item to aggregate
        'count',         -- aggregation function
        'optiongroup',   -- Column header
        '##temp'         -- output table name
    SELECT * FROM ##temp

结果：

   Teamid   4   5
    1   2   0
    2   1   1
    3   0   1

Answer 2

SELECT  a.*, o.optionGroup, COUNT(*)
FROM    team a
CROSS JOIN
        option o
JOIN    OptionTeam ot
ON      ot.teamId = a.teamId
        AND ot.optionGroup = o.optionGroup
WHERE   o.OptionId = @id
GROUP BY
        a.teamId, o.optionGroup

Answer 3

select teamID,
sum(case when optionGroup = 4 then 1 else 0 end) as optionGroup4,
sum(case when optionGroup = 5 then 1 else 0 end) as optionGroup5,
from optionteam
group by teamID

要添加更多选项组而不更改代码，请尝试按该字段进行分组：

select teamID,optionGroup,count(optionID) as optionCount
from optionteam
group by teamID,optionGroup

如何在SQL select语句中动态创建列

3 个答案: