从mysql中减去给定日期的天数

Question

个人假是10天。我需要从总休假中减去剩余的假期，即10天

result i have

   SELECT id, firstname,lastname,join_date, completion_date,title, leave_from,leave_to, Given_leave_Days,Taken_Leave_Days,Remaining_Leave_Days  FROM (SELECT T1.id,T1.firstname,T1.lastname,T1.join_date,T1.completion_date,T0.title,T2.leave_from,T2.leave_to,T2.user_id,T0.Leave_Days as Given_leave_Days,SUM(DATEDIFF(T2.leave_to,T2.leave_from)+1) AS Taken_Leave_Days ,T0.Leave_Days - SUM(DATEDIFF(T2.leave_to,T2.leave_from)+1) as 'Remaining_Leave_Days' FROM users_leave_request T2 INNER JOIN users T1 ON T2.user_id = T1.id INNER JOIN leave_type T0 ON T2.leave_type_id = T0.id GROUP BY T1.id, T1.firstname, T1.lastname, T1.join_date,T1.completion_date,T0.title,T2.leave_from,T2.leave_to,Given_leave_Days order by firstname) A

我必须在前端显示结果。

result in frontend

Answer 1

一般答案是

select date_sub(now(), interval 10 day)

您可以将now()替换为表格中的任何日期，您可以更改day，month等year。

我的例子的结果是今天前10天的日期。例如，如果您只想过滤超过10天的日期，您可以这样做：

select * from mytable t where t.mydate < date_sub(now(), interval 10 day)