Question

使用带有代码点火器的Ajax，使用po_id和item_id更新quantity_received详细信息时出现问题。我的问题是，当我更新po_id = 5和item_id = 1时，quantity_received详细信息会更新。再次当我更新第二项po_id = 5和item_id = 2时，quantity_received细节没有得到更新，同样的值已经更新，我在item_id = 1 ..

    My code:

   <table class="table table-striped table-hover table-bordered mytable order-table" id="table">
            <thead>
                <tr>
                    <th>PO Id</th>
                    <th style="width:0px;">Item Id</th>
                    <th>Item Name</th>
                    <th>Quantity</th>
                    <th>Add RO</th>
                    <th colspan="2">Action</th>
                 </tr>
            </thead>
                    <tbody>
                        <?php
                             foreach ($pitems as $result)
                             {
                        ?>
                    <tr class="">
                         <td><input type="text" disabled name="po_id" id="po_id" value="<?php echo $result->po_id; ?>"/></td>
                         <td><input type="text" disabled name="item_id" id="item_id" value="<?php echo $result->item_id; ?>"/></td>
                        <td><input type="text" disabled name="item_name" id="item_name" value="<?php echo $result->item_name; ?>"/></td>
                        <td><input type="text" disabled name="quantity_purchased" id="quantity_purchased" value="<?php echo $result->quantity_purchased; ?>"/></td>
                         <td><input type="text"   name="quantity_received" id="quantity_received" required placeholder="Enter Received Items" value="<?php echo $result->quantity_received; ?>"/></td>

                         <!--td><span class="action"><a href="#" id="<?php echo  $result->po_id.'/'.$result->item_id; ?>" class="delete" title="Delete">X</a></span></td-->
                         <td><span class="action"><a href="#" id="<?php echo  $result->po_id.'/'.$result->item_id.'/'.$result->quantity_purchased.'/'.$_POST['quantity_received']; ?>" class="edit" title="Edit">Add</a></span></td>

                           <?php
                               }
                               ?>

                             </tbody>
                          </table>

的Ajax：

    $(".edit").click(function(){

    var element = $(this);
    var del_id = element.attr("id");
    var arr = del_id.split('/');
    var quantity_purchased = $('#quantity_purchased').val();
    var quantity_received = $('#quantity_received').val();
    var del_id1 = element.attr("id");

      if(confirm("Are you sure you want to Edit this?"))
      {

        $.ajax({
                type: "POST",
                 url: "<?php echo base_url().'/inventory_c/ro_edit_poid11' ?>",
                cache: false,
                data: 'po_id='+arr[0]+'&item_id='+arr[1]+'&quantity_received='+quantity_received,

                dataType: "html",
                success: function(htmldata) {
                alert("success");

                   }
                 });

                   }
       return false;
            });

我的控制器很有趣：

      public function ro_edit_poid11() 
      {
     $po_id = $_POST['po_id'];
     $item_number = $_POST['item_id'];
     $quantity_received = $_POST['quantity_received'];
     $last_id= $po_id;
        $edit_temp_purchase = array( 
                  'quantity_received' => $quantity_received,
                );

              $this->db->where(array('po_id' => $po_id, 'item_id' => $item_number));
              $this->db->update('bgs_po_list_items', $edit_temp_purchase);
        [enter image description here][1]
 }

请做我的需要@谢谢

Answer 1

为以下2个输入框提供不同的ID

$(document).on('click','a.edit',function(){
var element = $(this);
var del_id = element.prop("id");
var arr = del_id.split('/');

var po_id = parseInt(arr[0]);
var item_id = parseInt(arr[1]);
var quantity_purchased = $('#quantity_purchased_'+po_id+'_'+item_id).val();
var quantity_received = $('#quantity_received_'+po_id+'_'+item_id).val();

var del_id1 = element.attr("id");

  if(confirm("Are you sure you want to Edit this?"))
  {

    $.ajax({
            type: "POST",
             url: "<?php echo base_url().'/test/ro_edit_poid11' ?>",
            cache: false,
            data: 'po_id='+arr[0]+'&item_id='+arr[1]+'&quantity_received='+quantity_received,

            dataType: "html",
            success: function(htmldata) {
            alert("success");
        }
    });
}     
});

然后获取数量购买的价值并在您的jquery中获得如下：

  public function ro_edit_poid11() 
  {
 $po_id = $_POST['po_id'];
 $item_number = $_POST['item_id'];
 $quantity_received = $_POST['quantity_received'];
 $last_id= $po_id;
    $edit_temp_purchase = array( 
              'quantity_received' => $quantity_received,
            );

          $this->db->update('bgs_po_list_items',$edit_temp_purchase,['po_id' => $po_id, 'item_id' => $item_number]);
    echo 'success';
}

在php函数中返回ajax的回显

custom doclet

希望这会奏效。

使用Ajax更新codeigniter

1 个答案: