Question

我使用语音识别并检查列表中的颜色，如果我说的不在列表中，则会显示“未找到颜色”＃39;如果发现它显示“找到颜色”＆＃39;我只希望它显示每条消息一次。我遇到的问题是如何找到未找到的颜色＆＃39; msg正确显示。

# speech recognition

import speech_recognition as speech

#a lot of variables used for loops and conditions
voice = speech.Recognizer()
condition = False
condition2 = False
condition3 = False
boolean = False
counter = 0
counter2 = 0

while condition == False:
#with microphone input as the input
with speech.Microphone() as source:
    print("Say something!")

    #variable = the input from the microphone
    audio = voice.listen(source)
    voiceRecog = voice.recognize_google(audio)
    try:
        #print the word that was heard
        print("\nYou said: " + voiceRecog)
    except speech.UnknownValueError:


        #if couldnt recognise then print this msg
        print("Sorry, we couldn't make that out. Try again!")

    except speech.RequestError as e:
        print("Could not request results from Google Speech Recognition service; {0}".format(e))


    #list of colours  for comparing   
    colours = ["blue", "red", "Green", "Orange", "yellow", "pink", "purple", "black"]

    #loop to check the word spoken against each word in the list
    for i in range(len(colours)):



        #so that if colour found it doesnt claim colour not found
        if boolean == False:
            condition2 = False

        #increase counters by 1 and change booleans to True
        #if spoken word matches any words in the list then output
        if colours[i] == voiceRecog:

            boolean = True
            condition2 = True
            condition3 = True
            counter += 1
            counter2 += 1

            print("\nColour Found!\n")

        #if user says "quit" then all booleans = True (exit all loops)
        elif voiceRecog == "quit":

            boolean = True
            condition = True
            condition2 = True
            condition3 = True

        #if none of other conditions check value of i and of con2
        else:
            #if end of list is reached and con2 = False then con3 = False
            if (i + 1) == len(colours) and condition2 == False:
                condition3 = False
                print(end = "")
    #if con3 = False then counter increase and print 'colour not found'
    if condition3 == False:            
        print("\nColour not found!\n\n")
        counter += 1

#once loop exited by saying quit, print attempts and successful attempts
print("\nYou checked for", counter, "colours and had", counter2, "successful attempts")

以上是我的代码，下面是一个场景。

说点什么！
             你说：蓝色
             找到了颜色！

说点什么！
             你说：绿色
             找到了颜色！

说点什么！

你说：戴夫戴夫

说点什么！

你说：退出

您检查了2种颜色并成功尝试了2次

应该尝试3次，但尝试成功2次。

但如果我这样做，反过来说：

说点什么！

你说：戴夫戴夫

找不到颜色！

说点什么！

你说：Steve Steve

找不到颜色！

说点什么！
             你说：红色
             找到了颜色！

说点什么！
             你说：黑色
             找到了颜色！

说点什么！

你说：退出

您检查了4种颜色并成功尝试了2次

我知道这样做的原因，但我无法找到解决方法。

Answer 1

# speech recognition

import speech_recognition as speech

#a lot of variables used for loops and conditions
voice = speech.Recognizer()
# Maintain status of each attempt. You can just use two variables successful_attempts and total_attempts also but status list might help you in maintaining more things like a list of tuples (color, result) etc
status = []
# successful_attempts, total_attempts = 0, 0

while True:
    #with microphone input as the input
    with speech.Microphone() as source:
        print("Say something!")

        #variable = the input from the microphone
        audio = voice.listen(source)
        voiceRecog = voice.recognize_google(audio)
        try:
            #print the word that was heard
            print("\nYou said: " + voiceRecog)
        except speech.UnknownValueError:


            #if couldnt recognise then print this msg
            print("Sorry, we couldn't make that out. Try again!")

        except speech.RequestError as e:
            print("Could not request results from Google Speech Recognition service; {0}".format(e))


        #list of colours  for comparing   
        colours = ["blue", "red", "Green", "Orange", "yellow", "pink", "purple", "black"]

        if "quit" in voiceRecog:
            break
        elif voiceRecog in colours:
            status.append(1)
            # successful_attempts += 1
            print("\nColour Found!\n")
        else:
            status.append(0)
            print("\nColour not found!\n\n")

        # total_attempts += 1

#once loop exited by saying quit, print attempts and successful attempts
print("\nYou checked for", len(status), "colours and had", sum(status), "successful attempts")
#print("\nYou checked for", total_attempts, "colours and had", successful_attempts, "successful attempts")

Answer 2

嗨，我是一个c＃程序员，我不知道python语法..我的想法在c＃中试试这个有效吗？

<item name="windowActionBarOverlay">true</item>
<item name="android:windowActionBarOverlay">true</item>

在不期望语音识别结果时打印消息

2 个答案: