我正在努力创建一个由joomla数据库组成的表。目前我正在使用以下代码:
$query= "SELECT DATUM, A , B ,C, D, E, F, G FROM ".$db->quoteName('#__XYZTABLE'). " WHERE DATUM_ENG>= CURDATE()";
$db->setQuery($query);
$results = $db -> loadObjectList();
echo "<table><tr><th>Name</th><th>Department</th></tr>";
foreach($results as $row){
echo "<tr>"; echo "<td>".$row->last_name."</td>";
echo "<td>".$row->dept."</td>";
echo "</tr>"; }
echo "</table>";
基本上,这段代码运行正常。结果是:
DATUM , A , B ,C, D, E, F, G
xxxx1 ,aa1,bb1,cc1,dd1,ee1,ff1,gg1
xxxx2 ,aa2,bb2,cc2,dd2,ee2,ff2,gg2
....
但是,我想创建一个html表来转置数据并将其显示为以下形式:
xxxx1 , xxxx2, xxxx3 ....
A aa1 , aa2 , aa3
B bb1 , bb2 ,bb3
C cc1 , cc2 ,cc3
D .....
在这个论坛和谷歌搜索后,我找不到类似的东西。有人可以用特定代码帮我吗?
答案 0 :(得分:1)
使用一些php数组函数,你可以这样:
$object = new stdClass();
// create some test values
$object->DATUM = '2016120';
$object->A = 'aa';
$object->B = 'bb';
$object->C = 'cc';
$object->D = 'dd';
$object->E = 'ee';
$object->F = 'ff';
$object->G = 'gg';
for ($i = 1; $i < 10; $i++){
$vars = get_object_vars($object);
$obj = new stdClass;
foreach ($vars as $key=>$var){
$obj->$key = $var.$i;
}
$results[] = $obj;
}
// end of creating test values
echo "<table><tr><th>DATUM</th><th>A</th><th>B</th><th>C</th><th>D</th></tr>";
foreach ( $results as $row ) {
echo "<tr>";
echo "<td>" . $row->DATUM . "</td>";
echo "<td>" . $row->A . "</td>";
echo "<td>" . $row->B . "</td>";
echo "<td>" . $row->C . "</td>";
echo "<td>" . $row->D . "</td>";
echo "<td>" . $row->E . "</td>";
echo "<td>" . $row->F . "</td>";
echo "<td>" . $row->G . "</td>";
echo "</tr>";
}
echo "</table>";
echo '<h3>New Variant</h3>';
echo '<table>';
$elements = count($results);
foreach (get_object_vars($results[0]) as $key=>$var){
echo '<tr>';
$tag = ($key === 'DATUM') ? 'th>' : 'td>';
echo '<'.$tag . $key .'</'.$tag;
for ($i = 0; $i < $elements; $i++){
echo '<'.$tag . $results[$i]->$key.'</'.$tag;
}
echo '</tr>';
}
echo '</table>';`