在一个SSH会话中运行多个命令

时间:2016-11-18 18:52:34

标签: go

我需要在一个ssh会话中运行多个命令:

// Define the client configuration
config := &ssh.ClientConfig{
    User: USERNAME,
    Auth: []ssh.AuthMethod{
        ssh.PublicKeys(pem),
    },
}

// Connect to the machine
 client, err := ssh.Dial("tcp", HOSTNAME + ":" + PORT, config)
 if err != nil {
    panic("Failed to dial: " + err.Error())
}

// Create a session
session, err := client.NewSession()
if err != nil {
    panic("Failed to create session: " + err.Error())
}
defer session.Close()

// Start running commands!
var output bytes.Buffer
session.Stdout = &output

// 1)  Login to swarm registry
fmt.Println("Logging into swarm registry...")
if err := session.Run("docker login ..."); err != nil {
    panic("Failed to login to swarm registry: " + err.Error())
}
fmt.Println(output.String())

// 2)  List all of the docker processes
fmt.Println("List swarm processes...")
if err := session.Run("docker ps"); err != nil {    // <-------- FAILS HERE
    panic("Failed to list swarm processes: " + err.Error())
}
fmt.Println(output.String())

我仔细阅读了源文件(session.go)和Session.Run命令,并说:

  

会话只接受一次对Run,Start,Shell,Output或CombinedOutput的调用。

对于我的用例,我需要发出第一个命令来记录会话,然后在我登录后发出后续命令。

是否有另一种方法可以使用相同的ssh会话运行多个命令?

1 个答案:

答案 0 :(得分:2)

感谢@JimB,我现在正在这样做:

// Create a single command that is semicolon seperated
commands := []string{
    "docker login",
    "docker ps",
}
command := strings.Join(commands, "; ")

然后像以前一样运行它:

if err := session.Run(command); err != nil {
    panic("Failed to run command: " + command + "\nBecause: " + err.Error())
}
fmt.Println(output.String())