Question

我在表单中有三个String的“集合”：

1. Set<String> genderSet 
    sort:bestsellerRating:gender:Female,:bestsellerRating:gender:Male
2. Set<String> ageSet
    sort:bestsellerRating:age:0 - 6 Months, :bestsellerRating:age:6 - 12 Months :bestsellerRating:age:12 - 14 Months
3. Set<String> priceSet
    sort:bestsellerRating:price:£0-£19.99, :bestsellerRating:price:£200-£299.9

想要创建一个返回类似于以下内容的string的函数：

Output: sort:bestsellerRating:gender:Female:gender:Male:age:0 - 6 Months:age:6 - 12 Months:age:12 - 14 Months:price:£0-£19.99:price:£200-£299.9

不想玩字符串，因为它不是一个好方法。原因：genderSet，ageSet和priceSet可以是以下任何内容：分隔

希望使用HashMap实现此目标我希望实现这样的目标：

public String getQuery(final Form Form)
    {
        private static final String FACET_SEPARATOR = ":";

        final Map<String, Set<String>> queryMap = new HashMap<String, Set<String>>();

        final Set<String> giftFinderQuerySet = new HashSet<String>();

        final Set<String> valueSet = new HashSet<String>();

        final Set<String> genderSet = form.getGenderSet();  

        final Set<String> ageSet = form.getAgeSet();

        final Set<String> priceSet = form.getPriceSet();


for (final String gender : genderSet) 
    {
        final String[] genderList = gender.split(FACET_SEPARATOR);// This will bring first- [sort, bestsellerRating, gender, Female]  at one time, then [bestsellerRating, gender, Male] later in the next loop

        for (final String genderSplittedValue : genderList)
        {
        //valueSet.add(genderList[+1]); 
                queryMap.put(genderSplittedValue, valueSet); // Issue here: Need the map to be formed like this: queryMap(sort, bestSelling), queryMap(gender, [Male,Female])

        }


    }

for (final String age : ageSet) 
    {
        final String[] ageList = age.split(FACET_SEPARATOR);//Similar list like genderList 

        for (final String ageSplittedValue : ageList)
        {
                queryMap.put(genderSplittedValue, ageList[+1]); // Similar issue like above

        }


    }

for (final String price : priceSet) 
    {
        final String[] priceList = price.split(FACET_SEPARATOR);//Similar list like genderList 

        for (final String priceSplittedValue : priceList)
        {
                queryMap.put(priceSplittedValue, priceList[+1]); // Similar issue like above

        }


    }

现在，一旦我们准备好了地图，那么在进一步的代码中就没有问题了

for (Map.Entry<String,Key> entry : queryMap.keySet()) 
    {
        String key = entry.getKey();
        String value = entry.getValue();
        giftFinderQuerySet.add(key+FACET_SEPARATOR+value);
    }

for (final String query : giftFinderQuerySet)
    {
        searchQuery = searchQuery.concat(query);
    }
    return searchQuery;
    }//End of method

需要帮助：需要像这样形成地图：queryMap（sort，bestSelling），queryMap（性别，[男，女]），queryMap（年龄，[0 - 6个月， 6 - 12个月，12 - 14个月]），queryMap（价格，[£0-£19.99，£200-£299.9]）

Answer 1

有了解决方案，重新编写了以下方法以实现输出：

通过来自Alternate Array of Strings的forLoop设置HashMap值

1 个答案: